Solution for Chapter 14
(compiled by Nate Bode, solutions by credited authors)
February 12, 2009
A
13.10 Winds and ocean currents in the north Atlantic [by unknown]
(a) The balance of the friction of the wind with the ocean and the Coriolis
force builds a
Solution 11
12.8: Free-energy analysis of buckling instability [by Dan Grin]
(a) From Eq. (10.23) in the course notes, we know that the total elastic energy
is
1
2
E (x,x ) dxdydz.
2
E=
(1)
2
d
From Eq. (10.77) in the notes we know that x,x z dx and from
Ph 136: Solution 5 for Chapter 5 and 6
5.5 Electron-Positron Equilibrium at Low Temperatures [by Xinkai
Wu], [modied by Kip Thorne and Dan Grin]
(a) The reaction equation e + p e + p + e + e+ gives e + p =
2e + p + e+ , which implies e + e+ = 0, i.e.
e =
Ph 136: Solution 4 for Chapter 4 and 5
5.3 Grand Canonical Ensemble for Ideal Relativistic Gas [by Alexei
Dvoretskii, edited by Georey Lovelace]
(a) Suppose there are N identical particles in the volume. Since the gas
is in a classical regime, the average
Ph 136: Solution 3 for Chapter 3
3.14 Solar Heating of the Earth: The Greenhouse Eect [by Alexander
Putilin]
(a) The energy per unit time per unit frequency emitted by the surface
element dA of the sun into the solid angle d centered around unit vector n
Ph 136: Solution for Chapter 2
3.6 Observations of Cosmic Microwave Radiation from a Moving Earth
[by Alexander Putilin]
(a)
h4 3
N
c2
2
gs
N = 3 = 3 (f or photons)
h
h
2h 3
(2h/c2 ) 3
= I = 2 = h/kT
0 1
c
e
in its mean rest f rame.
I =
let x = h/kT0 ,
I