Experiment 4b: Newton's Second Law and the Coefficient of Rolling Friction (i)
(ii)
Fr = Fn
F = Fr Therefore, Fr = Ma FN = Mg Ma = Mg = Ma/Mg = |a/g|
(iii) Gate #2 gives lower values.
Table I shows the deceleration of a moving cart as measured
Experiment 9(a) Springs Spring Energy and Energy Conservation & 9(b) Energy Conservation and the Coefficient of Rolling Friction
Table I shows the initial velocity and the distance that the cart moves in the experiment as found in three separate tr
Experiment 18b Simple Harmonic Motion: Sinusoidal Behavior in the Spring Mass System
Table I shows the gate number (gate), displacement [y(cm)], time [t(s)], velocity [v(m/s)], and acceleration [a(m/s2)] as determined in the experiment. Table I: Ex
Experiment 15: Moment of Inertia Rotational and Translational Kinetic Energy Question: Derive the above statement that E t/Es = 0.71 KE s = KEt + KEr = (1/2)mv2 + (1/2)I2 Using I = (2/5)mr2 and = v/r, KE s = KEt + KEr = (1/2)mv2 + (1/2)[(2/5)mr2](v
Experiment 21: Forced Oscillations and Resonance in a Simple Harmonic Motion System 2fo = (k/M)1/2 T = 2(M/k), 1/fo = T 1/fo = 2(M/k) fo = (1/2) (k/M) 2fo = (k/M)1/2 Dr. Placek told us not to worry about answering this question.
(i)
(ii)
(iii) Bot
Experiment 24 The Speed of Sound in Air: Resonance Method (i) Equation 2 [ = 4L/(2n 1)] cannot really be derived, but can be proven by this experiment. (Dr. Placek said to be sure to note this).
(ii)
(iii)
A pipe organ most closely represents th
Experiment 7: Uniform Circular Motion and the Centripetal Force
(i)
The Experimental Centripetal Force as a Function of Centripetal Acceleration
Centripetal Force
0.5 0.4 0.3 0.2 0.1 0 0 1 2 Centripetal Acceleration y = 0.28x - 0.1148 R2 = 1
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