PHY 252 Lab 5: Ohms Law
By: Ishaq Ibrahim, Joseph Charboneau
Purpose:
Through measuring a current that passes through different amounts of resistance and resistors
the differences between the effects of resistors can be identified. Examples that we
experi
PHY 252 Test 3 Practice Problems
1. The figure below shows an electron moving near a current loop which lies in the x
y plane with its center at the origin. If the electron's velocity is parallel to the y axis,
what is the direction of the magnetic force
Ohms Law
Introduction
Ohms law applies to many, but not all, materials. Many materials show a constant resistance over a
wide range of applied voltages and are said to be ohmic. These will show linear voltage-current
relationships. Those that do not are s
EQUIPOTENTIAL SURFACES COMPUTER LAB ACTIVITY
Remember that an equipotential surface is the set of all points around a group of charges that
are at the same potential. These surfaces allow us to calculate the amount of work needed to
move a charge from one
Remove the Screw
A metal bracket is held in place on a wood surface by a bolt and a nail. A screw is also inserted into the
wood, but it is underneath the bracket. Your mission: remove the screw. You may use three tools: a
hammer, a screwdriver and a wren
PHY 252 TEST 3 Formulary
F q (E + v B )
FB qv B q v B sin
m v2
F=ma=
r
7
0 4 10 T m/A
I
B 0
4
d s r
r2
FB 0 I1 I 2
2a
r r
dB
E
ds emf dt
B B dA B A cos
IA B B I A B sin
FB IL B I L B sin
v r
Blong wire
Bloop
Bloop
2 r
T
v
I
0
2a
0 Ia 2
Four identical charges are arranged at the corners of a horizontal square. The charges are all Q and the
sides of the square are d. A fifth identical charge floats at a height s above the center of the center of the
square. The upward force is Q*Enet and
PHYSICS TOOLS: Conservation of Energy and the Work Energy Theorem
These two tools are really the same thing, but in the conservation of energy equation the work
done by conservative forces is rewritten as the change in Potential energy
Equations:
K + Ug +
PHYSICS TOOLS: Kinematic Equations
Equations:
vf = vi +at
x = (vi + vf)t
x = vit + at2
vf2 = vi2 + 2 ax
Principle Unknowns:
Initial and final velocities, displacement, acceleration and time
Secondary Unknowns:
Force (via acceleration through NSL)
Indicati
PHY 252 TEST 3 Formulary
FB qv B q v B sin
FB IL B I L B sin
m v2
F=ma=
r
I
B 0
4
v r
d s r
r2
0
I
enc
B B dA B A cos
B dA 0
I
R
I
R
1 e
t /
e t / I i e t /
E
B
P F v
( for velocity selector )
0 I
NI
sin 1 sin 2
Btoroid 0
4a
2r
0 I
N
B
An insulating slab of charge lies along the x-y plane between z = D. The volume charge density is a
function of z.
(z) = 0 (1- z2/D2).
Use Gauss Law to find the electric field inside and outside the slab.
Z
Y
X
Old Test 2
Sample Problems
1. 13.3 V
1. 4.43 x 10-6 m
2. a
2. 1.84 x 106 m/s
3. 148 nJ
3. c
4. d
4a. 36 F
5. 7.75mV
4b. 810 C
6. b
5. 90 F
7. 3.2 W
6. 1.73
8. 0.04 A
7. c
9. 400 C
8. 1.63 J/s
Bonus
9a. L to R: 1.8 A, 2.2 A, 0.4 A
I = 2.4 A
9b. 8 V
r = 2.9
Phy 252 Test 1 Equation Sheet
Particle
Electron (e)
Proton (p)
Neutron (n)
Coulombs law and Electric Field
qq
F12 k e 1 2 2 r12
r
F
E
q
q
E k e 2 r
r
Mass (kg)
9.11 x 10-31Q dq
1.673 x
10-27l dl
1.675 x 10-27
Electric Potential and Potential Energy
DU
D
PHY 251 Final Formulary
r
mm
F12 G 1 2 2 r12
r
The gravitational field:
where G = 6.673 x 10-11 Nm2 / kg2 and the negative sign indicates an attractive force.
r
g
r
Fg
Gravitational Potential energy for any two particles.
m
U
Gm1m2
r
SHM
f
1
T
T
2
2 f
U
Wake Technical Community College
Mathematics and Physics Dept.
Mathematics and Sciences Division
Spring 2017
Course Syllabus
PHY 252 sections 4230 and 4241 General Physics II
Lecture = 3 hours Lab = 3 hours Total Credits = 4
Description
This course uses c
SHOW ALL WORK ON YOUR OWN PAPER.
CIRCLE YOUR ANSWERS. INCLUDE UNITS.
Time for test: 100 minutes
8 pts
3 pts
PHY 252 A
TEST 2 Sp 10
1. An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a
distance of 2.20 m
Checklist for Test 3
1. Use the Impulse Momentum Theorem to calculate the average force or the change in momentum. The
Impulse can be calculated as Favg t or the area under the force vs time graph.
2. One dimensional collisions for the three cases mention
PHY 251 Test 2 Formulary
Newtons 2nd
Law
Frictional
Forces
Fnet F ma
f
s s max
N
F
x
Vector scalar
or dot
product
Work
,
definition of s
f s max s N
Uniform Circular Motion
Circular
Motion
ma x
Fradially inward
F
,
y
ma y
,
F
z
0 f s f s max
,
ma z
f s
PHY 252 Test 3C
Spring 2009
Name: _
Show your work on the paper provided. Write equations, show units in each step. Provide
drawings where appropriate. Do not expect partial credit for a wrong answer and no work shown.
1.
[12 pts.] A particle with mass 6.
PHY 251, Fall 2009
Test 1
Name_
Show your work for partial credit. Circle your final answer and include units.
1. [10pts] The density of lead is
3
11 .3 10 kg / m
3
. What is the radius of a lead sphere of
mass 850 grams?
2. [10 pts] Sally is driving alon
PHY 252 Test 3 Practice Problems
1. The figure below shows an electron moving near a current loop which lies in the x
y plane with its center at the origin. If the electron's velocity is parallel to the y axis,
what is the direction of the magnetic force
PHY 252 Test 1C
Spring 2009
Name: _
Show your work on the paper provided. Write equations, show units in each step. Provide drawings
where appropriate. Do not expect partial credit for a wrong answer and no work shown.
1. A 6-F capacitor is charged to 20
PHYSICS TOOLS: Newtons Second Law (NSL)
Equations:
F = ma or
Fx = max, Fy = may and Fz = maz
Choose coordinates so that a is along a positive coordinate axis. This causes two of the
components of a (ax, ay or az) to be zero and the third component to be e
In an RC circuit, how many time constants must elapse if an initially uncharged capacitor is to reach 80% of its final
energy?
Consider the circuit at the right.
(a) Use the junction rule to determine a relation between i1, i2, and i3.
(b) What does the l
Prerequisite (17:57)
Chemical Bonding
Properties of organic compounds depend upon STRUCTURE.
Proton = + charge
Electron = - charge
Neutron = neutral
Atomic Number (Z) = proton #. Ex: Carbon atomic number (Z) = 6 = Carbon has 6
protons.
Atomic Mass Un
Prerequisite (17:57)
Chemical Bonding
Properties of organic compounds depend upon STRUCTURE.
Proton = + charge
Electron = - charge
Neutron = neutral
Atomic Number (Z) = proton #. Ex: Carbon atomic number (Z) = 6 = Carbon has 6
protons.
Atomic Mass Un
Slide 1
Black = Theobromine (stimulant in chocolate & tea)
Red = Caffine (stimulant in chocolate, tea & coffee)
Blue = Ethanol (drug in alcoholic beverages)
Classified as organic molecules because they ALL contain the element CARBON.
Slide 2
Molecule 1 =
Prereq Checkup (Homework)
1. # of Protons, Electrons, and Neutrons.
Proton number is the atomic number.
When the atom is neutral, the electron number
equals the proton number.
For the anion electron number, you add the charge
to the atomic number to de
Prereq
1.
a)
K. 19 protons. # Proton = Atomic #
b)
Li. 3 electrons. # Electrons = # Protons = Atomic #
c)
Br1-. 36 electrons. Br is an anion (negative ion) meaning it has more electrons then protons. In
this case, its only increased by one.
d)
Mg2+. 10 el