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Module 5: Exercise 5.2 Chi Square Procedures
What is the population under consideration?
The Presidents of the US.
What are the two variables under consideration?
Region of birth and political party of US Presidents.
Group the bivariate data for the varia
Module 5: Exercise 5.1 Interferences from Two Samples
Task 1: Consider the three samples listed in the table:
A
1
3
5
Total
X
9
9/3 = 3
B
0
6
2
5
2
15
15/5 = 3
s
2
2.45
C
3
12
6
3
24
24/4 = 6
4.24
Obtain total sum of squares (SST,) treatment sum of square
Module 4: Exercise 4.2 Hypothesis Testing
Refer to the following data:
Twotailed test; 0.10
Assume that the normal distribution applies and find the critical z values.
Two tailed test implies the following:
a
0.10
1
= 1= 10.05 = 0.9500
2
2
0.9500 = 1.
Module 4: Exercise 4.1 Inferences from Two Proportions and Samples
Task 1
These results should not be used for 2 reasons:
 The sample sizes used are not independent; they come from a same population (authors
friends);
 The samples are not given as simpl
Exercise 3.1
Construct a 95% confidence interval estimate of the mean salary of an NCAA football coach.
Mean of 415,953
Standard deviation of 463,364.
X=
n=40
X= 415953
J= 463364
= 0.05
/2 =0.025
Z 0.025 = 1.92
E=z or/z (j/n)
E = 1.96 (463364/40)
E= 14359
Exercise 2.1
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2
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3
0.16
Is not a probability distribution. Does not how measureable data, discrete and
continuous random variable categorical distribution, random variables, probability mass
function, stochastic processes, continuo
Exercise 2.2
Task 1
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The bar graph is the more suitable graphical representation of the data because bar graphs Are
easier to read and understand, the
Homework 1
Task 1
1.1
a. Population The collection of all individuals or items under consideration in a statistical study.
b. Sample That part of the population from which information is obtained.
1.7
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1.14
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Module 6: Exercise 6.1 Linear Correlation
The obtained scatter plot is given below,
The computed correlation coefficient between these two variables is 0.8717 and the critical value
from the table is 0.754.
As the correlation coefficient is more t