3-6
a) P = P + P*i*n
2 = 1 + 0.03*n
n = 1/0.03 = 33.3 years
b) 2P = P(1+ 0.03)n
2 = 1.03n
ln(2) = n*ln(1.03)
n = ln(2)/ln(1.03) = 23.45 years
3-13
Given two cash flows that are equivalent if the interest rate is i. Which one is more
valuable if the intere
The basic cost of production can be expressed as:
Cost = Regular Time Production Cost + Overtime Production Cost
Regular time production cost = 90 units/hr
Overtime production = 90*(0.95) = 85.5 units/hr
So, the hour required to produce the specified numb
The car can be driven: 28 mpg*16 gal = 448 miles
Three options exist:
1. Return it with a full gas tank. So we must pay for gas to fill it up at market rate of
$3.95/gallon.
2. Return it without filling it and pay $5.45/gallon. So company fills the tank a
CE 431-Structural Steel Design
Set: 2016.02.18
Homework 6
Due: 2016.02.26
Problem 1
A W1245 column is pinned at the top and bottom and has no intermediate supports. On a single
graph, plot the following curves for this column:
a) vs. for = 36
b) vs. for
CE 431-Structural Steel Design
Set: 2016.03.04
Homework 8
Due: 2016.03.11
Problem 1
Compute , , and the shape factor, k, about the horizontal axis (x-axis) for the sections
shown below.
Problem 2
The W2162 beam shown below is provided with adequate latera
CE 431-Structural Steel Design
Set: 2016.02.04
Homework 3
Due: 2016.02.11
Problem 1
a) Determine the LRFD design tensile strength for the member and bearing-type connections
using:
a. A36 steel plates and A490 -in. bolts with threads excluded from the she
CE 431-Structural Steel Design
Set: 2016.02.11
Homework 5
Due: 2016.02.18
Problem 1
A 1/4-in llet weld is used to connect the members shown below. Determine the LRFD design
load that can be applied to this connection, including the plates, using the AISC
CE 431-Structural Steel Design
Set: 2016.01.28
Homework 3
Due: 2016.02.04
Problem 1
Determine the LRFD design strength of a double angle, L7x7x3/4 in with two gage line in its long
leg and one in its short leg, 7/8 in. dia. bolts as shown below. Standard
CE 431-Structural Steel Design
Set: 2016.01.20
Homework 2
Due: 2016.01.27
Problem 1
Axial forces in a column due to service loads are as follows:
Dead:
500 k compression
Live:
400 k compression
Roof live: 50 k compression
Snow:
35 k compression
Wind:
200
Homework 5 Solutions - Welded Connections
Problem 1
A 1/4-in fillet weld is used to connect the members shown below. Determine the LRFD design load that
can be applied to this connection, including the plates, using the AISC Specification.
(a) If A36 stee
Homework 3 Solutions - Analysis of Tension Members
Problem 1
Determine the effective net area of the W16 40 shown below. Assume the holes are for 43 -in bolts.
W16 40 (AISC Table1-1 pg 1-22) : Ag = 11.8 in2 , bf = 7.00 in, tf = 0.505 in
WT8 20 (AISC Table
Homework 6 Solutions - Compression Members
1
Problem 1
A W1245 column is pinned at the top and bottom and has no intermediate supports.
On a single graph, plot the following curves for this column:
(a) Pn vs. L for Fy = 36ksi
(b) Pn vs. L for Fy = 50ksi
(
CE 442, Spring 16, HW 2
Homework 2
(Due Feb 5, 2016, Friday)
1. Find the effluent concentrations from a plug flow reactor (PFR) and a CSTR, each treating the same
pollutant and each with a detention time of 60 minutes. The pollutant undergoes a first orde
Chapter 18: Accounting and Engineering Economy
18-1 Engineers and managers make better decisions when they understand the "dollar" impact of their decisions. Accounting principles guide the reporting of cash flows for the firm. Engineers and managers can
Chapter 16: Economic Analysis in the Public Sector
16-1 Public decision-making involves the use of public money and resources to fund public projects. Often there are those who are advocating for particular projects, those who oppose projects, those who w
Chapter 15: Selection of a Minimum Attractive Rate of Return
15-1 The interest rates on these securities vary greatly over time, making it impossible to predict rates. Three factors that distinguish the securities: Municipal Bond Corporate Bond Bond Durat
Chapter 14: Inflation and Price Change
14-1 During times of inflation, the purchasing power of a monetary unit is reduced. In this way the currency itself is less valuable on a per unit basis. In the USA, what this means is that during inflationary times
Chapter 13: Replacement Analysis
13-1 For the Replacement Analysis Decision Map, the appropriate analysis method is a function of the cash flows and assumptions made regarding the defender and challenger assets. Thus, the answer would be the last it depen
Chapter 12: After-Tax Cash Flows
12-1
(a) Federal Taxes On the first $35,000 From $35,000 to $70,000 16% 22% $5,600.00 $5,940.00 $11,540.00 Federal taxes=$11,540 $1,280.00 $10,260.00
Taxable income $62,000 Non-refundable tax credit=$8,000 16%= Federal tax
Chapter 10: Uncertainty in Future Events
10-1 (a) Some reasons why a pole might be removed from useful service: 1. The pole has deteriorated and can no longer perform its function of safely supporting the telephone lines 2. The telephone lines are removed
Appendix 7A: Difficulties Solving for An Interest Rate
7A-1 Year 0 1-9 10 11-19 Cash Flow +$4,000 +$4,000 -$71,000 +$4,000
There are 2 sign changes in the cash flow indicating there may be 2, 1, or zero positive interest rates. At i = 0% At i = % NPW= +$5
Chapter 6: Annual Cash Flow Analysis
6-1
$45 $60
$15
$30
C
C
C
C = $15 + $15 (A/G, 10%, 4) = $15 + $15 (1.381) = $35.72
6-2
B B B B
$10
$10
B = [$100 + $100 (F/P, 15%, 4)] (A/F, 15%, 5) = [$100 + $100 (1.749)] (0.1483) = $40.77
6-3
$60 $45
$30
$15
E
E
E
E