Physics 1c Practical, Spring 2015
HW 1 Solutions
April 2, 2015
1
Serway 30.7 (5 points)
By superposition, it is trivial to see that the eld at the center of the loop is equal to the eld at the
center due to the loop plus the eld at the center of the loop
Physics 1c Practical, Spring 2015
Hw 3 Solutions
April 16, 2015
1
Serway 31.79 (5 points)
By Lenzs Law, current will ow in each of the two sub-loops to oppose the change in ux. One
can easily see then, that the left sub-loop will have counterclockwise cur
Physics 1c Practical, Spring 2015
Homework 4 Solutions
April, 2015
32.27 (5 points)
(a) (2.5 points)
From Kirchhos Law, we can write down the ODE for current I(t):
RI + L
dI
=E
dt
(1)
The solution is
I(t) =
E
+ C1 e
R
R
Lt
(2)
The constant of integration
Physics 1c Practical, Spring 2015
Homework 2 Solutions
April 12, 2015
31.11 (5 points)
(a) (2 points)
At the end of the solenoid, the magnetic eld B produced by the solenoid is
1
0 nI
2
(1)
d
d
d 1
1
2
2
2 dI
= (r2 B) = ( 0 nr2 I) = 0 nr2
dt
dt
dt 2
2
dt
Physics 1c Practical, Spring 2015
Quiz 1 Solutions
April 20, 2015
1
(a)
(10 points)
(2 points)
The magnitude of the magnetic eld due to the long straight wire is B = 0 I for a point a per2r
pindicular distance r from the wire. If we consider the magnetic