jkgég @ d/wul. QAAA
October 12t , 2007
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ECES-306 Modulation and Coding
Recitation #3
1) Consider the following two message signal spectra (disregard the magnitude bars).
|M1(m)l 1AIZ[{U)[
- 21(4000) 23114000 M4000) M4000
a.) Assum
Chapter 11
11.1-1 This is clearly a non-stationary process. For example,
i
amplitudes of all sample functions are zero at same :
instants (one is shown with a dotted line). Hence, the I
statistics clearly depend onr. C 7 C 7 ti,
t -
Fig. S! 1.1-!
11.1-
Chapter 8 Exercises
3: .
8.1-1 If a plesiochronous network operates from Cesium beam clock which is accurate to :t 3 parts "
in 1012, how long will it take for a D83 signal transmitted between two networks to become out "
of sync if a 1/4 bit length
Chapter 6
#
6.1.1
6.1-2
6.1-3
The bandwidths of gi(t) and 92(2) are 100 kHz and 150 kHz, respectively. Therefore the Nyquist sampling rates
for 91(1) is 200 kHz and for 92(1) is 300 kHz.
A150 912(1) => {737100) # may), and from the width property of
Chapter 5
H
mte) - 2000 '9)
t" -sooo t"
t... ta
IO-IM q.qM '10. 10M 4.," IOM :on
Fig.55.1-1
5.1-1 in this case fc =10 MHz. In, = 1 and m; = 8000.
For FIVI :
A} = twp/27. = 2W x 105/21: = 105 Hz, Also j. = 107. Hence. (f.)....,. = 10' +105 = 10.1 MHz.