The Land Ethic
When god-like Odysseus returned from the wars in Troy, he hanged
all on one rope a dozen slave-girls of his household whom he
suspected of misbehavior during his absence.
This hanging involved no question of propriety. The girls
were proper
In Aldo Leopolds Sand County Almanac, he shares his unique views of nature and
environment. Inside the book are his ideas defining nature and its preservation and its ways of
life. The demeanor portrays a Zen-like understanding of how the environment work
Alternative 2 is the city of Waukeshas proposal of obtaining potable drinking water from Lake
Michigan. The project is estimated at $207 million, with other alternatives ranging in capital
costs of $160 to $377 million, making the Lake Michigan with retur
Ryan Neiheisel
Lab 6
1)
a. (4*y)+x)/(5*x)
ans = 0.8588
b. 5/(y-(1/x^(5)
ans = 1.1906
c. 3*pi*x^(2)
ans = 245.1385
d. 3*(6*x-7)/(8*y)-5)
ans = 2.4755
2)
a. x=(a+b)/(b+d)+(d-c)/(d^(2)+(d+c)/(e^(3)
x = 1.9737
b. s=(b-c+f)/(a+b-c+d)
s = 5.9091
c. r=1/(1/a)+(1
Homework 3
1. A.) The probability that the strength is less than or equal to 5,000 psi is .85 or 85%. If you
look at the probability of P(Fc>5,000) being .15 which I look at on a scale of 1.00 and
minus 1.00 from .15 to get the probability of the strength
Ryan Neiheisel
Civil Engineering 280 401
October 12, 2016
Homework 4
1.) a. To find the probability of P(X<=1) with the probability mass function I took all the x values within [0,1]. This adds up to be
0.066. therefore, the probability that the values ar
CE 280 Computer-based Engineering Analysis
Homework 2
Due by 5 PM, Wednesday, September 28, 2016
Point values are shown in brackets. Show your work. Explain any assumptions you make.
1. [16] Among the cast aluminum parts manufactured on a certain day, 80%
1. [20] Solve Textbook Problem 2-8
Standard Deviation of the high dose patients is 45.7. The sample mean of the high dose patients
is 50.9. The Dot Diagram of the high dose patients is,
High Dose Patients Spread on a Dot Diagram
0
20
40
60
80
100
120
140
Ryan Neiheisel
Assignment 5
1)
Variable
X
N
16
For the mean I did
Mean
24.99
Xi
n
SE Mean
0.159
StDev
96.79
Sum
399.851
= xx, so, 399.851/16 = 24.99
X
( i X )
For StDev I did
n1
S 2=
, so, (399.851-24.99) /(16-1) =
2
9368.05^(1/2)=96.79
2)
a. Zc=(X-mean)