5.16
El.
b.
Solution of HW 5
i. First-order
ii. Third-order
iii. First-order
iv. Secondorder
i. 150') = u + 5.x
ii. my) = 50 + [31.1- + 163.3 + 163.9
iii. 130') = 130 + [9.x
iv. My) = .60 + lx+ 523:2
i. )3. > 0 since the slope of the line is positive.
i
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4.36
4.37(b)
l).
4.38
XX/t 2/ I
Solution of HW 4
a. [50 = 325790. This means that the mean percentage of motor vehicles withoat eataEytic
converters would be 325,790% when a given year is 0. Since the years range only from 1984 to
1999, 0 is not in the ob
/' glut/'0 .8? VP/1 XV? %
LXL
1.32 a. The probability that a normal random variable will lie between 1 standard deviation below the
W545 mean and 1 standard deviation above the mean is indicated by the shaded area .in the figure:
The desired probability i
Sbldttow 0E: H (Al/2 XX/7f
3.10 a. The Radiata Pine has a slope of -2.50 which implies that fatigue stress on the wind turbine blade is
diminished by 2.5 alter each cycle. The Hoop Pine has a slope 0| -2.36 which impites that latigue
W . . . . . 6
stress
3. i W W
a. The rst order model i.(E(y) =
a.
A
b. The least squares prediction equationi yr:e20.352 + .l3.350.r] + 243.7145.
c. [1:20.352 This has no meaning because 4': = 0 and .15 = D are not in the observed range.
I = 13.35 The mean annual ea
Si, Mm
STAT 2223001'Test 1
Spring 2017
Please ll in the following blanks
Av
Name: ' Student ID:
1 Multiple Choice Problem (60 pts)
There are only one right choice in each. problem, each question worth 3 pts.
1 1. Chemical and manufacturing plants sometime
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