Physics 1401
Motion in 2 Dimensions
Part I Falling Bodies
Objective:
Understand, analyze and solve problems with Motion in Two Dimensions
Materials:
(1) Pasco Scientific Ballistic Pendulum ME-6831
(1)
Equation Sheet for Exam 3
For this exam, always assume: g = 10 m/s2
= 3.14
sin 0 = cos = sin = cos 3 = 0;
2
2
cos 0 = sin = 1;
2
1
sin 30 = sin = 2 ; cos 30 = cos =
6
6
sin 45 = sin =
4
sin 60 =
Equation Sheet for Exam 2
On this exam, always assume g = 10 m/s2 .
= 3.14; arc length s = r; circumference of a circle C = 2r; 1 rev = 2 rad
Potential energy: UAB = WAB . Work-energy theorem: Wnet
l.
j,
For the usual unit vectors i,
and,t, which point in the -r, y, and z-directions,
respectively, which of the following equations is correct?
A) i".i =s
B) i*) =-j"i
C) i"i =-i"i
,vf
FCR AI$Y
fruO
I
. A massive
disk with rotational inertia 1= 5.0 kg . *' is initially rotating with angular
velocity (Do =20rad/s. Then, a constant torque is applied for a period of 4.0 s, causing
the disk to stop r
1. An object is launched from ground level at an angle 0 : 30 degrees with respect to
ak f * *
2.
(+r)
| 'tfq* r#
,d
_
= voG*rB ?cfw_t
j
S)
;> t* " ffi*9= r$*KXg$ * ro s
$*
lf
gY6tuLg
u.
01ffi#i,
u"*8
l.
A ball with mass m = 2.0 kg is connected by a string to a fixed point on the ceiling.
The ball moves with
illustrated in the figure. / The length of the string is Z : 0.50 m and the angle 0 between
Name (Print) : _Name (Signature) : _
Student ID #: _
Physics 1321
Exam III Spring 2013
Chapters 11-15
Bubble in your name, Seven Digit MyUH ID# and your answers on the scantron sheet. USE
A #2 PENCIL.
PHYS 211 Final Exam
Spring 2014
Sample 2 Solutions
1) A waiter is in an elevator, holding a stack of dishes. As observed by someone
standing still on the ground floor, watching the elevator move down
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An abstrac
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s
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2 (5.75 N) (0.812 m)
=
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0.0004 kg m2
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before
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Consider t
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1
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which makes the ball osc
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When a sou
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A river fl
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Why is the
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001 (part 1 of 2) 10.0 point
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Equation Sheet for Exam 1
sin2 + cos2 = 1
sin 0 = cos = sin = cos 3 = 0;
2
2
sin 30 =
sin 45 =
sin 60 =
1
2 = 0.500;
2
2 = 0.707;
3
2 = 0.866;
cos 0 = sin = 1;
2
cos 45 =
3
2
2
2
cos 60 =
1
2
cos