We aren't endorsed by this school

CHE 220 - THERMODYNAMICS - Penn State Study Resources
  • 3 Pages exam1
    exam1

    School: Penn State

    Course: THERMODYNAMICS

    CH E 220 Exam #1 February 3 6:307:45 PM Name: Student ID: Open books No personal notes or homework solutions Answers without explanation do not count Organize your work neatly State your assumptions clearly Good luck! Please sign your name under the pledg

  • 6 Pages lecture_24after
    lecture_24after

    School: Penn State

    Course: THERMODYNAMICS

    CHE 220 Introduction to Chemical Engineering Thermodynamics Lecture 24:examples of open system energy balances Flow calorimetry Mixing Adiabatic turbine Sudden expansion 1 Example 1: a flow calorimeter operates at steady state and conditions noted

  • 3 Pages LK_Tables
    LK_Tables

    School: Penn State

    Course: THERMODYNAMICS

    Lee Kesler Tables Tr = 0.5 z0 z1 h0 h1 s0 s1 0 1 Pr 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2 1.4 1.6 1.8 2 2.5 3 3.5 4 0.0207 0.0413 0.0619 0.0825 0.1031 0.1236 0.1442 0.1647 0.1851 0.2056 0.2261 0.2465 0.2873 0.3280 0.3687 0.4092 0.5103 0.6110 0.711

  • 1 Page hw14
    hw14

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 14 Due: Will not be collected Reading: Sections 6.76. Note: the nal will cover chapters 1-6, up to and including section 6.9. Problems: 6.27, 6.29. 6.30, 6.31, 6.39 1

  • 1 Page hw13
    hw13

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 13 Due: April 24 Reading: 6.6 Problems: 6.12, 6.15, 6.17, 6.20 1

  • 4 Pages exam4
    exam4

    School: Penn State

    Course: THERMODYNAMICS

    Problem 1 A rigid pressurized cylinder contains steam at 22 bar, 400 C. The cylinder is placed in a heat bath at 100 C and is allowed to reach thermal equilibrium. a) Calculate the amount of heat. b) Calculate the entropy generation. c) Calculate the volu

  • 7 Pages sol1
    sol1

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 1 Due: January 23 Reading: Chapter 1 1 Problem 1 Solution We will need the following unit conversions: 1 ft D 0:3048 m; 1 lb D 0:454 kg; 1 lbmol D 454 mol (Note on the conversion mol to lbmol: one mol has a mass equal to

  • 1 Page hw12
    hw12

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 12 Due: Friday April 18 Reading: Chapter 6, 6,16.5 Problems: 6.2, 6.4, 6.5, 6.8 1

  • 1 Page hw7
    hw7

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 7 Due: Will not be collected Reading: 3.8-3.10; review of chapter 3. Problems 3.6, 3.17, 3.28, 3.31, 3.35, 3.38 1

  • 1 Page hw6
    hw6

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 6 Due: February 27 Reading: Chapter 3, sections 3.63.7; read ahead 3.83.9. Problems: 3.18, 3.22, 3.26, 3.29 1

  • 1 Page hw8
    hw8

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 8 Due: March 20 Happy Spring Break! Reading: Chapter 4: 4.1, 4.2 Problems 4.3, 4.4, 4.5, 4.7. 1

  • 1 Page hw4
    hw4

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 4 Due: February 13 Reading: 2.32.12, review of chapter 3. Read ahead sections 3.1-3.3 Problems: 2.15, 2.18, 2.20, 2.25. 1

  • 1 Page hw5
    hw5

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 5 Due: February 21 Reading: 3.33.6 Problems: 3.3, 3.4, 3.10, 3.14 1

  • 6 Pages sol2
    sol2

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 2 Due: January 30 Reading: Chapter 2: 2.12.3 1 Problem 1 Solution a) 25 C, 1 bar: liquid, because the temperature is below the saturation temperature at 1 bar (99.63 C). 10 bar, 80 C: liquid, because the temperature is b

  • 5 Pages sol9
    sol9

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 9 Due: March 27 Reading: 4.34.11, review of chapter 4 1 Problem 1 Solution Outline: For reversible isothermal process, Q D TS The work is then obtained as W D U Q Numerical substitutions (in standard steam-table units) T

  • 8 Pages sol14
    sol14

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 14 Due: Will not be collected Reading: Sections 6.76. Note: the nal will cover chapters 1-6, up to and including section 6.9. 1 QB heat in 1 2 boiler work in work out pump turbine WB WT condenser 3 4 heat out QC Problem

  • 6 Pages sol13
    sol13

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 13 Due: April 24 Reading: 6.6 1 Problem 1 ./problem-dbase/ch06_12/problem.tex. Solution 1 2 P .bar/ 35: 3: T . C/ 500 200 H .kJ=kg/ 3451:5 2866 S .kJ=kg K/ 7:1592 7:3132 a) m.H2 P P H1 / D W ) mD P P W H2 H1 D 1:28 kg=s

  • 5 Pages sol12
    sol12

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 12 Due: Friday April 18 Reading: Chapter 6, 6,16.5 1 Problem 1 Solution a) W D 45 J=mol K H D CP .T2 Q D H T1 / D W D 9083 J=mol 4583 J=mol b) S D Cp ln T2 T1 R ln P2 D P1 1:01778 J=mol K d) Wideal D H T0 S D 2 8779:55 J

  • 5 Pages sol11
    sol11

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 11 Due: Will not be collected Reading: Chapter 5, sections 5.85.11 1 Problem 1 Solution a) The residual properties can be calculated as follows: H S R R P D V P Z @V dP T @T P @V dP @T P 0 Z D 0 R P with the integrations

  • 10 Pages sol3
    sol3

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 3 Due: (Will not be collected) Reading: Review of sections 2.1, 2.2; 2.32.5 1 Problem 1 Solution a) At 1 bar, 210 C, the specic volume of steam is found by interpolation to be V D 2219:2 cm3 /g D 2:2192 m3 /kg Since the

  • 7 Pages sol4
    sol4

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 4 Due: February 13 Reading: 2.32.12, review of chapter 3. Read ahead sections 3.1-3.3 Problems: 2.15, 2.18, 2.20, 2.25. Problem 1 Solution a) The second virial coefcient is directly related to the slope of an isotherm on

  • 6 Pages sol5
    sol5

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 5 Due: February 21 Reading: 3.33.6 1 Problem 1 Solution a) For this constant-pressure expansion, the amount of work is 1 1 W D P0 .Vs Vl / D P0 s l where P0 D 1 bar is the atmospheric pressure, V is the specic volume, is

  • 5 Pages sol6
    sol6

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 6 Due: February 27 Reading: Chapter 3, sections 3.63.7; read ahead 3.83.9. 1 Problem 1 Solution From the steam tables at 6 bar we nd (in standard steam table units): V U H Liquid 0:0011 669:72 670:5 Vapor 0:3156 2566:8 2

  • 6 Pages sol10
    sol10

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 10 Due: April 3 Reading: review of chapter 4; 5.15.7. 1 Problem 1 Solution The ideal-gas heat capacity of nitrogen is ig CP .t/ D 8:231 10 12 t 4 C 1:3053 10 8 t 3 C 5:8198 10 7 t2 2:17 10 3 t C 29:423 ig with T in K and

  • 5 Pages sol8
    sol8

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 8 Due: March 20 Happy Spring Break! Reading: Chapter 4: 4.1, 4.2 1 Problem 1 Solution Entropy change of ice: The process is conducted under constant pressure (dQ D dH ), therefore, the entropy change will be calculated a

  • 7 Pages sol7
    sol7

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 7 Due: Will not be collected Reading: 3.8-3.10; review of chapter 3. 1 Problem 1 Solution a) At the initial state: P1 D 5 bar; T1 D 151:84 C; V1 D 0:3748 m3 =kg; U1 D 2560:7 kJ=kg The mass in the tank is m D V tank =V1 D

  • 1 Page fig_mollier
    fig_mollier

    School: Penn State

    Course: THERMODYNAMICS

    4000 Mollier diagram of steam 3900 C 0 T. Matsoukas 2014 75 700 C 3800 650 C 3700 600 C 3600 550 C 1000 bar 800 bar bar 3500 400 bar bar 600 3400 40 b bar 0.1 5b ar 0.2 8b ar 350 C 300 C 0.0 2900 6b 3000 0.0 ar 0.0 3100 400 C bar 0.1 100 60 b ar 150 bar

  • 1 Page hw9
    hw9

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 9 Due: March 27 Reading: 4.34.11, review of chapter 4 Problems 4.8, 4.12, 4.18, 4.20 1

  • 1 Page hw3
    hw3

    School: Penn State

    Course: THERMODYNAMICS

    ChE 220 - Spring 2014 Homework Set 3 Due: (Will not be collected) Reading: Review of sections 2.1, 2.2; 2.32.5 Problems: 2.3, 2.6, 2.8, 2.9, 2.11, 2.12 The rst four problems of this assignment cover review material from sections 2.1-2.2. The last two prob

  • 2 Pages Lecture_17
    Lecture_17

    School: Penn State

    Course: THERMODYNAMICS

    Lecture 17 - 1 step model processes Many "real" thermodynamic processes (apart from irreversibility) can be modeled as composed of a succession of "one-step" processes. Important examples of these building-block processes are: workfree (no change in

Back to course listings