CE 544 Open Channel Hydraulics - Homework #1
Assigned: 15 Jan
Due: 29 Jan1 at the start of class
Please review the syllabus carefully so that you understand the requirements for homework
format, etc.
1) T
CE 544 Open Channel Hydraulics - Homework #4 Solutions
Problem 1.
I did this in Excel, and the results are given below. Note that I also include the exact analytic solution, as
a point of comparison. We
CE 544
HW 3 Solutions
For my solution, Im going to cut / paste a bunch of stuff out of a spreadsheet I built
to solve this. First, let us deal with building a rating curve for the downstream
channel. This is
CE 544 Open Channel Hydraulics - Homework #6
Assigned: 7 Mar
Due: 14 Mar at the beginning of class
Please review the syllabus carefully so that you understand the requirements for homework format, etc.
1. Yo
CE 544 Open Channel Hydraulics - Homework #6
Assigned: 26 Feb
Due: 5 Mar at the beginning of class
Please review the syllabus carefully so that you understand the requirements for homework format, etc.
You hav
CE 544 Open Channel Hydraulics - Homework #4
Assigned: 19 Feb
Due: 26 Feb at the beginning of class
Please review the syllabus carefully so that you understand the requirements for homework format, etc.
As you
CE 544 Open Channel Hydraulics - Homework #6
My matlab code is below. Note: I assumed the 2:1 slope was 2H:1V.
[snip]
%ce544 HW 5 solution
clear all
close all
m=2;
ide slope (H:V)
phi=atan(1/m);
b=100;
'ase width (ft
CE 544 Open Channel Hydraulics - Homework #3
Assigned: 12 Feb
Due: 19 Feb at the beginning of class
Please review the syllabus carefully so that you understand the requirements for homework
format, etc.
Thi
CE 544 Open Channel Hydraulics - Homework #2
Assigned: 29 Jan
Due: 5 Feb at the beginning of class
Please review the syllabus carefully so that you understand the requirements for homework
format, etc.
1)
CE 544 Open Channel Hydraulics - Homework #6
1. The basis Parshall flume equation gives you Q = 47.8 cfs. From the figure, with an upper head of 2.0
ft, and a submergence factor of 0.9, we get a correction