Solutions to Homework Assignment 2
MATH 256-01 Section 1.2, Page 14 To Keep: 1, 2, 6, 11, 12, 13, 15 1. (a) Since dy = y + 5, we have dt dy/dt =1 y + 5 d [ln | y + 5|] = 1 dt ln | y + 5| = t + C ln |
Solutions to Homework Assignment 3
MATH 256-01 Section 1.3, Page 22 To Keep: 1-21, 23, 28 1. Second order linear. 2. Second order linear. 3. Fourth order linear. 4. First order nonlinear. 5. Second or
Solutions to Homework Assignment 8
MATH 256-01 Section 2.6, Page 95 Problems: 1-14, 18-22, 25-30 1. M = 2x + 3, My = 0; N = 2y 2, Nx = 0. Since My = Nx , this equation is exact. We have x = M x = 2x +
Solutions to Homework Assignment 12
MATH 256-01 Section 3.3, Page 152 Problems: 1-10, 15-18, 21-25, 28 1. W (f, g) = pendent. 2. cos 3 = cos 2 cos - sin 2 sin = (cos3 - cos sin2 ) - (2 sin2 cos ) = co
Solutions to Homework Assignment 9
MATH 256-01 Section 2.7, Page 103 Problems: 1, 3, 4, 5, 7, 11, 13 I will use the MAPLE code we created in class for most of these exercises. I modified the code a li
Solutions to Homework Assignment 18
MATH 256-01 Section 3.7, Page 183 Problems: 1-19 odd 1. The solution to the corresponding homogeneous equation is c1 e2t + c2 e3t , so let Y (t) = u1 e2t + u2 e3t .