mendoza (cm57837) Graphs Vert Motion campbell (20100)
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before answering.
001 (part 1 of 2) 10.0 points
The tallest volcano in the so
001 10.0 points
A ball is thrown straight up from ground level.
After a time 6 s, it passes a height of 31.2 m.
What was its initial speed? The acceleration due to gravity is 9.8 m/s2 .
Correct answer: 34.6 m/s.
Explanation:
m/
11
Building
This print-out
mendoza (cm57837) Dynamics intro campbell (20100)
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1
T
a
T
a
001 (part 1 of 4) 10.0 points
A 89 kg man stands on a
mendoza (cm57837) MIdterm 2 Review campbell (20100)
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001 (part 1 of 5) 10.0 points
A crate is pulled up a rough in
mendoza (cm57837) Angular Momentum campbell (20100)
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001 10.0 points
A solid cylinder of mass M = 32 kg, radius
R =
mendoza (cm57837) 2D Motion campbell (20100)
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001 10.0 points
~ B,
~ and C
~ have the following
Three vectors A,
x
mendoza (cm57837) Momentum Intro campbell (20100)
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001 10.0 points
Use 5.98 1024 kg as the mass of the Earth.
A 28
mendoza (cm57837) Kinematics Intro campbell (20100)
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001 (part 1 of 3) 10.0 points
The position of a car coasting
mendoza (cm57837) Work NRG campbell (20100)
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001 (part 1 of 2) 10.0 points
A mechanic pushes a 1900 kg car from re
mendoza (cm57837) Rotational Dynamics campbell (20100)
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001 10.0 points
A bicycle tire of radius 0.32 m and mass 1.
mendoza (cm57837) Friction campbell (20100)
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001 10.0 points
A(n) 4.47 kg block is pushed along the ceiling
with a
mendoza (cm57837) Static Equilibrium campbell (20100)
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001 10.0 points
The system shown in the figure is in equilib
mendoza (cm57837) Momentum campbell (20100)
(m1 + m2 ) v
m1
r
(m1 + m2 ) x
g
=
m1
2 y
s
9.8 m/s2
(6 g + 110 g) (2.5 m)
=
6g
2(1.5 m)
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mendoza (cm57837) NRG in Rotation campbell (20100)
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001 10.0 points
The hour and minute hands of a tower clock
like
mendoza (cm57837) Grav Pot NRG campbell (20100)
1
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2 G ME
1
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1
=
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h
RE
1+
before answering.
RE
G ME
h
=2
001 10.0 points
2
h
RE
1+
mendoza (cm57837) Work intro campbell (20100)
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001 (part 1 of 2) 10.0 points
A 16.4 kg block is dragged over a rou
mendoza (cm57837) Rotation Intro campbell (20100)
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001 (part 1 of 2) 10.0 points
A dentists drill starts from rest.
mendoza (cm57837) Oscillation examples campbell (20100)
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001 (part 1 of 3) 10.0 points
A 363 g mass is connected to
mendoza (cm57837) Circular motion campbell (20100)
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001 (part 1 of 2) 10.0 points
An air puck of mass 0.034 kg is t
Names:
Pre-lab 3 Worksheet
1st Circuit: A Charging RC Circuit
Paste oscilloscope trace
of charging capacitor
here
Questions for 1st circuit:
Q1: For the RC circuit you built, what is the value of
the equation
V(t) Vo (1- e
t
Vo
in
?
RC )
Q2: From the know
Names:
Pre-lab 2 Worksheet
st
1 Circuit:
Paste
Questions for the 1st Circuit:
Q1: Compare the voltage differences across the 100 and the 220
resistors.
Q2: What can you say about the sum of the voltage differences
across the two resistors?
Q3: What can yo
EGR 241 Statics - Fall 2013
Dr. Matthew Rickard, Associate Professor
CBU College of Engineering
Sydney Harbor Bridge
http:/www.travlang.com/
Dr. Matthew Rickard
Associate Professor, CBU College of Engineering
BS, MS, PhD from UC Irvine in Mech & Aero Eng
Lenzs Law
There is an induced current in a closed, conducting loop if and
only if the magnetic flux through the loop is changing. The
direction of the induced current is such that the induced
magnetic field opposes the change in the flux.
i.e.
Changing ma
Electric Motor Rectangular Current Loop in a
Uniform Magnetic Field
Total Force on Loop = sum of Forces on each side
(
FB = I L ! B
)
FB = F1 + F2 + F3 + F4
"
"
two sides parallel (1 and 3) to field
and two perpendicular (2 and 4) to the field"
Electric M
Example 23.1
A flat loop of wire consisting of a single turn with area
8.00 cm2 is placed perpendicular to a magnetic field. The field
strength is uniformly increased from 0.500 T to 2.500 T in
1.00 s.
a.) What is the emf induced in the loop?
b.) If the c
Ampere s Law
More useful than Biot-Savart for cases of constant current
and regular geometry (symmetry)
! B ds =
0
I Through
- Integral is around a closed path (loop)
- Ithro is the total current passing through the loop
- 0 is the permeability of free s
Magnetic Force FB
Magnetic force on a moving charged particle is:
FB = q v ! B
where
q = electric charge
v = velocity
B = magnetic field
Units: Tesla (T)
1T = 1 N s C-1 m-1
Maximum and Minimum Force Values
FB = 0 (minimum) when
Sin = 0 = 0o or 180o
i.e.
B
Problem Solving Guide Network Analysis using
Kirchoffs Laws
1.) Draw circuit and label with all known quantities.
2.) Assign branch currents (if not already known).
3.) Apply the Junction Law to the junctions where
the branches meet.
4.) Apply the Loop La