4300:623 Physical/Chemical Treatment Process
Homework #4
SHOW YOUR WORK/DERIVATIONS
1) Consider the following:
Scheme 1:
Scheme 2:
a) For the following conditions, show which reactor scheme, 1 or 2, i
Homework Assignment 1
1
Due September 11th: Environmental Chemistry
Calculate ionization coefficients for aqueous chlorine
as a function of pH and plot them
0 and 1 vs. pH
pC vs. pH: pC = -log(Concen
Physical/Chemical Treatment Process
Homework #3
SHOW YOUR WORK/DERIVATIONS
1) Consider the following reaction:
2A + 3B P
-rA = k[A][B]
a) Develop the integrated batch expressions for the following cas
Chapter 4: Force System Resultants
Chapter Objectives
To discuss the concept of the moment of a force and show how to calculate it in
two and three dimensions.
To provide a method for finding the mom
Chapter 10: Moments of Inertia
Chapter Objectives
To develop a method for determining the moment of inertia and product of inertia
for an area with respect to given x- and y-axes.
To develop a method
Chapter 2: Force Vectors
Chapter Objectives
To show how to add forces and resolve them into components using the
Parallelogram Law.
To express force and position in Cartesian vector form and explain
Chapter 5: Equilibrium of a Rigid Body
Chapter Objectives
To develop the equations of equilibrium for a rigid body.
To introduce the concept of a free-body diagram for a rigid body.
To show how to so
Chapter 9: Center of Gravity and Centroid
Chapter Objectives
To discuss the concept of the center of gravity, center of mass, and the centroid.
To show how to determine the location of the centroid f
Chapter 3: Equilibrium of a Particle
Chapter Objectives
To introduce the concept of the free-body diagram for a particle.
To show how to solve particle equilibrium problems using the equations of
equ
Chapter 7: Internal Forces
Chapter Objectives
To show how to use the method of sections for determining the internal
loadings in a member.
To generalize this procedure by formulating equations that c
Chapter 6: Structural Analysis
Chapter Objectives
To show how to determine the forces in the members of a truss using the method
of joints and the method of sections.
To analyze the forces acting on
Chapter 1: Introduction
Chapter Objectives
To provide an introduction to the basic quantities and idealizations of mechanics.
To give a statement of Newtons Laws of Motion and Gravitation.
To revie
Frames and Machines
Trusses
1). Consists of pins
2). Straight 2-force members
3). Forces directed along the member
Frames
- Structures that have at least one multi-force member
3 or more forces
- For
4.4 Principle of Moments Also known as Varigon's Theorem Let's say we have several concurrent forces. We can determine its resultant R = F1 + F2 . The moment of R about 0, where r is the position vect
Chapter 8 - Friction 8.1 Characteristics of dry friction Friction - a resistive force that prevents or retards the slipping of one body with respect to another. 2 types of friction 1). Dry (coulomb)-
2.5 Cartesian vectors Right hand coordinate system y j i k z 3-dimensional vectors
y
x
Fy
y x
F
x
Fz
z
Fx
z
F = Fx + Fy + Fz F = Fx i + Fy + Fz k j F = uF F uF =
Note:
F = Fx + Fy + Fz Fx = F cos x
2
Chapter 5- Equilibrium of a rigid body 5.1 Conditions for rigid-body equilibrium Previously we found that a system of forces can be reduced to a force-couple system. When the force and couple are equa
Chapter 9 Center of Gravity and Centroid Center of gravity- the point at which the weight of the body can be concentrated. CG of 2-D body z y ( x 1 y 1 ) weight x y ( x 2 y 2 ) weight = dW = dW
1 2
W
Method of Sections Method of joints works well when you want to know the forces in all the members. If we want to know a force in a particular member, the method of sections is more efficient. Look at
Addition of a System of Coplanar Forces Vector Notation In many problems it will be necessary to resolve a force into 2 components that are perpendicular to each other. y j i x
O 2 vectors, i and that
5.4 Two and Three Force Members The solution to some problems can be made easier if you recognize members that are subjected to only 2 forces. Two force members - only 2 forces applied at 2 points on