Adam Wrobel
Paxton Thedford
Jeremy Binagia
Jingyan Yue
Characterization of Lipid Bilayer and Protein Properties Through Fluorescence
Microscopy
Abstract
The rate of lateral diffusion of the cellular b
Henry Nguyen
Hhn247
52670
Leigh Krueger
Experiment #7
Bomb Calorimetry
Introduction
The purpose of this experiment is to use a bomb calorimeter to find the standard
enthalpy of formation for various c
Yawen Ren
Quynh Sam
Melvin Lopez
Visualizing Atoms and Molecules by Scanning Tunneling Microscopy
Abstract
In this experiment, we studied the surface structure and electronic properties of
HOPG, Au(11
Quynh Sam
Yawen Ren
Melvin Lopez
Photophysical Properties of Nanocrystalline Materials
Abstract
In this investigation, we carried out a series of experiments to study size
dependent optical properties
Melvin Lopez
Yawen Ren
Quynh Sam
Differential Scanning Calorimetry
Abstract
Differential scanning calorimetry (DSC) measures various thermal properties of
materials by measuring heat flow as a functio
Similarly to HOPG, gold is also organized in a lattice structure, more specifically Au (111) which is a cubic
close-packed structure. The (111) is the Miller Index which is used to describe the main c
Abstract
Calorimetric methods have long provided insight into both the intermolecular forces at and
between the multitudinous phases of specialized materials. These were our findings for the following
Appendix:
J
J
H ( ) S (
)
g
gK
167.9
.4993
N/A
N/A
Figure 1: Polymer DSC curves of (top to bottom)
a) PEG with a first order melt requiring a latent heat of a heat rate integrated over temperature rat
Results and Discussion:
The polymers under scrutiny were shard-like PEG and viscous PPG at ambient conditions. The
transitions of PEG only had a MP and no GT, therefore, it must have been highly cryst
Practice Exam 1
R = 8.314 J/(K mol), 1bar = 105 Pa, 1 L =10-3 m3
1. True/False. Classify the statements below as either True or False (No explanation required).
(a) If you know the pressure, temperatu
Basic Mathematical Relations
n
⎛ 1⎞
e = lim⎜1 + ⎟ ≈ 2.718
n→∞
⎝ n⎠
Log and power
x
,
y
ln x + ln y + L = ln xy L ,
ln x − ln y = ln
log c b
,
log c a
log x = log10 x ,
ln x = log e x
a x / a y = a x−
Solutions for the Practice Exam 3
Problem 1. (a) Chemical potentials are idential to make the total Gibbs free energy minimum. : True (b) 2 ( NO2(g) = (N2O4(g): False (c) Liquid droplets form spheres
Solutions for the PracticeEx 1
1. (a) You only need two variables out of P,V and T to define a state of a gas: True (b) The energy of ideal gas remains constant : False (c) wrev > wirrev: True (d) Ent
Problem Set 4: Due by Oct. 30 before class
Problem 1. One mole of ideal gas is compressed isothermally from 1 to 5 bar at 100 C. (a) What is the Gibbs energy change, G? (b) What would have been the Gi
Problem Set 3: Due by Oct. 16 in class
Problem 1. Two blocks of the same metal and same size are at different temperatures T1 and T2. Each blocks heat capacity at a constant pressure is CP. These bloc
Happy Molecule Website
http:/www.chem.uci.edu/undergrad/applets/happy/happy.htm
DNA Origami
Design by Calculation!
Rothemund, Nature (2006)
DNA Origami
Rothemund, Nature (2006)
Also 3D version, Zheng