Assignment#1Sol.nb
1
ME 406 Assignment #1 Solutions
PROBLEM 1 We define the function for Mathematica.
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(a) We use Plot to construct the plot.
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fHxL
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3
ME 406 ASSIGNMENT #1
PROBLEMS DUE IN CLASS THURSDAY JANUARY 22, 2009
This assignment is not typical of the assignments in this course. It has one specific purpose: to give you a crash course in Mathematica. Mathematica is the tool that we use in this cour
ME 406 ASSIGNMENT #6
PROBLEMS DUE IN CLASS ON THURSDAY MARCH 5, 2009 LECTURE SCHEDULE AND READING
Section in Class Notes I. PLANE AUTONOMOUS SYSTEMS 1.8 Case Study: van der Pol Oscillator 1.9 Searching for Periodic Solutions 1.10 Stability of Periodic Sol
ME 406 ASSIGNMENT #10
PROBLEMS DUE BY 6 PM FRIDAY APRIL 24 2009 LECTURE SCHEDULE AND READING
Section in Class Notes 2.4 Volume in Phase Space 2.5 Lorenz Equations Date Section in Text T Apr 14 -T, Th Apr 14,16 9.2, 9.3
PROBLEMS (Each problem is worth 25 p
ME 406 ASSIGNMENT #8
PROBLEMS DUE BY 6 PM ON FRIDAY APRIL 10, 2009 LECTURE SCHEDULE AND READING
Section in Class Notes II. HIGHER ORDER AUTONOMOUS SYSTEMS 2.1 Linear Systems Distinct Eigenvalues 2.2 Linear Systems Repeated Eigenvalues Date Section in Text
ME 406 ASSIGNMENT #2
PROBLEMS DUE IN CLASS THURSDAY JANUARY 29, 2009
This assignment has two objectives: (1) to give you practice using DynPac, and (2) to give you some experience with the basic concepts for two-dimensional systems.
LECTURE SCHEDULE AND R
Assignment#3Sol.nb
1
ME 406 Assignment # 3 Solutions
In[552]:=
sysid
Mathematica In[553]:= 6.0.3, DynPac 11.02, 2102009
plotreset; intreset;
Problem 1
The equations of the problem are dx dt = ay, dy dt = -x -2 y.
The eigenvalue equation is obtained in the
ME 406 Further Results for the Project: Analysis of Solution Near the Spiral Equilibrium for a = 0
1. Introduction
sysid; plotreset; intreset; imsize = 250;
Mathematica 6.0.3, DynPac 11.02, 4102009
In this notebook, we look at the solution of the project
ME 406 Assignment #4 Solutions
sysid
Mathematica 6.0.3, DynPac 11.01, 1302009
Problem 1
Part a
The right-hand sides at the origin are sin(0+0) = 0 and sin(0-0) =0, so (0,0) is an equilibrium. The righthand sides are sin(x + y) = x + y + (higher order te