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CHE 220  THERMODYNAMICS  Penn State Study Resources
 Penn State University (Penn State, PSU)
 PROF. MARANNAS

lecture_24after
School: Penn State
Course: THERMODYNAMICS
CHE 220 Introduction to Chemical Engineering Thermodynamics Lecture 24:examples of open system energy balances Flow calorimetry Mixing Adiabatic turbine Sudden expansion 1 Example 1: a flow calorimeter operates at steady state and conditions noted

sol14
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 14 Due: Will not be collected Reading: Sections 6.76. Note: the nal will cover chapters 16, up to and including section 6.9. 1 QB heat in 1 2 boiler work in work out pump turbine WB WT condenser 3 4 heat out QC Problem

hw14
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 14 Due: Will not be collected Reading: Sections 6.76. Note: the nal will cover chapters 16, up to and including section 6.9. Problems: 6.27, 6.29. 6.30, 6.31, 6.39 1

hw13
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 13 Due: April 24 Reading: 6.6 Problems: 6.12, 6.15, 6.17, 6.20 1

exam4
School: Penn State
Course: THERMODYNAMICS
Problem 1 A rigid pressurized cylinder contains steam at 22 bar, 400 C. The cylinder is placed in a heat bath at 100 C and is allowed to reach thermal equilibrium. a) Calculate the amount of heat. b) Calculate the entropy generation. c) Calculate the volu

hw12
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 12 Due: Friday April 18 Reading: Chapter 6, 6,16.5 Problems: 6.2, 6.4, 6.5, 6.8 1

hw7
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 7 Due: Will not be collected Reading: 3.83.10; review of chapter 3. Problems 3.6, 3.17, 3.28, 3.31, 3.35, 3.38 1

hw6
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 6 Due: February 27 Reading: Chapter 3, sections 3.63.7; read ahead 3.83.9. Problems: 3.18, 3.22, 3.26, 3.29 1

hw8
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 8 Due: March 20 Happy Spring Break! Reading: Chapter 4: 4.1, 4.2 Problems 4.3, 4.4, 4.5, 4.7. 1

hw4
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 4 Due: February 13 Reading: 2.32.12, review of chapter 3. Read ahead sections 3.13.3 Problems: 2.15, 2.18, 2.20, 2.25. 1

hw5
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 5 Due: February 21 Reading: 3.33.6 Problems: 3.3, 3.4, 3.10, 3.14 1

fig_mollier
School: Penn State
Course: THERMODYNAMICS
4000 Mollier diagram of steam 3900 C 0 T. Matsoukas 2014 75 700 C 3800 650 C 3700 600 C 3600 550 C 1000 bar 800 bar bar 3500 400 bar bar 600 3400 40 b bar 0.1 5b ar 0.2 8b ar 350 C 300 C 0.0 2900 6b 3000 0.0 ar 0.0 3100 400 C bar 0.1 100 60 b ar 150 bar

LK_Tables
School: Penn State
Course: THERMODYNAMICS
Lee Kesler Tables Tr = 0.5 z0 z1 h0 h1 s0 s1 0 1 Pr 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2 1.4 1.6 1.8 2 2.5 3 3.5 4 0.0207 0.0413 0.0619 0.0825 0.1031 0.1236 0.1442 0.1647 0.1851 0.2056 0.2261 0.2465 0.2873 0.3280 0.3687 0.4092 0.5103 0.6110 0.711

sol2
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 2 Due: January 30 Reading: Chapter 2: 2.12.3 1 Problem 1 Solution a) 25 C, 1 bar: liquid, because the temperature is below the saturation temperature at 1 bar (99.63 C). 10 bar, 80 C: liquid, because the temperature is b

sol9
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 9 Due: March 27 Reading: 4.34.11, review of chapter 4 1 Problem 1 Solution Outline: For reversible isothermal process, Q D TS The work is then obtained as W D U Q Numerical substitutions (in standard steamtable units) T

sol13
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 13 Due: April 24 Reading: 6.6 1 Problem 1 ./problemdbase/ch06_12/problem.tex. Solution 1 2 P .bar/ 35: 3: T . C/ 500 200 H .kJ=kg/ 3451:5 2866 S .kJ=kg K/ 7:1592 7:3132 a) m.H2 P P H1 / D W ) mD P P W H2 H1 D 1:28 kg=s

sol12
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 12 Due: Friday April 18 Reading: Chapter 6, 6,16.5 1 Problem 1 Solution a) W D 45 J=mol K H D CP .T2 Q D H T1 / D W D 9083 J=mol 4583 J=mol b) S D Cp ln T2 T1 R ln P2 D P1 1:01778 J=mol K d) Wideal D H T0 S D 2 8779:55 J

sol11
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 11 Due: Will not be collected Reading: Chapter 5, sections 5.85.11 1 Problem 1 Solution a) The residual properties can be calculated as follows: H S R R P D V P Z @V dP T @T P @V dP @T P 0 Z D 0 R P with the integrations

sol3
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 3 Due: (Will not be collected) Reading: Review of sections 2.1, 2.2; 2.32.5 1 Problem 1 Solution a) At 1 bar, 210 C, the specic volume of steam is found by interpolation to be V D 2219:2 cm3 /g D 2:2192 m3 /kg Since the

sol4
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 4 Due: February 13 Reading: 2.32.12, review of chapter 3. Read ahead sections 3.13.3 Problems: 2.15, 2.18, 2.20, 2.25. Problem 1 Solution a) The second virial coefcient is directly related to the slope of an isotherm on

sol5
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 5 Due: February 21 Reading: 3.33.6 1 Problem 1 Solution a) For this constantpressure expansion, the amount of work is 1 1 W D P0 .Vs Vl / D P0 s l where P0 D 1 bar is the atmospheric pressure, V is the specic volume, is

sol6
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 6 Due: February 27 Reading: Chapter 3, sections 3.63.7; read ahead 3.83.9. 1 Problem 1 Solution From the steam tables at 6 bar we nd (in standard steam table units): V U H Liquid 0:0011 669:72 670:5 Vapor 0:3156 2566:8 2

sol10
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 10 Due: April 3 Reading: review of chapter 4; 5.15.7. 1 Problem 1 Solution The idealgas heat capacity of nitrogen is ig CP .t/ D 8:231 10 12 t 4 C 1:3053 10 8 t 3 C 5:8198 10 7 t2 2:17 10 3 t C 29:423 ig with T in K and

sol8
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 8 Due: March 20 Happy Spring Break! Reading: Chapter 4: 4.1, 4.2 1 Problem 1 Solution Entropy change of ice: The process is conducted under constant pressure (dQ D dH ), therefore, the entropy change will be calculated a

sol7
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 7 Due: Will not be collected Reading: 3.83.10; review of chapter 3. 1 Problem 1 Solution a) At the initial state: P1 D 5 bar; T1 D 151:84 C; V1 D 0:3748 m3 =kg; U1 D 2560:7 kJ=kg The mass in the tank is m D V tank =V1 D

sol1
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 1 Due: January 23 Reading: Chapter 1 1 Problem 1 Solution We will need the following unit conversions: 1 ft D 0:3048 m; 1 lb D 0:454 kg; 1 lbmol D 454 mol (Note on the conversion mol to lbmol: one mol has a mass equal to

hw9
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 9 Due: March 27 Reading: 4.34.11, review of chapter 4 Problems 4.8, 4.12, 4.18, 4.20 1

hw3
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 3 Due: (Will not be collected) Reading: Review of sections 2.1, 2.2; 2.32.5 Problems: 2.3, 2.6, 2.8, 2.9, 2.11, 2.12 The rst four problems of this assignment cover review material from sections 2.12.2. The last two prob

hw2
School: Penn State
Course: THERMODYNAMICS
ChE 220  Spring 2014 Homework Set 2 Due: January 30 Reading: Chapter 2: 2.12.3 Problems: 2.1, 2.2, 2.4 and 2.7 1

Lecture_17
School: Penn State
Course: THERMODYNAMICS
Lecture 17  1 step model processes Many "real" thermodynamic processes (apart from irreversibility) can be modeled as composed of a succession of "onestep" processes. Important examples of these buildingblock processes are: workfree (no change in