Problem 4.193 The force F = 60i + 60j (lb).
(a) Determine the moment of F about point A.
(b) What is the perpendicular distance from point A to
the line of action of F?
Solution: The position vector of A and the point of action are
r4=3i+2j+12ktftL andr;=
Statics ECE210 Take home exam 5
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Midterm exam No. 5: Open book, open notes. It is not permitted to discuss the content of
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exam on Fri
Statics ECE210 Exam 3
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Practice exam: It is permitted to discuss the content of this exam with others. All your work
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1. Determine the coordinates of the c
I
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eac
Statics ECE210 Exam 2
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Solutions to midterm exam No. 2: (10/4 points each problem).
1. Determine the force and moment reactions at the support A of the built-in beam which is
subjected to the sine-wave load distribution.
2. The
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1. (a) Is the L-shaped bar a
Statics ECE210 Exam 1
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each problem).
1.
Statics ECE210 Exam 1
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Midterm exam No. 1: It is not permitted to discuss the content of this exam with others. All
your work must be shown; be neat and mark your answers. (10/3 points each problem).
1. The collar A slides on a
Statics ECE210 Exam 1
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1. The collar A slides on a smooth ve
Problem 5.142 {a} Draw the free-body diagram of the
50-1b plate, and explain wh)r it is statically indeterminate.
(b) Determine as many of the reactions at A and B as
possible.
Solution:
(:1] Thu: pin supports at A and S are two-force supports, ihus then:
Problem 5.145 (21} Draw the free-body diagram of
the beam.
(b) Determine the reactions at the suppons.
Solution:
[3) The fuse body diagram is shown.
[h] The sum of the moments about 3
EMS =+th0* (141+ 1300: U.
[mm which :1}! =20 + 300: 500 N-m The sum oi
Problem 5.2 The beam has a built~in support and is i214
hmdcd by a 2-kN force and a 6 kN-m couple. IlA QT MM]
(:1) Draw the free-bmly diagram of the beam. 3
(1:) Determine lhe reactions at the supports. I
tw- 2 m -1 J
Solution:
In]
{h} Zn, :0: szu
/
Problem 4.208 If you represent the forces exened by
the oor on the table legs by a force F acting at the
origin 0 and a couple M. what are I" and M?
Solution: The sum of the forces is the equivalent force at the
origin. F = (50+48-l50 +42)j = l90j (N)
Problem 4.201 The two systems are equivalent. Deter-
mine the forces A; and A and the couple MA.
Solution: The sum of the fumes for System I is
2 F; =(21y + 201i.
2 Fr = {Ar + 3U)j.
The sum of forces fer System 2 is
2 E: = (20 and
Err = {so 10)}.
Equaling
Problem 4.188 Determine the moment of the 400-N
force (a) about A. (b) about B.
Solution: Use the two dimensional description of the moment. The
vertical and horizontal components of the 280 N force are
Fr = véosin 30" = "200 N.
Fx = +400co530° = 346.4I N
Statics ECE210 Final Exam
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Final exam: It is not permitted to discuss the content of this exam with others. All your work
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1. Connections at A, B , C and D