Set 6 2008
5.1*
d (u + gz ) = 0
(a)
(b)
Btu 1.29 u lbm o T = = = 11 F CV ,steel Btu 0.12 o lbm F Btu 1.29 u lbm o T = = = 1.3 F CV ,water Btu 1.0 o lbm F
5.3*
(a)
N
ChE 218 Spring 2008 Exam 1 Name: _ Part 1 (30 points) CLOSED Book/Notes This part should take not longer then 10 minutes. Do any 5 of the six problems. Mark an `X' through the number you do not wish
2.7- 6
Energy Balance on a Flow System with a Pump and Heat Exchanger. Water stored in a large, well-insulated storage tank at 21.0 C and atmospheric pressure is being pumped at steady state from thi
Problem 6.81 - rework Example 6.19 for particle settling in water at 68F . Dp := 10
-6
cP := 10
-2
poise
m
p := 2000
kg m
3
f := 1000
kg m
3
f := 1.002cP
Assuming that stokes law applies,
Set 07
6.13
r02 - r 2 P Recall the velocity profile for Poisueille Flow: V (r ) = - (eqn 6.8) 4 x and maximum velocity occurs at r = 0: Vmax = V (0) =
r02 P D02 P - = - 4 x 16 x Vma
Set 4 2008
4.2 (a)
(b)
Relative to the gun barrel, 2 ft 2000 mV 2 lbf s 2 s 3 K.E. = = 0.02 lbm = 1.242 10 ft lbf = 1.684 kJ 2 2 32.2lbm ft ft V0 2000 s V = V0 - gt; V = 0 when t = = = 62.11
Set 03 2.58* The pressure at the bottom of the dip tube is h (a) That is the depth at the end of the dip tube. The total depth is 4.807 + 0.5 =5.3074 ft. (b) If we use 2.000 psig, the calculated depth
2.30* See Example 2.9.
lbf 1 ft in 2 t= = 0.05 ft = 0.60 in = 1.52 cm lbf 2 10,000 2 in 1000 From the larger table in Perry's equivalent to Appendix A.3 we see that a 12 inch diameter, schedule 80 pip
Set 1 2008
1.3*
= mass
volume:
For 100lbm
= 100 lbm
102
50lbm 50lbm lbm =102 3 + 3 3 ft 4.49 62.3lbm ft 62.3lbm ft
lbm ft 3 453.6g 1.63g = 3 3 lbm ft 28310cm cm 3 Discussion; this
kJ := 10 J Problem 1 Given/Directly Calculated D1 := 4.026in from A.2, page 598) := 6cp D2 := 2in D2 := = 0.497 D1 Part a) Assuming a discharge coefficient: (This will need to be checked later) Usi
Set 5 2008
4.6* System: the water path through the dam, from inlet to outlet., steady flow The initial and final velocities are essentially 0. Assume also the enthalpy does not change. Then, the only