patel (kvp267) HW01 ben-zvi (54740)
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001
10.0 points
Find the derivative of f when
f (x) =
1. f (x) =
Find the value
patel (kvp267) HW09 ben-zvi (54740)
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001
Consequently
I = 4 1
10.0 points
Evaluate the integral
2
2 x1
I =
dx .
x
1
patel (kvp267) HW08 ben-zvi (54740)
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001
10.0 points
1
Consequently,
1
2
sin 6t +
sin 12t + C
3
12
I = 3t +
with C a
patel (kvp267) HW07 ben-zvi (54740)
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1
e
3. I = ln 2 1
4 ln x
dx.
x5
I=
1
4. I =
5
1
1+ 4
4
e
2. I =
1
(ln 2 + 1)
8
patel (kvp267) HW06 ben-zvi (54740)
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2. I =
1
1
52
2
1
7 5
2
4. I = 5 2 correct
3. I =
001
10.0 points
Evaluate th
patel (kvp267) HW05 ben-zvi (54740)
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001
6
4.
2
10.0 points
For which one of the following shaded regions is its are
patel (kvp267) HW04 ben-zvi (54740)
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001
Correct answer: 6.5.
Explanation:
By linearity,
10.0 points
1
Determine the
patel (kvp267) HW03 ben-zvi (54740)
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001
1
and x = xi , we see that
i
n
area = lim
n
4+
i=1
4i
n
4
4
.
n
10.0 points
patel (kvp267) HW02 ben-zvi (54740)
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001
10.0 points
Find all functions g such that
Find the most general antideriva
patel (kvp267) HW10 ben-zvi (54740)
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001
10.0 points
1
is the volume of the solid below the graph of
f having the re