Elementary Statistics - V55.0105-1
Homework 6 Solutions
Problems:
1. There are
6
3
=
possible samples. We list them here:
654
= 20
321
abc abd abe abf
acd ace acf ade
adf
bcf
aef bcd bce
bde bdf bef
cde cdf
cef
def
If we assume random sampling, we assume
Elementary Statistics - V55.0105-1
Homework 5 Solutions
Problems:
1. 9.2. For case (a), notice that the function is negative from 0 to 4, which is not permissible. For case
(b), the area under the curve is not one; one can see by drawing the picture and b
Elementary Statistics - V55.0105-1
Homework 4 Solutions
Problems:
1. 8.2.
(a) No, it takes negative values.
(b) Yes.
(c) No, they do not add to one.
2. 8.4.
(a) No, it takes negative values.
(b) Yes, it is always nonnegative and the values add to one.
(c)
Elementary Statistics - V55.0105-1
Homework 3 Solutions
Problems:
1. 5.34.
(a) In this case, it is easy to see that all we need to do is choose the location of the couples. The
question is then equivalent to the question of how we can arrange four couples
Elementary Statistics - V55.0105-1
Homework 2 Solutions
Problems:
1. 3.26.
(a) 17
(b) 23
2. 3.28. Sorting the data gives
35, 36, 38, 38, 44, 46, 48, 50, 53, 54, 54, 56, 58, 59, 61.
There are 15 pieces of data, so that the median position is (15 + 1)/2 = 8