Chapter 1: Overview
Chapter 1: Overview
In-Class Exercises
1.1. a 1.2. a) 4 b) 3 c) 5 d) 6 e) 2 1.3. e 1.4. a) 4th b) 2nd c) 3rd d) 1st
Multiple-Choice
1.1. c 1.2. c 1.3. d 1.4. b 1.5. a 1.6. b 1.7. b 1.8. c 1.9. c 1.10. b
Questions
1.11. (a) In Europe, g
Physic 231 Lecture 6
Main points of todays lecture: Newtons 3d Law Frictional forces: kinetic friction: f k = k N static friction f s < s N Examples.
Newtons Third Law
When a body exerts a force on another, the second body exerts an equal oppositely dir
Physic 231 Lecture 5
Main points of todays lecture: points of today lecture: Newtons 1st law: If there is no net force, the velocity of a mass remains constant (neither the magnitude nor the direction of the velocity changes). nd law: Newtons 2 F = ma m
Physic 231 Lecture 4
Main points of todays lecture: Example: addition of velocities Trajectories of objects in 2 dimensions: dimensions:
g = 9.8 m/s 2 downwards vy = vy 0 gt y y y0 = 1 (vy + vyo )t 2
1 y = vy0t gt2 2 v2 v20 = 2gy y y vx = vx0 x = vx0t
Co
Lecture 3
Some points of verticle motion:
g = 9.8 m/s 2 downwards v = v0 gt y y y0 = 1 (v + vo )t 2
1 y = v0t gt2 2 2 v2 v0 = 2gy
Here we assumed t0=0 and the y axis to be vertical. Vectors and components Addition of vectors
Graphical determination of d
Physic 231 Lecture 2
Main points of todays lecture x v ; t t t0 for constant acceleration: a a; assuming also t 0 t v v0 at x vt
0
v lim a
t0
x t
v ;v at t v a lim t 0 t
1 v vo t 2 12 x v0 t at 2 2 v2 v0 2a x x
x (mi) (mi)
-1
0
1
2
Suppose the man walks
Physics 231 Lecture 18 Lecture 18
Main points of todays lecture: Heat and heat capacity: Q cmT Work in thermodynamic processes: Wsystem PV First Law of Thermodynamics: U Q PV Processes cyclic: P V T 0 isobaric: P 0 isovolumetric: V 0 isothermal: T 0 adi
Physics 231 Lecture 17
Main points of todays lecture: points of today lecture: Viscous flow F Av d Poisseuilles law
V R 4 P P2 1 t 8L Temperature Thermal expansion L TL; A A0 T ;
V V0 T Ideal gas properties:
PV nRT Nk BT 2 N 1 2N 2 P m v KE 3 V 2 3V 3 KE
Physics 231 Lecture 16 231 Lecture 16
Main points of todays lecture: Bernoulis equation 1 Pf v 2 gy f f 2 12 P0 v0 gy0 2 Viscous flow
Av d Poisseuilles law V R 4 P P2 1 8L t F
Does the water level go up or down?
a) The water level goes up. b) The wate
Physic 231 Lecture 12
Main new points of todays lecture: Kinematic equations for circular motion:
= t
= 0 + t
=
1 1 ( + 0 ) = 2 ( + 0 ) t 2 1 2 = 0 t + t 2 2 = 0 + 2 2
Torque
= Fd ; d is the lever arm
Conceptual question
An astronaut floating weightl
Physic 231 Lecture 10
Main points of todays lecture: Elastic collisions in one dimension:
v1 f = v2 f =
(m1 m2 ) v
m1 + m2 m1 + m2
10 +
(m2 m1 ) v
2m2 v20 m1 + m2 2m1 v10 m1 + m2
20 +
Multiple impulses and rocket propulsion.
Fpropellant t = m vf m v0 m (
Physics 231 Lecture 9
Impulses: forces that last a short time Main points of this lect. p = mv Momentum: F t = p = mv = m v f v i Impulse-Momentum theorem: p tot,f p1,f + p 2,f = p1,i + p 2,i p tot,i Momentum conservation: v f = ( m1 v 1 + m 2 v 2 ) ( m
Physic 231 Lecture 7
Main points of todays lecture: Work:
F s
W = Fs cos( ) = Fx x
Kinetic energy:
12 KE = mv 2
Work-energy theorem:
Wtotal = KE f KE0
PE = PE f PE0 = mg ( y f y0 )
Conservation of energy Potential energy:
E = KE f + PE f = KE0 + PE0
Ex
Physic 231 Lecture 8
Main points of todays lecture: Potential energy of spring
PE =
12 kx 2
Work, energy and nonconservative and external forces
KE f KE 0 + PE f PE 0 = W nonconservative + Wext
Power
P=
W ; P = Fv t
Example
A water slide is constructed