Name:
Momentum and Its ConServation — Practice
Find the missing variable(s).
3.0 m/s
5: =21 kg mfs
m:ﬂ_ _: m
V B‘S—lin: 71Q
A3. Finghe momentum of a 2.0 kg mass when \7 = 5.0I — 2.5j #.
f A '
3 —_ , s A m a
p mv @9ng Qt, (216$ g5 -
4. A 1.2 kg ball dro
University of the Free State
Universiteit van die Vrystaat
Physics Department
Departement Fisika
Semester test I / Semestertoets I
FSK 114
Assessors:
19 February 2010
Time: 60 min
Prof HC Swart
Dr OM Ntwaeaborwa
Mr J Dolo
Marks: 50
Answer all the question
25
Chapter 34
1. The bird is a distance d2 in front of the mirror; the plane of its image is that same
distance d2 behind the mirror. The lateral distance between you and the bird is d3 = 5.00
m. We denote the distance from the camera to the mirror as d1,
University of the Free State
Department of Physics
Semester test 2
FSK 114
Assessors: Prof. OM Ntwaeaborwa
20 April 2010
Prof. HC Swart
Time: 60 min
Mr. JJ Dolo
Marks: 50
2
-19
Answer all the questions. (Given g = 9.8 m/s ; nair=1, 1.6 x 10 C)
SECTION A
1
Chapter 9: Center of Mass & Linear Momentum
Example Problems
r
r
1
rcom M m i r i
r
r
Ptotal Mv com
r
r
r
r
p10 p20 p1f p2f
r
r
r
r
m1v10 m2 v 20 m1v1f m2 v 2f
t
r r
p J f F(t)dt
t0
m1 m2
2m2
v
v
m1 m2 10 m1 m2 20
elastic
2m1
m2 m1
v
v
m1 m2 10 m1
PHYSICS 1, CHAPTER 4
ADDITIONAL PROBLEMS
1. A force in the negative direction of an x axis is applied for 27 ms to a 0.40 kg ball initially moving at
14 m/s in the positive direction of the axis. The force varies in magnitude, and the impulse has magnitud
Chapter 9
9.2 Figure 9-37 shows a three particle system with masses m1 = 3.0 kg , m2 = 4.0 kg , and
m3 = 8.0 kg . The scales are set by xs = 2.0 m and ys = 2.0 m . What are (a) the x coordinate and
(b) the y coordinate of the systems center of mass? (c) I
Name:
(4 points)
ANSWER KEY
PHYSICS 1050
Mid-term Test 1
University of Wyoming
15 February 2005
This test is open-note and open-book. This means that any reference material is
permitted during the test. Calculators also are permitted. However, no collabor
Lecture 12
Chapter 17
Waves II
Prob 48 Chpt 16
A rope under tension of 200 Newtons and fixed at both
ends, oscillates in a second harmonic standing wave
pattern. The displacement of the rope is given by
y = (0.10m)(sin x / 2)(sin12 t)
where x=0 at one end
Chapter 29
Magnetic Fields
CHAPTE R OUTLI N E
29.1 Magnetic Fields and Forces
29.2 Magnetic Force Acting on a
Current-Carrying Conductor
29.3 Torque on a Current Loop in a
Uniform Magnetic Field
29.4 Motion of a Charged Particle
in a Uniform Magnetic Fiel