The state of stress for a material is shown on the element
a. Find the Fs by the maximum shear theory of failure if the material has yp = 400 MPa.
b. Find the Fs Mises-Henky Theory.
c. Find the Fs if the material is brittle having ult = 200 MPa and ul
HW 10 Solution
1) Find the value of the maximum stress in the weld in the fig below. Assume the direct stress to be
uniformly distributed over the throat area.
Left area = 0.707
Right area = 0.707
6 1.591in 2
6 1.061in 2
Total area A = 2.652 i
93) An is acted upon by the following stresses:
= 1,500 , = 22,500 , = 10,000
a. By means of equations compute the stresses on the sides of an element oriented 30
clockwise with the x-axis.
b. Find the value of for the maximum and minimum nor
5. A shaft is loaded by a torque of 40,000 in. 1b. The material has a yield point of 50,000 psi. F5 is equal to 2.
(21) Find the required diameter by the maximum shear theory.
(b) Find the required diameter by the von MisesHencky theory.
Solution: The she
HW 11 Solutions
Find the resultant force on each rivet of the joint in the figure below.
C N1r12 N 2r22 Pe
C 37.52 37.52 18,000 3705
C 240n / mm
Moment force, F 240 37.5 9,000N
Upward on left rivet and downward on right rivet.
Direct force F
MET 320: Homework 10
9 April 2016
Chapter 7, Problem 1:
The value of the maximum stress in the weld in
the fig below.
Assume the direct stress to be uniformly
distributed over the throat area.
= 2H + 2V 1=
A =( w 1)
MET 320: Homework6
27 February 2016
Chapter 2, Problem 5:
Shaft is loaded by torque of 40,000 in lb
Material has yield point of 50,000 psi
Safety Factor of 2
Find the required diameter by the maximum
shear theory; Find the requi
MET 320: Homework5
19 April 2016
Chapter 7, Problem 16:
Find the resultant force on each rivet of the joint
in the figure below.
F D = F M 1=C r 1 Pe=C ( r 1 +r 2 ) F M 2=C r 2
=9,000 N ( 18000
MET 320: Homework3
30 January 2016
Chapter 1, Problem 32:
Find the deflection of the end A of the beam.
b h3 dy
= C y c = C y cslope =l A C
12 d x atC 2 EI
d x atC
y Amoment =
HW 9 Solution
1) A shaft carries a steady torque of 30,000 in.lb at a shearing stress of 8,000 psi. What is the
diameter of the shaft?
3) Suppose it is specified that the deflection at the center of a simply supported shaft under its
own weight should not
The force should be moved to the shaft, it will be moved by a force equal in magnitude and acting in the
same direction and a torque equal to the force times the distance moved.
= 1 + 2 = 1000 12 = 12,000 # . . (1)
1 1 =
Find the reactions and also the value of the bending stress at a point 5 ft. from the left end of
Compute the values of the transverse shear stress at points 25, 50, 75 and 100 mm below the
top surface of the beam for cross sections to t
51. Determine the width of the flange b of the offset link if the permissible value of the working stress
is 8,000 psi
A = 3 + 2 (b ) = 1+b in2
Moment of inertia:
( )( )
1 1 5 2
= 12 ( 2) +
MET 320: Homework1
16 January 2016
Chapter 1, Problem 2:
The value of the distance, x, if the lower member
is to be horizontal.
F st =
A st = st st = st
A st E st
A al =
A al E