Homework 1 Solutions
The arriving packet must first wait for the link to transmit 6,750 bytes or 54,000 bits.
Since these bits are transmitted at 2 Mbps, the queuing delay is 27 msec. Generally, the
queuing delay is (nL + (L - x)/R.
8 10 6
Homework 2 Solutions
a. In the second segment from Host A to B, the sequence number is 197, source port
number is 302 and destination port number is 80.
b. If the first segment arrives before the second, in the acknowledgement of the first
Homework 3 Solutions
a). Data destined to host H3 is forwarded through interface 3
b). No, because forwarding rule is only based on destination address.
Homework 4 Solutions
If we divide 10011 into 1010101010 0000, we get 1011011100, with a remainder of R=0100.
Note that, G=10011 is CRC-4-ITU standard.
a). No. E can check the subnet prefix of Host Fs IP address, and then learn that F is on