332:373 Elements of Electrical Engineering Dr.Drzewiecki Minimum Things to Know for Midterm
Spring, 2008
Know how to: 1. Apply the voltage divider and current divider principles, equivalent circuit combinations. 2. Write the node voltage equations and app
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5,69 Assume the switch in the circuit of Figure P569
has been closed for a very long time. It is suddenly
opened at r = O and then reclosed at r = 5 5. Determine
an expression for the inductor current for f 3 O. 7fiétIpL éérlLf"
332: 373 Elements of Electrical Engineering Shoane Notes on Solutions to 2ndOrder Differential Equation
Dr.
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2ndOrder DE
Dr. Shoane
2
2ndOrder DE Dr. Shoane
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2ndOrder DE Dr. Shoane
4
2ndOrder DE Dr. Shoane
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2ndOrder DE
6
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2ndOrder DE
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EE 332:375 Elements of Electrical Engineering Laboratory Lab Reports are due two weeks after the laboratory session, on the next laboratory date.
Lab Report Content: 1. One Group Report can be written on Lab Manual. Include a representative Prelab. 2. Ind
332: 373 Elements of Electrical Engineering Spring 2009 Dr. Drzewiecki Homework Assignment #1 Due Tuesday, January 27
2.3 2.7 2.8 2.20 2.48
Note 
1 amp = 1 coulomb/sec
Note  1 watt = 1 joule/sec Replace the v(t) vs t graph with v = 12 volts (a constant)
332: 373 Elements of Electrical Engineering Homework Solutions #11
Spring, 2007 Dr. Shoane
1
Problem 7.43
Hwk Soln #11 Spring, 2007 Dr. Shoane
2
Problem 7.46, part (d) (cont)
Alternatively,
Hwk Soln #11 Spring, 2007 Dr. Shoane
3
5.76 Find the maximum value of u(r) for I > O in the
circuit of Figure P536 if the circuit is in steady state at
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5.70 For 1' > 0. determine for what valuc ofrz = 25A
in the circuit of gun: P530 if the circuit is in steady
state at r = 0.
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NOTES ON LECTURES 2 & 3
1. Voltage Across a Resistor The terminal where the positive current flows into the resistor is the positive voltage terminal across the resistor, regardless of what was LABELED there as the positive terminal. 2. Voltage and Curren
These Equations Generalize to Circuits with More Than 2 Nodes or 2 Meshes
Equation Setup for Nodal Analysis Gs connected x Va to Node a
Node a: Node a

Gs between x Vb = Current Source Nodes a & b into
Node b: Node b

Gs between x Va Nodes a & b
+
Gs