ECE 5325/6325 Fall 2009: Homework 5(f) Solution
From the Lecture 11 notes: Frequency Shift Keying : Assume Ts > 1/fc , and show that these two are orthogonal. 1 (t) = 2 (t) = cos (2fc t), 0 t Ts 0, o.w. cos 2 fc + 0,
1 Ts
t , 0 t Ts o.w.
Solution: The int
ECE 5325/6325 Fall 2009: Homework 7(a-d) Solutions
7a: (i) For each subchannel, B/N bandwidth is used. (ii) For each subchannel R/N data rate is carried. Or, if QAM/PSK is used, the bit rate is log2 M B/N . (iii) The center frequency for 1+ the kth subcha
ECE 5325/6325 Fall 2009: Homework 8d Solutions
My answers for the required fade margin in dB for M independent Rayleigh fading channels is shown in the table. For selection combining, the result is from Figure 7.11 in the Rappaport book, from seeing where
Sheet1 What standards, frequencies, bands do I use for wireless communications? Note these answers are mine; you might use different devices and products. Standard Bands Channel BW (MHz) Cell phone (Verizon) CDMA 824-894, 1800-2000 MHz 2.5 =2*1.25 Cordles
ECE 5325/6325 Fall 2009: Homework 4(f) Solution
(4f) As shown in this gure, a WLAN signal arrives at a ground oor access point from a laptop (Pt=100 mW) on the 3rd oor, via scattering from a tree outside of the building. Neglecting wall/window losses, and
ECE 5325/6325 Fall 2009: Exam 1 Solutions
1. (25 pts total) Question 1 was dierent between the 6325 and 5325 exams (but all other questions were the same). For the other half who havent seen the questions, they are also included on this problem. First, th
ECE 5325/6325 Fall 2009: Exam 2 Solutions
1. (25 pts total) The total length of the direct path would be 2002 + 292 = 202 m. Because of the symmetry, the two distances to the knife edge are d1 = d2 = 101 m, and the height h = 29/2 = 14.5 m. Since fc = 45
ECE 6325/5325 Spring 2010: Exam 3 Solutions
1. (20 pts) (a) For d = [1, 0, 1], we need to nd d = cG. In this case d = [1, 0, 1, 1, 2, 1] mod 2 = [1, 0, 1, 1, 0, 1]. (b) The coded bits [1, 0, 1, 0, 0, 0] are received. We need to nd rS = [1, 2, 1] mod 2 = [
ECE 5325/6325 Fall 2009: Homework 3(d) Solution
(3d) Typical cell phones transmit 500mW maximum. BS receivers require -115 dBm of power. What is the maximum distance between a cell phone and base station that could work in an ideal case with matching base
ECE 5325/6325 Fall 2009: Homework 3(d) Solution
(3f) What is the approximate E-eld magnitude in the two-ray (ground reection) model from Section 4.6 for vertical polarization (i.e., when the reection coecient is 1, rather than -1)? What is the approximate
ECE 5325/6325 Fall 2009: Homework 4(a) Solution
(4a) Extend the GSM uplink example from the lecture 7 notes, and consider the GSM downlink, using the same system parameters with one dierence. The dierence is that the noise gure of a mobile receiver is 8 (
ECE 5325/6325 Fall 2009: Homework 4(b) Solution
(4b) For the sensor network example from the lecture 7 notes, what would the range be if the fade margin was zero? In that case, how would the range increase if we used a better RFIC that had a sensitivity o