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College Physics 103
Homework Set #9
Spring 2010
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Due in class by 6/3 (Professor Johnsons class) and by 6/4 (Professor Kims class)
1.A monoenergetic beam of electrons (me = 9.11 x 10-31 kg) whose kinetic energy is 120 eV is
incident on a single slit of
Homework Set 5 - Solutions
Problem 1
Vsound
331.
Sqrt
22
273
273.
344.079
Wave length of 523.25 :
Vsound
523.25
0.65758
One octave up (double frequenc- wavelength in half) :
up
2
0.32879
One octave down (frequecy in half, double wavelength) :
down
2
1.315
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College Physics 103
Homework Set #6
Spring 2010
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Due in class by 5/13 (Professor Johnsons class) and by 5/14 (Professor Kims class)
1. A beam of light passes through a 45 90 45 prism as shown. (a) What can be said
about the index of refraction of the p
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College Physics 103
Homework Set #7
Spring 2010
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Due in class by 5/20 (Professor Johnsons class) and by 5/21 (Professor Kims class)
1. In a double-slit experiment you saw in class the distance between slits is 5.0 mm and the slits
are 1.0 m from the sc
Solution Set
Problem Set 8
Problem 1
Resolving power for a circular aperture is :
R_, D_ 1.22 D
1.22
D
Blue light (in radians - preferred answer):
R420. 10 ^ 9, 2 12 .0254
8.40551 107
In degrees (OK) :
R420. 10 ^ 9, 2 12 .0254 180 Pi
0.00004816
In arc s
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College Physics 103
Homework Set #4 - Key
Spring 2010
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Due in class by 4/29 (Professor Johnsons class) and by 4/30 (Professor Kims class)
1.When a system is taken from state i to state f along the path i a f as shown
below, it is found that Q = 50 cal
College Physics 103
Spring 2010
Problem Set 3
1. A blacksmith heats a horse shoe (.25 kg iron) to an average temperature of 700 oC.After working it on an anvil, he plunges it
into 5 gallon bucket of water (at 20 oC).Assuming that minimal energy is lost by
EquationsandNumbers
m
F
1
= P = FB = gVobject Av = const .
P + v 2 + gy = const .
V
A
2
2
5
2
3
g = 9.8 m / s 1 atm = 1.01 10 N m water = 1000 kg m
TK ) = T ( C ) 273 L = L0T
+
(
V = V0T
N
R = 8.314 J / mol K n =
N A = 6.02 10 23
kB = R N A
NA
12
Equations and Numbers
v string
FT
and v string =
2L
(m L)
I
r2 r1 = m and r2 r1 = (2 m + 1)
(in dB) = 10 log
( m = 0, 1, 2, L)
2
I0
A
I0 = 1.0 1012 W m 2 , log ( AB) = log A + log B , log = log A log B , log A n = n log A
B
v
v
f n = nf 1 ( n = 1, 2
Equations and Numbers for the Final
m
F
1
= , P = , FB = gVobject , Av = const . , P + v 2 + gy = const .
V
A
2
T (K ) = T (C ) + 273.15 , L = L0T , V = V0T , PV = nRT = Nk BT , R = 8.314 J mol K ,
1
3
f
N A = 6.02 10 23, kB = R N A , KE = mv 2 = k BT ,
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College Physics 103
Homework Set #1 Key
Spring 2010
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1.The human lungs can operate against a pressure differential of up to one-twentieth of an
atmosphere. If a diver uses a snorkel (long tube) for breathing, how far below water level
can he swim? From