Ariel Daher
Exam 1
Biostatistics
1.
a)
Depicted above is are two histograms a histogram that shows the distributions for humerus length
among sparrows that perished in a storm with those that survived. The distributions will be
describedexplained by the t

20.
a) Methods that would be appropriate to test whether there was a difference in
mean skin color between the Kokanee and Sockeye groups include a log
transform, Welchs test, a non-parametric test, and a pooled t-test.
b)
Boxplot Display of BEFORE the Lo

Ariel Daher
Biostatistics 228-53
Assignment #4
15 March 2016
Chapter 7: Analyzing Proportions
21.
a. Since the number of trials = 10, her success rate is can be calculated as 0.4 or 40%. This
can be calculated by taking x = 4 and multiplying it by the num

Ariel Daher-Biostatistics Exam 2
1.
Let x = the normal body size in female fur seals
Assume x follows
a) A normal distribution
b) With mu = 124.6
c) And sigma = 6.5
a)
Individuals that have a total body length greater than 125 cm is approximately 0.475.
b

Ariel Daher
Maaya Arbaji
Biostatistics 228-53
9 February 2016
Assignment 2: Estimating with uncertainty and probability
Chapter 4 #21
a. Error bar C indicates the standard deviation in which this bar should generally be wider
than the standard error, but

Ariel Daher Biostatistics Assignment #4 Optional Work
Chapter 7 Practice Problems
1. Assuming that seven independent pathogenic isolates have been extracted
from patients and tested for resistance
a. The assumptions of the binomial distribution are that n

Ariel Daher
Biostatistics 228-53
Assignment #4
15 March 2016
Note: * I collaborated my corrections with Andrew Nahra and Morgan Maclean, but not all of
our answers are the same.
Chapter 7: Analyzing Proportions
21.
a. Since the number of trials = 10, her

Review Problems for Exam 2
1.
a. T
h
e
odds in favor of divorce for non-Smokers are approximately 0.462 to 1. The odds
in favor of divorce for smokers are approximately 0.964 to 1.
b. The estimated odds ratio of divorce for smokers compared to divorce for

Review Problems for Exam 2
1.
a. T
h
e
odds in favor of divorce for non-Smokers are approximately 0.462 to 1. The odds
in favor of divorce for smokers are approximately 0.964 to 1.
b. The estimated odds ratio of divorce for smokers compared to divorce for

Chapter 11
18.
0. Parameter
Let mu = True mean Threespine stickleback fish mating preference
1. Hypothesis
H0: mu = 0 (The data has no evidence that the threespine stickleback fish has mating
preference with different size)
Ha: mu 0 (The data does provide