Chapter 2 Homework Solutions
Textbook Homework
E2.3a V1 = 22.4 L , V2 = 44.8 L , T = 273 K (constant) , n = 1.00 mol
(a) Reversible
U nCV ,m T 0
H nC p ,m T 0
w nRT ln(V2 / V1 ) 1 mol (8.31 J / mol K
CHEM 5200 - Final Exam - December 12, 2013
INFORMATION PAGE (Use for reference and for scratch paper)
Constants and Conversion Factors:
R = 8.31 J/mol-K = 8.31 kPa-L/moiK
1 Latm = 101 J 1 L-bar = 10
CHEM 5200 - Final Exam - December 12, 2013
INFORMATION PAGE (Use for reference and for scratch paper)
Constants and Conversion Factors:
R = 8.31 J/mol-K = 8.31 kPa-L/mol-K
1 L-atm = 101 J
1 L-bar = 10
`CHEM 5200 - Exam 4 - November 26, 2013
INFORMATION PAGE (Use for reference and for scratch paper)
Constants and Conversion Factors:
F = 96,500 C/mol
1 C-Volt = 1 J
R = 8.31 J/mol-K = 8.31 C-V/mol-K =
CHEM 5200 - Exam 2 - October 17, 2013
INFORMATION PAGE (Use for reference and for scratch paper)
Constants and Conversion Factors:
R = 0.082 L-atm/mol-K = 8.31 J/mol-K = 8.31 kPa-L/mol-K
1 L-atm =