Assignment 2 (100%)
Solve the following problems neatly. Use Nodal Analysis only
1) For the circuit shown in figure 1, determine the node voltages using nodal analysis (15%)
6V
R2
V1
R3
V2
1k
V3
1k
R4
2k
R1
1k
12 V
Figure 1
Node A:
V 1 V 2
1k
+
V 1 0
1k
=
EET310 Circuit Analysis
Instructor:
Unit-4 Lab
ECPI University
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Running head: Nodal Analysis Experiment Lab
1
Nodal Analysis Experiment Lab
EET 310
Circuit Analysis
Mr. Livingston
Britney Oates
ECPI University
February 4, 2017
Signed: Britney Oates
The Honor Pledge States:
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EET 310 Circuit Analysis
Unit 5 Final Exam Practical
By: Joseph Leeman
Instructor: Dr. Setodehnia
Online EET Department
ECPI University
Date: 17 July 2016
The Honor Pledge States:
I pledge to support the Honor System of ECPI. I will refrain from any form
Unit3PracticeQuiz
See Figure 8.3. If the 2 resistor short circuits,
what would happen to the voltage across the 10
resistor?
Select one:
a. The voltage would increase.
b. The voltage would drop to zero.
c. The voltage would decrease.
d. The voltage woul
Assignment 3 ( 100%)
Solve the following problems neatly. Use mesh Analysis only
1) For the circuit shown in figure 1, determine the mesh currents using mesh analysis and
determine the branch current i (20%)
Figure 1
(1): 10(I1) 6 + 2(I1 I2) = 0
(2): 2(I2
EET310
Unit 5 Review
Joseph Leeman
Self-Test
1. In applying the superposition theorem,
(a) all sources are considered simultaneously
(b) all voltage sources are considered simultaneously
(c) the sources are considered one at a time with all others replace
EET 310 Circuit Analysis
Unit 1 Lab Superposition
By: Joseph Leeman
Instructor: Dr. Setodehnia
Online EET Department
ECPI University
Date: 12 June 2016
The Honor Pledge States:
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EET 310 Circuit Analysis
Unit 4 Lab Superposition
By: Joseph Leeman
Instructor: Dr. Setodehnia
Online EET Department
ECPI University
Date: 3 July 2016
The Honor Pledge States:
I pledge to support the Honor System of ECPI. I will refrain from any form of a
EET 310 Circuit Analysis
Unit 2 Lab Superposition
By: Joseph Leeman
Instructor: Dr. Setodehnia
Online EET Department
ECPI University
Date: 18 June 2016
The Honor Pledge States:
I pledge to support the Honor System of ECPI. I will refrain from any form of
EET 310 Circuit Analysis
Unit 3 Lab Superposition
By: Joseph Leeman
Instructor: Dr. Setodehnia
Online EET Department
ECPI University
Date: 26 June 2016
The Honor Pledge States:
I pledge to support the Honor System of ECPI. I will refrain from any form of
Keni El Bey
EET310: Circuit Analysis
Unit 2 Assignment 1
4/4/2016
Self-test
6. C
The Thevenin equivalent form of any two-terminal resistive circuit consists of an equivalent voltage
source (VTH) and an equivalent resistance (RTH), arranged as shown in Fig
Running Header: EET310 Unit I Lab Assignment
EET310: Circuit Analysis
Instructor: Dr. Setoodehnia
Unit 1 Lab Experiment
By: Keni El Bey
4/2/2016
ECPIs Honor Pledge: I pledge to support the Honor System of ECPI. I will refrain from any form
of academic dis
EET310 Circuit Analysis
Instructor:
Unit-1 Lab
ECPI University
ECPIs Honor Pledge: I pledge to support the Honor System of ECPI. I will refrain from any
form of academic dishonesty or deception, such as cheating or plagiarism. I am aware that as a
member
Self-Test
6. Thevenins theorem converts a circuit to an equivalent form consisting of
(a) a current source and a series resistance
(b) a voltage source and a parallel resistance
(c) a voltage source and a series resistance
(d) a current source and a paral
EET310 Circuit Analysis
Instructor:
Unit-3 Lab
ECPI University
ECPIs Honor Pledge: I pledge to support the Honor System of ECPI. I will refrain from any
form of academic dishonesty or deception, such as cheating or plagiarism. I am aware that as a
member
EET310 Circuit Analysis
Instructor:
Unit-2 Lab
ECPI University
ECPIs Honor Pledge: I pledge to support the Honor System of ECPI. I will refrain from any
form of academic dishonesty or deception, such as cheating or plagiarism. I am aware that as a
member
Self-Test
1)
2)
3)
4)
5)
6)
E
D
B
C
C
B
Problems
2)
a) 0
b) 45
c) 18
d) 500
4)
a) -94
b) 2.503
10) I1 = 1.235, I2 = 2.053, I3 = 1.88
11)
8.2 I 1+10 I 212=0 , 10 I 2+5.6 I 36=0
12) I1 = 0.6927A, I2 = 0.633A, I3 = -0.0597A
13) VR1 = I1*R1, VR2 = I2R2, VR3 =