HOMEWORK ASSIGNMENT 1
12. The fact that the spheres are identical allows us to conclude that when two spheres are in contact, charge is redistributed so that they possess equal charges. Therefore, when a charged sphere (q) touches an uncharged one, t
EXAM 2 Wednesday, Feb 27th
Chapters 25, 26, and 27
Multiloop Circuits - Kirchhoff's Rules
Kirchhoff's Junction Rule : The sum of the currents entering any junction is equal to the sum of the currents leaving the junction.
Kirchhoff's Loop Rule : Th
RECITATION 14 CH 35-11. With an incident angle of 1 45, the light will refract at the surface of the glass, making an
angle 2 with the normal in the glass, where
n sin 2 sin 1.
The light will strike the other glass surface at point B at an angle
RECITATION 4
5. The area of each face is A = (1.40 m)2.
(a) Since the field has only a y-component, there will be no flux through the faces pointing in the x and z directions. Then
net
^ ( E j )j
A ^ j
y =0
^ ( E j )j A ^ j
y 1.40 2
0.00 N C
3
HOMEWORK ASSIGNMENT 7 10. The intensity is
I
c B max 2
0
2
3.0 108 m s 1.0 10 4 T 2 4 10 H m
7 2
2
1.2 106 W m 2 .
41. The initial beam has intensity I 0
43W m2 and is vertically polarized. Since the first polarizing
sheet has its polarizati
RECITATION 13 5. If P is the power and t is the time interval of one pulse, then the energy U in a pulse is
U
P t
100 1012 W 1.0 10 9 s
1.0 105 J.
11. (a) The maximum value of the magnetic field is
B max
(b) The intensity is
E max c
2.0 V m 3
RECITATION 11 7. Each of the semi-infinite straight wires contributes 0 i 4 R (Eq. 30-9) to the field at the center of
the circle (both contributions pointing "out of the page"). The current in the arc contributes a term given by Eq. 30-11 pointing i
RECITATION CHAPTER 22 1. The mass of an electron is m = 9.11 mass M = 75.0 kg is
n M m
1031 kg, so the number of electrons in a collection with total
75.0 kg 9.11 10 31 kg
8.23 1031 electrons .
The total charge of the collection is
q ne 8.23 103
HOMEWORK ASSIGNMENT 2
20.
We set a coordinate system with the origin at the center of the dipole, the x axis through the point
P and the y axis through the charge +q. The fields due to the individual charges make an angle with the x-axis. The x-c
HOMEWORK ASSIGNMENT 4 8. (a) We use Eq. 28-17:
C 4 ab b a 4 8.85 pF m 40.0 10 3 m 38.0 10 3 m 40.0 10 3 m 38.0 10 3 m
0
0
85pF.
(b) Let the area required be A. Then C
C b a
0
A b a , or
A
85 pF 2.0 10 3 m 8.85 pF m
0.019 m2
190 cm2 .
18. (a)
Chapter 23 Electric Fields
In this chapter we will introduce the concept of an electric field. As long as charges are stationary, Coulomb's law describes adequately the forces among charges. If the charges are not stationary we must use an alternati
Chapter 26 Current and Resistance
In this chapter we will introduce the following new concepts:
-Electric current ( symbol i ) -Electric current density vector (symbol J ) -Drift speed (symbol vd ) -Resistance (symbol R ) and resistivity (symbol )
Chapter 35 Images
One of the most important uses of the basic laws governing light is the production of images. Images are critical to a variety of fields and industries ranging from entertainment, to security, to medicine In this chapter we define a
RECITATION 7 9. (a) and (b) Assume i1 travels to the right, i2 up and i3 down. We use the loop rule twice, clockwise
around the outer loop and clockwise around the right loop:
10 V 5.0 V i1 R1 i3 R3 i2 R2 i3 R3 0 V; 0 V.
We use the junction rule i3
RECITATION 12 5. (a) Table 26-2 gives the resistivity of copper. Thus,
R
L A
1.69 10
8
m
0.10 m 1.25 10 m
3 2
1.1 10
3
.
(b) The current induced in the loop has a magnitude of
i
E
R
1 d mag R dt
r 2 dB , R dt
where r is the radius of t
HOMEWORK ASSIGNMENT 3
4.
The electrostatic potential difference is given by Eq. 25-8 as V
W elec q ,
where W elec is the work done by the field as the charge q moves in the electric field. (a) VB V A
W elec e 3.94 10 1 9 J 1.60 10 -1 9C 2.46 V.
2
RECITATION 9 1. (a) We use Eq. 29-3:
F mag q vB sin 3.2 10
19
C 550 m s 0.045 T sin 52
F mag m 6.2 10 18 N 6.6 10 27 kg
6.2 10
18
N.
(b) The acceleration has a magnitude of a
9.5 108 m s 2 .
(c) Since it is perpendicular to v , F mag does no
RECITATION 10 32. The magnetic force on the wire is
F mag iL B i L^ i ^ B y ^ Bz k j 0.010 T ^ j iL ^ Bz ^ B y k j
0.50 A 0.50 m 2.5 10 3 N ^ j
^ 0.0030 T k
^ 0.75 10 3 N k.
37. The magnetic field can be expressed as B
opposite the hinge has a
RECITATION 6
11. Since the mass density of the material does not change, the volume remains the same. If L1 is the
original length, L2 is the new length, A1 is the original cross-sectional area, and A2 is the new crosssectional area, then L1 A1
L2 A
RECITATION 5 5. The electric field produced by an infinite sheet of charge has magnitude E 2 0 , where is the surface charge density. The field is normal to the sheet and is uniform. Place the origin of a coordinate system at the sheet and take the
RECITATION 3
7. Since point P lies directly between the two identical +5.0q charges, the field due to one of those
charges is equal in magnitude and opposite in direction to the field due to the other charge. Their sum is zero. Note that the +3.0q c
Chapter 25
Electric Potential
In this chapter we will define the electric potential ( symbol V )
associated with the electric force and accomplish the following tasks:
Calculate V if we know the corresponding electric field.
Calculate the electric field i
HOMEWORK ASSIGNMENT 5 18. We consider the point at which it enters the field-filled region, velocity vector pointing downward.
The field points out of the page so that v B points leftward, which indeed seems to be the direction of the force; therefor
Chapter 24 Gauss' Law
In this chapter we will introduce the following new concepts:
The flux (symbol ) of the electric field Symmetry Gauss' law We will then apply Gauss' law and determine the electric field generated by: An infinite, uniformly char
Chapter 22 Electric Charge
In this chapter we will introduce a new property of matter known as "electric charge" (symbol q). We will explore the charge of atomic constituents. Moreover, we will describe the following properties of charge: - Types of
RECITATION 8 5. (a) The capacitance of a parallel-plate capacitor is given by C 0 A d , where A is the area of each
plate and d is the plate separation. Since the plates are circular, the plate area is A = R2, where R is the radius of a plate. Thus
RECITATION 2 11. (a) With a understood to mean the magnitude of acceleration, Newton's second and third laws lead to
mB aB mA a A mB 6.3 10 7 kg 7.0 m s 2 9.0 m s 2 4.9 10 7 kg .
(b) The magnitude of the force on the first particle (A) is
FB mA a A
Chapter 36 Interference
In this chapter we explore the wave nature of light and examine several key optical interference phenomena.
Diffraction
For plane waves entering a single slit, the waves emerging from the slit start spreading out, diffracting