Chapter 3 Reactor Energy
Distribution
Xue Yang, PhD
Assistant Professor of Mechanical Engineering
Texas A&M University-Kingsville
9/8/2016
MEEN 4395
1
3.4 Energy generation parameters
Example 3.2: Heat Transfer Parameters
in Various Power Reactors. For t

=
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= 0 1 1 1
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14
However = 1 0 over the opening A1 and zero
elsewhere around the surface
of the vessel. Therefore if the coolant density at the opening
is p1, we get
The solid line in Figure 4.3 defines the control volume
around t

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.
=
=1
+
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(4.33)
19
The momentum law, applied to the control volume, accounts
for the rate of momentum change because of both the
accumulation of momentum due to net influx and the
external forces acting on the control volume. By s

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Consider loss of coolant from a pressure vessel. The process
can be described by observing the vessel as a control volume
or the coolant as a control mass. Assume the coolant leaves
the vessel at an opening of area A1 with velocit

=
+ (4.3)
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7
The right-hand side of Equation 4.3 describes the rate of change
of the variable in Eulerian coordinates, and the left-hand side
describes the time rate of change in Lagrangian coordinates.
In a steady-state flow system

, =
,
+
,
(4.12)
, =
(4.13)
,
=
,
, =
, +
,
(4.14)
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=
(4.15)
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Where = relative velocity of the material with respect to the
surface of the control volume:
The total rate of change of the integral of the function

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2. If valve C is opened just until the
pressure in the two tanks is equalized and
is then closed, what are the final
temperature and pressure in tanks A and
B? Assume no transfer of heat between
tank A and tank B.
Note that for a diat

10/12/2016
MEEN 4395
Texas A&M University-Kingsville
Xue Yang, PhD
Assistant Professor of Mechanical Engineering
Chapter 4
Transport Equations for
Single-Phase Flow
1
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2
Thermal analyses of power-conversion systems involve the
solutio

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= =1 +
.
.
(4.39)
+
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+
20
The energy equation (first law of thermodynamics) applied to a
control volume takes into consideration the rate of change of
energy in the control volume due to net influx and any sources or
sinks

=
0
= 0.5
3.5
Solve for T1.
0
1
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Solve for n2/n, and you also know n1/n.
The energy loss from n1 shall equal energy gain of
n2. Therefore,
1 0 1 = 2 2 0
Solve for T2.
0
We assume there are n1 moles of gas in tank A,
and n2 moles of gas

10/12/2016
MEEN 4395
Texas A&M University-Kingsville
Xue Yang, PhD
Assistant Professor of Mechanical Engineering
Chapter 4
Transport Equations for
Single-Phase Flow
1
10/12/2016
MEEN 4395
2
Thermal analyses of power-conversion systems involve the
solutio