Homework 11
P9.1.9
ffw(t)
Given a full-wave rectified waveform of
A1
period T , as shown in Figure 9.4.1b,
A2
except that because of dissymmetry in
the rectifier circuit, the half-sinusoids
are not all of the same amplitude but
t
-T
-T/2
T/2
T
alternate w
AMERICAN UNIVERSITY OF BEIRUT
ELECTRICAL AND COMPUTER ENGINEERING DEPARTMENT
_
EECE 210
Electric Circuits
Fall 2006-2007
QUIZ I- Solution
Problem 1 (4 points)
Find the equivalent resistance between terminals a and b for the circuit shown below
a
b
Answer:
Basic Concepts in Circuit Analysis
Nassir H. Sabah
EECE 210
Fall Semester 2014
Contents
Page
Chapter 1
Preliminaries to Circuit Analysis
Objective and Overview
1-1
1.1
What are electric circuits and what are they used for?
1-1
1.2
What laws govern the beh
Chapter 6
Circuit Equations
Objective and Overview
The Chapter presents the systematic methods for analyzing circuits, namely,
the node-voltage and mesh-current methods and discusses some of their variations.
Kirchhoffs laws and Ohms law provide the numbe
Chapter 9
Linear Transformer
Objective and Overview
The chapter introduces magnetic coupling between coils, whereby a timevarying magnetic field of a current-carrying coil induces a voltage in a nearby coil.
Magnetic coupling is the basis for transformer
Chapter 9
Linear Transformer
Objective and Overview
The chapter introduces magnetic coupling between coils, whereby a timevarying magnetic field of a current-carrying coil induces a voltage in a nearby coil.
Magnetic coupling is the basis for transformer
Chapter 11 Basic Responses of First-Order Circuits
Objective and Overview
The chapter examines the natural responses of RC and RL circuits, as well as
their responses when connected to dc sources, and formulates a general procedure
for deriving the respon
Chapter 1
Preliminaries to Circuit Analysis
Objective and Overview
The chapter introduces some basic notions on electric circuits before
embarking on circuit analysis in the following chapters.
The chapter begins by explaining what electric circuits are,
Chapter 3
Circuit Equivalence
Objective and Overview
The Chapter introduces the very fundamental concept of circuit equivalence
and applies it in a number of cases.
Circuit equivalence is ubiquitous in circuit analysis because of its usefulness,
although
Chapter 5
Circuit Simplification
Objective and Overview
This Chapter is concerned with various procedures and techniques that
simplify circuit analysis, either by reducing a given circuit to a simpler form or by
following certain methodologies that facili
AMERICAN UNIVERSITY OF BEIRUT
Department of Electrical and Computer Engineering
EECE210 Fall 2004
Quiz 1, November 5, 2004
Prof Karameh
Directions:
- You will have 1.5 hrs for this quiz.
- Write down your name in ink on all the pages. DO IT NOW!
- Answers
AMERICAN UNIVERSITY OF BEIRUT
Department of Electrical and Computer Engineering
EECE210 Fall 2005
Quiz 1, November 1, 2005
Prof Karameh
Directions:
- You will have 1.5 hrs for this quiz.
- No programmable calculators are allowed.
- Write down your name in
EECE 210 Final Exam fall 2009/2010 Sections 1, 3 and 4
Closed Book Three Hours
3%
1. Determine the power dissipated in the circuit, assuming I = 1 A.
Solution: The 1 Y is paralleled with a 3 , so that it effectively becomes a 0.5 Y, and
the circuit reduce
Final Exam 2010-2011
3%
10
5IX
_
+
1. Determine IX, assuming ISRC = 1 A
5
(Hint: write one KVL equation and
one KCL equation).
10 V
_
+
IX
A. 4 A
10
ISRC
12
15
B. 2 A
C. 3 A
D. 1 A
E. 5 A
Solution: Let the current through the 10 resistor be IY. From K
EECE 210
Quiz 2 Nov 20, 2010
4%
1. The current components in a resistor R, as found from superposition, are -8 A and +4 A.
Determine the power dissipated in the resistor if R = 2 .
Solution: The magnitude of the current through R is 4 A. The power dissipa
Quiz 3 December 18, 2010
4%
1. A current i = Imcos(t + 30) flows through an impedance (5 j5) . Determine the rms
phasor voltage across the impedance if Im = 2.5 A.
Solution: The phasor current is Im30 A. The impedance is 5 2 45 o . The phasor
voltage is 5
Problem (12 pts)
Consider the circuit shown
j3
4
a
I
150 A
rms
2
0.5I
-j 4
b
a. Determine the open-circuit voltage at terminals a and b. (3 pts)
15 = 1.5I; I = 10 A; VTh = 10(2 j 4) 5(4 j 3) = -j 55 V.
b. Determine the current flowing in the short circu
www.amal-aub.org
5. Find the vohage v, ( t) across the
a
b.
c.
d.
'
1.60cos(2f) V.
l.GOsin(t) V.
3.2ms(f) V.
2.26cos(t) V.
Nom of the above.
6. Two lnypsdances 2 , =9 . 8 - 78' B and 2, = 1 ~ 5 ~ 2 1 . fl, are connected in p d l d
~
8'
and the combinatIan
AMERICAN UNIVERSITY OF BEIRUT
Prof. R. Chedid FACULTY OF ENGINEERING
& ARCHITECTURE
Name'.
ID: .
(EECE 210) ELECTRIC CIRCUITS & ELECTRONICS
CLOSED BOOK (1 1/2 HRS)
Programmable Calculators are not allowed
Provide your answers on the computer’s card only
R
Chapter 4
Circuit Theorems
Objective and Overview
The Chapter presents some theorems that apply to electric circuits, and which
center primarily around Thevenins theorem.
Thevenins theorem takes circuit equivalence to its extreme, by representing
any LTI
Chapter 8
Sinusoidal Steady State
Objective and Overview
The chapter introduces phasor analysis, a powerful and very useful
methodology that extends to the sinusoidal steady state all the concepts, theorems,
and procedures applied to resistive circuits un
Homework 1
P1.1.7
Seven circuit
iA
interconnected
as shown in
Figure P1.1.7.
The assigned
iD + vD
iB vB +
B
elements are
iC
+
vA A
vC
D
F
iE
+
vE
C
vF + i
F
vG
E
+
iG
+
G
positive
directions of
Figure P1.1.7
voltage drops and
currents are
indicated. Base
Homework 4
P3.1.11
Determine VO in Figure
a
10 A
b
P3.1.11 using node-voltage
4
analysis. Do not transform the
2
voltage source. Consider that
the current entering node a
+
10 V
+
8
2
due to this source is
0.25(10 Va )
VO
4Ix
Ix
Figure P3.1.11
Solution P3
Homework 6
P5.1.6
Given the sinusoidal time function v of
v
10 ms
Figure P5.1.6. Express v as a function of
time and as a phasor.
3
20 V
t
Solution P5.1.6
v = 10cos(t+ ) V.
= 2/T = 2/(10*10-3) = 200.
At t = 0 , v = 3, so that cos() = 0.3, or, = 72.54.
As
Homework 3
P2.3.5
24
8
Determine VO by redrawing the
ladder network of Figure 2.3.5 as
+
a cascade of three voltage
40
+
20
160 V
40
10
dividers.
VO
Figure P2.3.5
Solution P2.3.5
8
20|(40 + 40) = 16 ; 10|(24 + 16) = 8 ;
hence Vac = 160
Vbc = 80
VO =
Homework 5
P4.1.13
Determine VO in Figure
10 A
a
P3.1.11 using TEC.
b
4
+
2
10 V
+
8
VO
2
4Ix
Ix
Figure P3.1.11
Solution P4.1.13
4
With the 8 removed, and the 10 V source acting
a
5Ix
alone as an independent source, the current in the
2
4 resistor is 5Ix.