Chapter 6
No need to know frequency polygon
If you dont divide by the n-1 then the estimator is biased
Better know jump to solve this chapter questions or else you are fucked.
Chapter 7
Not included in the open book test, but in closed book exam
Rand

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ME 335
ME 335
Quiz 8 Solution
11 March 2016
QUIZ
Suppose that the random variable X has a continuous uniform distribution over the
interval [2, 6]. Determine the cumulative distribution function.
Solution
A continuous uniform distribution of random variab

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Jointly Distributed Random Variables
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Random Variables
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The Uni

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Discrete Random Variables
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Continuous Random Variables
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Descriptive Statistics
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Ch. 9 HW
Problem 1
HO: = 16 (The mean waiting time is equal to 16 minutes)
HA: > 16 (The mean waiting time is greater than 16 minutes)
= 0.05 =5
p is greater than 0.05 so we cannot reject the null hypothesis.
Problem 2
: = 15
a) Power= 0.32 b) n=156
Prob

Problem 1:
Problem2:
Normal distribution fits the histogram well, and Prob < W is 0.5183 which is really good.
Problem 3:
Gamma and Beta distributions fit very well, but gamma distribution is better since it has higher Prob > W2 than betas Prob > D.

ME 335 Chapter 3 Homework
Problem 1
a)Use JMP to find the probability of obtaining at least one 6 in four rolls of a fair die.
p(x1) = 1- p(0) = 1- 0.4823 = 0.5177
b)Now consider another game; throw a pair of dice 24 times and compute the probability of a

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ME 335
HO08
Engineering Probability and Statistics
Homework 4
11 February 2016
Announcements
This assignment is due by 5 PM on 19 February 2016. Please place your section number
at the top of your homework.
Readings
Sections 2.8, 3.1, 3.2, and 3.3 your te

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ME 335
HO19
ME 335
Homework 8 Solutions
28 March 2016
Section 4.8: Exponential Distribution
4.118, 4.119, 4.125
Section 5.1: Two or More Random Variables
5.1, 5.2, 5.8
Section 5.2: Covariance and Correlation
5.33, 5.34, 5.36, 5.46
Section 6.1: Numerical S

ME 335
HO21
ME 335
Homework 9 Solutions
1 April 2016
Section 6.3: Frequency Distributions and Histograms
6.53, 6.56, 6.58
6.53
Histogram of Energy
Frequency
20
15
10
5
0
Engery Consumption
The data are skewed.
6.56
25
Frequency
20
15
10
5
0
20-30
30-40

ME 335
HO17
ME 335
Homework 6 Solutions
17 March 2016
Section 4.2: Probability Distributions and Probability Density Functions
4.1, 4.4, 4.11
4-1.
a) P (1 < X ) = e x dx = (e x )
1
1
= e 1 = 0.3679
2 .5
b) P (1 < X < 2.5) =
e
x
dx = (e x )
1
2.5
1
= e 1 e

ME 335
ME 335
Quiz 4 Solution
10 February 2016
Problem
The analysis of shafts for a compressor is summarized by conformance
to specifications:
444
22
520
14
If a shaft is selected at random, what is the probability that it conforms
to surface finish requi