ECE3254 HW3. Assigned 10/5 Due Oct 19.
Also reading Ch. 5 to review your AC circuit analysis for problem 7 . Sorry that I did not review this
material but I will provide some brief review as we go along.
In 7d), you need to find vo/vs
ECE3254 HW5 Assigned Nov. 2 Due Nov. 9. Exam #3 Nov. 12 (Cover only Ch. 14. However, your
knowledge on the review materials, such as node voltage analysis, will be extremely useful).
P14.12 - The result indicates that, the math op
HW#2 ECE 3254 Assigned Sept 17, Due Sept 24.
Exam #1 announced (see bottom of the page)
Note: The above problems are from Exercise. For example, Exercise 10.2 is on p. 479
6. P 10.37.
7. P 10. 54 On this problem, you need to find RL, C and the peak voltag
ECE 3254 HW#1 Due Sept 10 (Monday)
P1.67 , Ans: Ix=4.5 A
P1.73, some Ans: v= 6V
P2.50 (make sure you submit Matlab code printout) , some Ans: v1=8.847 V
P2.78, some Ans: current through the source is 0.05A
P5.53, some Ans:
m) if vm
: i H"
Var. [5U I UJV
4. Ks: skarbm
VMG .0435 Vsszd I00 : Ki/asa mar
: Vasi + K- Rs (V6159; ,. We)
V656 XSmA/v 31w (Vagwm =- (S
2 L .
, (a) R'- (A)
* . 3,306
1 :1: + F
4V0! kf 50 luA A/l/2
4 W 7- 500 [u m
If: K. a, H L [C cfw_u n
F i . Veg: V I yd; k
W Y0 KL Var] ISU I USS EBV
. Ks 34ml R. cfw_cku
Solutions to example problems (Sorry it's a little messy, but I only had about 45 minutes to write this up) 1) At a glance, we see that the two current sources both send all of their current through the 5k resistor, so the total current is 2 amps, so
Non-Ideal Operational Amplifiers Open Loop The open-loop response gives you some powerful insight into the op amp's performance. Open-loop means NO feedback; the response of the "naked" op amp. Op Amps are generally used with f