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School: Penn State
Course: THERMODYNAMICS
CH E 220 Exam #1 February 3 6:307:45 PM Name: Student ID: Open books No personal notes or homework solutions Answers without explanation do not count Organize your work neatly State your assumptions clearly Good luck! Please sign your name under the pledg
School: Penn State
Course: MASS BALANCES
ChE 210 Fall 2012 Quiz 07, 50 minutes 2012nov17 Last name _ First name _ Signature, indicating that you performed this exam with full academic integrity. _ 1 The Fischer-Tropsch process is a useful series of catalyzed reactions for converting hydrogen gas
School: Penn State
Course: Polymer Processing Technology
MatSE 448 / ChE 442: Polymer Processing Technology Exam #1 February 13, 2013 R. H. Colby 100 points total Name: _ I acknowledge that cheating will result in a grade of zero for the examination, and may result in failing the course and/or referral to the O
School: Penn State
Course: THERMODYNAMICS
CHE 220 Introduction to Chemical Engineering Thermodynamics Lecture 24:examples of open system energy balances Flow calorimetry Mixing Adiabatic turbine Sudden expansion 1 Example 1: a flow calorimeter operates at steady state and conditions noted
School: Penn State
Kristine Schoppe Chemistry 213 18 March 2008 Separation of Fluorene/Fluorenone Mixture by Column Chromatography Introduction Chromatography is the process of separating compounds using their chemical differences along with the differences of two phas
School: Penn State
Course: THERMODYNAMICS
CHE 220 Introduction to Chemical Engineering Thermodynamics Lecture 24:examples of open system energy balances Flow calorimetry Mixing Adiabatic turbine Sudden expansion 1 Example 1: a flow calorimeter operates at steady state and conditions noted
School: Penn State
Kristine Schoppe Chemistry 213 18 March 2008 Separation of Fluorene/Fluorenone Mixture by Column Chromatography Introduction Chromatography is the process of separating compounds using their chemical differences along with the differences of two phas
School: Penn State
3 / Diffusion in Concentrated Solutions 78 Table 3.4-1 Mass balance for species 1 in various coordinate systems Rectangular coordinates qc1 qn1x qn1y qn1z r1 qt qx qz qy Cylindrical coordinates qc1 1q 1 qn1h qn1z r1 rn1r qt qz r qr r qh Spherical coord
School: Penn State
You take a new job in a chemical plant and your first assignment is to figure out what to do about a bucket of a toxic chemical left behind. Your predecessor had left the bucket out back of the plant, but your company is in trouble with the EPA because th
School: Penn State
Approximate Schedule and Reading Material Note: Weekly reading assignments given in class are considered the definitive list of textbook material subject to examination not this list. All material covered in class, which will draw from sources beyond the
School: Penn State
Course: THERMODYNAMICS
CH E 220 Exam #1 February 3 6:307:45 PM Name: Student ID: Open books No personal notes or homework solutions Answers without explanation do not count Organize your work neatly State your assumptions clearly Good luck! Please sign your name under the pledg
School: Penn State
Course: MASS BALANCES
ChE 210 Fall 2012 Quiz 07, 50 minutes 2012nov17 Last name _ First name _ Signature, indicating that you performed this exam with full academic integrity. _ 1 The Fischer-Tropsch process is a useful series of catalyzed reactions for converting hydrogen gas
School: Penn State
.5! ran/f snow» all : Problem 1 (2% points) Diffusion is occurring through a thin ﬁlm of liquid. Initially, the concentration of the diffusing species in the ﬁlm is 0 throughout. At time = O, the-"coincﬁﬁﬁation on the left side of the liquid is held to 10
School: Penn State
School: Penn State
CHAPTER 3 Diffusion in Concentrated Solutions Diffusion causes convection. To be sure, convective ow can have many causes. For example, it can occur because of pressure gradients or temperature differences. However, even in isothermal and isobaric systems
School: Penn State
CHE 410, Fall 08. In class examples Class Example 1 Mass Balance Review Time to fill a balloon A balloon, initially at a volume of 0.01 m3 and filled with a gas at a pressure of 1 atm, is to be filled by flowing in helium at a rate of 0.1 m3/s and a press
School: Penn State
_ hog-c a M3 055 — _ - Mlil! . ' 6% l -. i a- my _ _ 1 :2 A: I- A A ‘: ,1 , Iv lYl-EAWVEAW ‘m-‘-A‘-‘g.‘v 1174-917 -' a Problem 2 (20 points): Pyrex glass is almost impermeable to all gases except He. Suppose a natural gas — He mixture is contained in a
School: Penn State
Homework 4 CHE 410 — Spring 2015 Assigned January 30, due February 6 Problem 1 — Problem 7.6-1 from your textbook (Knudsen diffusion) Problem 2 _ Problem 7.6-3 from your textbook (Knudsenftransition region diffusion) Problem 3 — Problem 7.1-4 from your te
School: Penn State
School: Penn State
%Homework1: exercise1 Pc = 24.9; %pressure(bar) P = 0.9*Pc; Pr = P/Pc; Tc = 568.7; R = 8.314e-5; %gas constant (bar. m^3/(mol. k) b1 = 0.118119; b2 = 0.265728; b3 = 0.15479; b4 = 0.030323; c1 = 0.0236744; c2 = 0.0186984; c3 = 0; c4 = 0.042724; d1 = 1.5548
School: Penn State
Problem Set #7 CHE 360 Due: Thursday, 4/16/2015 Consider the 2D Poisson equation on 11 square domain. 2u 2u 50exp(2 x) for 0 x 1 and 0 y 1 x 2 y 2 The boundary conditions are illustrated in the figure below. y u( x,1) 1 ux (1, y) 0 ux (0, y) 0 u( x,0) 0
School: Penn State
dx = 2.5; Tinf = 25; Tb = 50; L = 0:dx:50; x0 = ones(length(L),1); x1 = fsolve(@(x) fin(x),x0); figure(1) plot(L,x1*(Tb-Tinf)+Tinf) x2 = fsolve(@(x) fin2(x),x0); figure(2) plot(L,x2*(Tb-Tinf)+Tinf)
School: Penn State
Course: THERMODYNAMICS
CH E 220 Exam #1 February 3 6:307:45 PM Name: Student ID: Open books No personal notes or homework solutions Answers without explanation do not count Organize your work neatly State your assumptions clearly Good luck! Please sign your name under the pledg
School: Penn State
Course: MASS BALANCES
ChE 210 Fall 2012 Quiz 07, 50 minutes 2012nov17 Last name _ First name _ Signature, indicating that you performed this exam with full academic integrity. _ 1 The Fischer-Tropsch process is a useful series of catalyzed reactions for converting hydrogen gas
School: Penn State
Course: Polymer Processing Technology
MatSE 448 / ChE 442: Polymer Processing Technology Exam #1 February 13, 2013 R. H. Colby 100 points total Name: _ I acknowledge that cheating will result in a grade of zero for the examination, and may result in failing the course and/or referral to the O
School: Penn State
Course: THERMODYNAMICS
CHE 220 Introduction to Chemical Engineering Thermodynamics Lecture 24:examples of open system energy balances Flow calorimetry Mixing Adiabatic turbine Sudden expansion 1 Example 1: a flow calorimeter operates at steady state and conditions noted
School: Penn State
Kristine Schoppe Chemistry 213 18 March 2008 Separation of Fluorene/Fluorenone Mixture by Column Chromatography Introduction Chromatography is the process of separating compounds using their chemical differences along with the differences of two phas
School: Penn State
_ hog-c a M3 055 — _ - Mlil! . ' 6% l -. i a- my _ _ 1 :2 A: I- A A ‘: ,1 , Iv lYl-EAWVEAW ‘m-‘-A‘-‘g.‘v 1174-917 -' a Problem 2 (20 points): Pyrex glass is almost impermeable to all gases except He. Suppose a natural gas — He mixture is contained in a
School: Penn State
Homework 4 CHE 410 — Spring 2015 Assigned January 30, due February 6 Problem 1 — Problem 7.6-1 from your textbook (Knudsen diffusion) Problem 2 _ Problem 7.6-3 from your textbook (Knudsenftransition region diffusion) Problem 3 — Problem 7.1-4 from your te
School: Penn State
.5! ran/f snow» all : Problem 1 (2% points) Diffusion is occurring through a thin ﬁlm of liquid. Initially, the concentration of the diffusing species in the ﬁlm is 0 throughout. At time = O, the-"coincﬁﬁﬁation on the left side of the liquid is held to 10
School: Penn State
School: Penn State
School: Penn State
CHAPTER 3 Diffusion in Concentrated Solutions Diffusion causes convection. To be sure, convective ow can have many causes. For example, it can occur because of pressure gradients or temperature differences. However, even in isothermal and isobaric systems
School: Penn State
CHE 410, Fall 08. In class examples Class Example 1 Mass Balance Review Time to fill a balloon A balloon, initially at a volume of 0.01 m3 and filled with a gas at a pressure of 1 atm, is to be filled by flowing in helium at a rate of 0.1 m3/s and a press
School: Penn State
3 / Diffusion in Concentrated Solutions 78 Table 3.4-1 Mass balance for species 1 in various coordinate systems Rectangular coordinates qc1 qn1x qn1y qn1z r1 qt qx qz qy Cylindrical coordinates qc1 1q 1 qn1h qn1z r1 rn1r qt qz r qr r qh Spherical coord
School: Penn State
You take a new job in a chemical plant and your first assignment is to figure out what to do about a bucket of a toxic chemical left behind. Your predecessor had left the bucket out back of the plant, but your company is in trouble with the EPA because th
School: Penn State
Approximate Schedule and Reading Material Note: Weekly reading assignments given in class are considered the definitive list of textbook material subject to examination not this list. All material covered in class, which will draw from sources beyond the
School: Penn State
%Homework1: exercise1 Pc = 24.9; %pressure(bar) P = 0.9*Pc; Pr = P/Pc; Tc = 568.7; R = 8.314e-5; %gas constant (bar. m^3/(mol. k) b1 = 0.118119; b2 = 0.265728; b3 = 0.15479; b4 = 0.030323; c1 = 0.0236744; c2 = 0.0186984; c3 = 0; c4 = 0.042724; d1 = 1.5548
School: Penn State
Problem Set #7 CHE 360 Due: Thursday, 4/16/2015 Consider the 2D Poisson equation on 11 square domain. 2u 2u 50exp(2 x) for 0 x 1 and 0 y 1 x 2 y 2 The boundary conditions are illustrated in the figure below. y u( x,1) 1 ux (1, y) 0 ux (0, y) 0 u( x,0) 0
School: Penn State
dx = 2.5; Tinf = 25; Tb = 50; L = 0:dx:50; x0 = ones(length(L),1); x1 = fsolve(@(x) fin(x),x0); figure(1) plot(L,x1*(Tb-Tinf)+Tinf) x2 = fsolve(@(x) fin2(x),x0); figure(2) plot(L,x2*(Tb-Tinf)+Tinf)
School: Penn State
Homework #5: Part e) C(t+dt) = C(t) + dt * f f is dC/dt which is a nonlinear vector function. We linearize f: C(t+dt) = C(t) + dt *A*C(t) = (I+dt*A)*C(t) where I is a 2x2 identity matrix. C(t + dt) = [ 1 0 1 ] () After N steps we have: C(t+N*dt) = (I+dt
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 1 Assigned: Friday, January 30 Due: Thursday, February 5th on-line (at the beginning of the lecture) Note: Please use the le notation to upload the le on angel, label clearly
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 3 Assigned: Thursday, February 19 Due: Thursday, February 26th on-line (at the beginning of the lecture) Note: Please use the le notation to upload the le on angel, label cle
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 6 Assigned: Friday, March 27st Due: Thursday, April 2nd The temperature prole in a horizontal straight pin n of uniform cross section (Fig. 1) described by the heat Figure 1:
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 2 Assigned: Saturday, February 14 Due: Thursday, February 19 (at the beginning of the lecture) Note: Please include your name in the rst page, label clearly the problems and
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 3 Assigned: Thursday, February 19 Due: Thursday, February 26th on-line (at the beginning of the lecture) Note: Please use the le notation to upload the le on angel, label cle
School: Penn State
clc clear all close all tf = 6; dt = .3; Caf=10; ta=5; k=.12; df = @(C)[(Caf-C(1)/ta - k*C(1);-C(2)/ta + k*C(1)]; C0 = [20 0]'; % Euler explicit t = 0 : dt : tf; Cee = zeros(2,length(t); Cee(:,1) = C0; for i = 1 : length(t)-1 Cee(:,i+1) = Cee(:,i) + dt*d
School: Penn State
> k10 = 0.152; k12 = 0.207; k13 = 0.040; k21 = 0.092; k31 = 0.0048; > A=[-(k12+k13+k10) k21 k31;k12 -k21 0;k13 0 -k31] A= -0.3990 0.0920 0.0048 0.2070 -0.0920 0 0.0400 0 -0.0048 > eig(A) ans = -0.4523 -0.0398 -0.0037
School: Penn State
School: Penn State
HW #4: Part C: %We want to solve the ODE between t=0 and t=20. Time increments are 0.1 tf = 100; dt = .1; %We define a function equal to dC/dt A = [ -2.6 0.2 0.3 0.2; 0.8 -0.2 0 0; 0.7 0 -.3 0; 0.5 0 0 -.2]; I = 3; B = [0.1; 0 ; 0 ; 0]; dC = @(C) A*C+B*I;
School: Penn State
Course: THERMODYNAMICS
CHE 220 Introduction to Chemical Engineering Thermodynamics Lecture 24:examples of open system energy balances Flow calorimetry Mixing Adiabatic turbine Sudden expansion 1 Example 1: a flow calorimeter operates at steady state and conditions noted
School: Penn State
Kristine Schoppe Chemistry 213 18 March 2008 Separation of Fluorene/Fluorenone Mixture by Column Chromatography Introduction Chromatography is the process of separating compounds using their chemical differences along with the differences of two phas
School: Penn State
3 / Diffusion in Concentrated Solutions 78 Table 3.4-1 Mass balance for species 1 in various coordinate systems Rectangular coordinates qc1 qn1x qn1y qn1z r1 qt qx qz qy Cylindrical coordinates qc1 1q 1 qn1h qn1z r1 rn1r qt qz r qr r qh Spherical coord
School: Penn State
You take a new job in a chemical plant and your first assignment is to figure out what to do about a bucket of a toxic chemical left behind. Your predecessor had left the bucket out back of the plant, but your company is in trouble with the EPA because th
School: Penn State
Approximate Schedule and Reading Material Note: Weekly reading assignments given in class are considered the definitive list of textbook material subject to examination not this list. All material covered in class, which will draw from sources beyond the
School: Penn State
Course: THERMODYNAMICS
Lee Kesler Tables Tr = 0.5 z0 z1 h0 h1 s0 s1 0 1 Pr 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2 1.4 1.6 1.8 2 2.5 3 3.5 4 0.0207 0.0413 0.0619 0.0825 0.1031 0.1236 0.1442 0.1647 0.1851 0.2056 0.2261 0.2465 0.2873 0.3280 0.3687 0.4092 0.5103 0.6110 0.711
School: Penn State
Course: THERMODYNAMICS
4000 Mollier diagram of steam 3900 C 0 T. Matsoukas 2014 75 700 C 3800 650 C 3700 600 C 3600 550 C 1000 bar 800 bar bar 3500 400 bar bar 600 3400 40 b bar 0.1 5b ar 0.2 8b ar 350 C 300 C 0.0 2900 6b 3000 0.0 ar 0.0 3100 400 C bar 0.1 100 60 b ar 150 bar
School: Penn State
Chemical Engineering Exam #2 Equation Sheet Product Separation and Recycle (p. 135): Overall Conversion: Single-Pass Conversion: Recycle Ratio: Combustion: Percent Excess Air (p. 145): Ch. 5 Density of a mixture of liquids (p. 189): (eqn. 5.1-1) (eqn. 5.1
School: Penn State
Chemical Engineering Exam #2 Equation Sheet Ch. 4 General Balance Equation (p. 85): For continuous steady-state: For batch process: initial input + generation = output + consumption If balanced quantity is total mass, set generation = 0 and consumption =
School: Penn State
Chemical Engineering Exam #1 Equation Sheet Interpolation: Specific Gravity: Density & Flow Rate: Mass Fraction: Mole Fraction: Molality: Normality: Average Molecular Weight: Hydrostatic Pressure: Pressure: General Manometer Equation: Differential Manomet
School: Penn State
ECON 410.502 Macroeconomic Theory Spring 2010 Instructor: Guangyi Ma Assignment #2 Suggested Answers and Comments Page 1 Problem 1~25: Multiple choice problems 1. C Due to the diminishing MPK, the slope of the production function is steeper when 2. B the
School: Penn State
Course: MASS BALANCES
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School: Penn State
Course: MASS BALANCES
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School: Penn State
Course: MASS BALANCES
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School: Penn State
Course: MASS BALANCES
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School: Penn State
Course: MASS BALANCES
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School: Penn State
Course: MASS BALANCES
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School: Penn State
Course: MASS BALANCES
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School: Penn State
Course: MASS BALANCES
<?xml version="1.0" encoding="UTF-8"?> <Error><Code>NoSuchKey</Code><Message>The specified key does not exist.</Message><Key>7365e9fa69cd8c0395fafac0d820d1a3f9557088.doc</Key><RequestId>D 5931C40B7B09420</RequestId><HostId>dKtcHCmU4+Pso9r9+JlU/KWhQ+tzp4wV
School: Penn State
Course: MASS BALANCES
3/26/2008 CUM-Pnuam Pram: M-kvoo, 4TWW{ '_>§VLGIJ/75W 520m~10\£L //. / (QVEQ5-) {muml pig.) (ghnoldL) Wig LL51" (PM) Mass Balance on a Water Storage Tank A 12.5-m3 tank is being lled with water at a rate of 0.050 m3ls. At a moment when the tank conta
School: Penn State
Course: THERMODYNAMICS
CH E 220 Exam #1 February 3 6:307:45 PM Name: Student ID: Open books No personal notes or homework solutions Answers without explanation do not count Organize your work neatly State your assumptions clearly Good luck! Please sign your name under the pledg
School: Penn State
Course: MASS BALANCES
ChE 210 Fall 2012 Quiz 07, 50 minutes 2012nov17 Last name _ First name _ Signature, indicating that you performed this exam with full academic integrity. _ 1 The Fischer-Tropsch process is a useful series of catalyzed reactions for converting hydrogen gas
School: Penn State
.5! ran/f snow» all : Problem 1 (2% points) Diffusion is occurring through a thin ﬁlm of liquid. Initially, the concentration of the diffusing species in the ﬁlm is 0 throughout. At time = O, the-"coincﬁﬁﬁation on the left side of the liquid is held to 10
School: Penn State
School: Penn State
CHAPTER 3 Diffusion in Concentrated Solutions Diffusion causes convection. To be sure, convective ow can have many causes. For example, it can occur because of pressure gradients or temperature differences. However, even in isothermal and isobaric systems
School: Penn State
CHE 410, Fall 08. In class examples Class Example 1 Mass Balance Review Time to fill a balloon A balloon, initially at a volume of 0.01 m3 and filled with a gas at a pressure of 1 atm, is to be filled by flowing in helium at a rate of 0.1 m3/s and a press
School: Penn State
Course: MASS BALANCES
ChE 210 Spring 2014 Quiz 02, 45 minutes 2014 Feb 07 Ver. C Last name First name Signature, indicating that you performed this exam with full academic integrity. 2. Remote Engine Start. (40 points total) Introduction. Many cars allow remote s , which has t
School: Penn State
Course: MASS BALANCES
1. CURL UP AND DYE [70] Background: The hair care industry relies upon careful metering of dye to offer a diverse selection of hair dye, including Ash brown, Auburn brown, and Oak brown. Should the dye concentration in a hair color kit drift outside a rig
School: Penn State
Course: MASS BALANCES
ChE 210 Spring 2014 Quiz 03, 45 minutes 2014 Feb 28 Ver. A/B key Last name _ First name _ Signature, indicating that you performed this exam with full academic integrity. _ 1. MULTIPLE CHOICE [20] FOR VERSION A, 1) A gas cylinder contains (by mole) 8% eth
School: Penn State
Course: MASS BALANCES
ChE 210 Spring 2013 Final Quiz, 1 hour 50 minutes 2013 May 1 Last name _ First name _ Signature, indicating that you performed this exam with full academic integrity. _ 1 SCORE SHEET 1. _ / 40 pts. 2. _ / 15 pts. 3. _ / 40 pts. 4. _ / 5 pts. _ TOTAL / 100
School: Penn State
Course: THERMODYNAMICS
Problem 1 A rigid pressurized cylinder contains steam at 22 bar, 400 C. The cylinder is placed in a heat bath at 100 C and is allowed to reach thermal equilibrium. a) Calculate the amount of heat. b) Calculate the entropy generation. c) Calculate the volu
School: Penn State
Course: THERMODYNAMICS
Problem 1 The data below are for saturated liquid X : 190 C P D 1:9 bar T sat D SL D 83:54 J=mol K SV D 147:97 J=mol K L CP V CP D 32:9 J=mol K D 58 J=mol K Use these data to answer the following questions: a) Calculate the entropy of vaporization. b) Cal
School: Penn State
Course: THERMODYNAMICS
CH E 220 Exam #2 March 3, 2014 6:307:45 PM Name: Student ID: Open books No personal notes or homework solutions Answers without explanation do not count Organize your work neatly State your assumptions clearly Good luck! Please sign your name under the pl
School: Penn State
_ hog-c a M3 055 — _ - Mlil! . ' 6% l -. i a- my _ _ 1 :2 A: I- A A ‘: ,1 , Iv lYl-EAWVEAW ‘m-‘-A‘-‘g.‘v 1174-917 -' a Problem 2 (20 points): Pyrex glass is almost impermeable to all gases except He. Suppose a natural gas — He mixture is contained in a
School: Penn State
Homework 4 CHE 410 — Spring 2015 Assigned January 30, due February 6 Problem 1 — Problem 7.6-1 from your textbook (Knudsen diffusion) Problem 2 _ Problem 7.6-3 from your textbook (Knudsenftransition region diffusion) Problem 3 — Problem 7.1-4 from your te
School: Penn State
School: Penn State
%Homework1: exercise1 Pc = 24.9; %pressure(bar) P = 0.9*Pc; Pr = P/Pc; Tc = 568.7; R = 8.314e-5; %gas constant (bar. m^3/(mol. k) b1 = 0.118119; b2 = 0.265728; b3 = 0.15479; b4 = 0.030323; c1 = 0.0236744; c2 = 0.0186984; c3 = 0; c4 = 0.042724; d1 = 1.5548
School: Penn State
Problem Set #7 CHE 360 Due: Thursday, 4/16/2015 Consider the 2D Poisson equation on 11 square domain. 2u 2u 50exp(2 x) for 0 x 1 and 0 y 1 x 2 y 2 The boundary conditions are illustrated in the figure below. y u( x,1) 1 ux (1, y) 0 ux (0, y) 0 u( x,0) 0
School: Penn State
dx = 2.5; Tinf = 25; Tb = 50; L = 0:dx:50; x0 = ones(length(L),1); x1 = fsolve(@(x) fin(x),x0); figure(1) plot(L,x1*(Tb-Tinf)+Tinf) x2 = fsolve(@(x) fin2(x),x0); figure(2) plot(L,x2*(Tb-Tinf)+Tinf)
School: Penn State
Homework #5: Part e) C(t+dt) = C(t) + dt * f f is dC/dt which is a nonlinear vector function. We linearize f: C(t+dt) = C(t) + dt *A*C(t) = (I+dt*A)*C(t) where I is a 2x2 identity matrix. C(t + dt) = [ 1 0 1 ] () After N steps we have: C(t+N*dt) = (I+dt
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 1 Assigned: Friday, January 30 Due: Thursday, February 5th on-line (at the beginning of the lecture) Note: Please use the le notation to upload the le on angel, label clearly
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 3 Assigned: Thursday, February 19 Due: Thursday, February 26th on-line (at the beginning of the lecture) Note: Please use the le notation to upload the le on angel, label cle
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 6 Assigned: Friday, March 27st Due: Thursday, April 2nd The temperature prole in a horizontal straight pin n of uniform cross section (Fig. 1) described by the heat Figure 1:
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 2 Assigned: Saturday, February 14 Due: Thursday, February 19 (at the beginning of the lecture) Note: Please include your name in the rst page, label clearly the problems and
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 3 Assigned: Thursday, February 19 Due: Thursday, February 26th on-line (at the beginning of the lecture) Note: Please use the le notation to upload the le on angel, label cle
School: Penn State
clc clear all close all tf = 6; dt = .3; Caf=10; ta=5; k=.12; df = @(C)[(Caf-C(1)/ta - k*C(1);-C(2)/ta + k*C(1)]; C0 = [20 0]'; % Euler explicit t = 0 : dt : tf; Cee = zeros(2,length(t); Cee(:,1) = C0; for i = 1 : length(t)-1 Cee(:,i+1) = Cee(:,i) + dt*d
School: Penn State
> k10 = 0.152; k12 = 0.207; k13 = 0.040; k21 = 0.092; k31 = 0.0048; > A=[-(k12+k13+k10) k21 k31;k12 -k21 0;k13 0 -k31] A= -0.3990 0.0920 0.0048 0.2070 -0.0920 0 0.0400 0 -0.0048 > eig(A) ans = -0.4523 -0.0398 -0.0037
School: Penn State
School: Penn State
HW #4: Part C: %We want to solve the ODE between t=0 and t=20. Time increments are 0.1 tf = 100; dt = .1; %We define a function equal to dC/dt A = [ -2.6 0.2 0.3 0.2; 0.8 -0.2 0 0; 0.7 0 -.3 0; 0.5 0 0 -.2]; I = 3; B = [0.1; 0 ; 0 ; 0]; dC = @(C) A*C+B*I;
School: Penn State
If we run the file HW1_Q1, we get the following output in the command window: > HW1_Q1 ans = The liquid/gas nitrogen volume per is 6.796621e-05 and 6.254211e-04 m^3/mol, respectively part b) In the command window, we call the function written in file HW1_
School: Penn State
ChE 360 - Mathematical Methods in Chemical Engineering, Spring 2015 Homework Set 5 Assigned: Saturday, March 19 Due: Thursday, March 26th on-line (at the beginning of the lecture) Note: Please use the le notation to upload the le on angel, label clearly t
School: Penn State
M = 50; N = 50; Lx = 1; Ly = 1; u0=ones(N,M); u=fsolve(@hotplate,u0); %Discretized Variables: x = linspace(0,Lx,N); y = linspace(0,Ly,M); surf(x,y,u) %This estimates the value of u(.5,.5) u_m=(u(25,25)+u(26,26)/2; % ans = % % 1.7901
School: Penn State
function f=fin2(x) % parameters k = 10; h = 25; epsilon = 0.98; sigma = 5.67e-8; fin_length = .50; dx = .025/fin_length; D = .03; Tinf = 25; Tb = 50; a4 = -epsilon*4*sigma*(Tb-Tinf)^3*fin_length^2/(k*D); a3 = -4*epsilon*4*sigma*(Tb-Tinf)^2*Tinf*fin_length
School: Penn State
function [P] = HW1_Q2Pa(V,T) Pc = 24.9; %pressure(bar) Tc = 568.7; R = 8.314e-5; %gas constant (bar. m^3/(mol. k) b1 = 0.118119; b2 = 0.265728; b3 = 0.15479; b4 = 0.030323; c1 = 0.0236744; c2 = 0.0186984; c3 = 0; c4 = 0.042724; d1 = 1.55488e-5; d2 = 6.236
School: Penn State
%Homework1: exercise1 R = 8.3144621; %P = 2.2e6; %P = 2e5; P = 1.2e6; T = 110; a = 0.1408; b = 3.913e-5; f = @(v) P*v^3 - (P*b + R*T)*v^2 + a*v - a*b; v11 = 1e-2; v12 = 1e-2+1e-4; f1 = f(v11); f2 = f(v12); while abs(f2) > 1e-8 df = (f1 - f2)/(v11-v12); 0e
School: Penn State
School: Penn State
Course: THERMODYNAMICS
ChE 220 - Spring 2014 Homework Set 14 Due: Will not be collected Reading: Sections 6.76. Note: the nal will cover chapters 1-6, up to and including section 6.9. 1 QB heat in 1 2 boiler work in work out pump turbine WB WT condenser 3 4 heat out QC Problem
School: Penn State
Course: THERMODYNAMICS
ChE 220 - Spring 2014 Homework Set 12 Due: Friday April 18 Reading: Chapter 6, 6,16.5 1 Problem 1 Solution a) W D 45 J=mol K H D CP .T2 Q D H T1 / D W D 9083 J=mol 4583 J=mol b) S D Cp ln T2 T1 R ln P2 D P1 1:01778 J=mol K d) Wideal D H T0 S D 2 8779:55 J
School: Penn State
Course: THERMODYNAMICS
ChE 220 - Spring 2014 Homework Set 11 Due: Will not be collected Reading: Chapter 5, sections 5.85.11 1 Problem 1 Solution a) The residual properties can be calculated as follows: H S R R P D V P Z @V dP T @T P @V dP @T P 0 Z D 0 R P with the integrations
School: Penn State
Course: THERMODYNAMICS
ChE 220 - Spring 2014 Homework Set 3 Due: (Will not be collected) Reading: Review of sections 2.1, 2.2; 2.32.5 1 Problem 1 Solution a) At 1 bar, 210 C, the specic volume of steam is found by interpolation to be V D 2219:2 cm3 /g D 2:2192 m3 /kg Since the
School: Penn State
Course: THERMODYNAMICS
ChE 220 - Spring 2014 Homework Set 4 Due: February 13 Reading: 2.32.12, review of chapter 3. Read ahead sections 3.1-3.3 Problems: 2.15, 2.18, 2.20, 2.25. Problem 1 Solution a) The second virial coefcient is directly related to the slope of an isotherm on
School: Penn State
Course: THERMODYNAMICS
ChE 220 - Spring 2014 Homework Set 5 Due: February 21 Reading: 3.33.6 1 Problem 1 Solution a) For this constant-pressure expansion, the amount of work is 1 1 W D P0 .Vs Vl / D P0 s l where P0 D 1 bar is the atmospheric pressure, V is the specic volume, is