27. Which of the following is NOT one of the basic financial statements for the federal governmentat-large?
Statement of operations and changes in net position.
Statement of net cost
Statement of custodial assets.
28. Which of t
6 U ( b b2 ) x
b 2 ( b1 + b2 )
( 6 )( 0.0626 )(1.5)( 0.0125)(112.5)
( 0.0375) ( 0.1x103 )
= 5634x103 Pa = 5.634 MPa
Be careful of the units !
b ( b + 2b2 ) b L 5b + b
L 1 1
( b1 b2 ) b2 2 b1 b2
9. Velocity profile:
= where n > 0
Boundary layer displacement thickness * = 1
= 1 dy = y 1
(n + 1) n + 1
Boundary layer momentum thickn
From the von Karman integral equation:
d U 2 d
0 = U
U 2 d
0 d = 0 U dx 2 = U x
x 12 x
where: Re x =
Drag per unit width:
D = 0 dx =
Fully developed velocity profile in the annulus of concentric cylinders:
where R1 = radius of cylindrical cooling channel, and
R2 = radius of fuel element (solid and co-axial with the cooling channel)
From the simplified equ
7. The Government Accountability Office (GAO) is part of which branch of the federal government
None of the above; it is independent of any other branch of government.
8. Which of the foll
ESSAYS (CHAPTER 16)
1. Why is the FASAB named an advisory board? What happens if the GAO, Treasury, or OMB rejects
one of its standards?
2. One of the major problems encountered by FASAB in setting standards for financial
statements for the federal govern
14. Federal government capital expenditures can be accounted for in which of the federal funds?
All of the above.
15. Which of the following types of expenditures are not accounted for in the federal go
3. An operational objective should be a statement of aspirations.
4. An operational objective should be accomplishable by an unspecified future date.
7. An accounting program has determined that preparing students for careers in public accounting is
ANSWERS TO PROBLEMS (CHAPTER 13)
a. Accounts Receivable $1,000,000
Patient Service Revenue $1,000,000
b. Patient Service RevenueContractual Adjustments $ 20,000
Accounts Receivable-Allowance for Contractual Adjustments $ 20,000
c. Bad Debt Expen
ESSAYS (CHAPTER 13)
1. Austin Community College, a government institution, issues stand-alone financial
statements. Although the college maintains its accounts on a fund basis, it does not
include a combined fund balance sheet or statement of revenues and
ANSWERS TO MULTIPLE CHOICE (CHAPTER 13)
= 500 kN m
L = 150 mm
b1 = 0.075 mm
b2 = 0.025 mm
U = 1.5 m/s
Determine: i) of the lubricant
iii) Max. pressure pm
iv) Centre of pressure xcp
6 UL2 b1
ln 2 1 2
w ( b1 b2 ) b2
FIGURE A: Graph shows % saturation of
hemoglobin with oxygen under varying PCO2 &
FIGURE B: Effect of prior hypertension on mortality in
patients with MI (myocardial infarction) stratified by
year the study began.
RR < 1990 vs RR > 1990 has a p < 0.0
_ 355.lexp[—0.0342: : )
3'31 410342-120: 15+2’-3.1'
= 3 eXp[ _ ( I 3ﬂ=12081k2fm3
And the specific power is now
P40 IA 2%,01? = 0.5A'120811821883 = 335.3 Wa’m2
That's only a drop of [340.04—335.3]/340.04 = 1.4%. not a big deal. 37.8 The tabl
5.2 For the simple equivalent circuit of a 0.017 1113 photovoltaic cell shown below,
the reverse saturation current is I0 = 4 X 10'11 A and at an insolation of l-sun the
short-circuit current is [SC 2 6.4 A,. At 25°C, find the following:
5.6 Recreate the spreadsheet that was started in Example 5.4 for a 72-cell, 233-W
PV module for which the equivalent circuit of each cell has both series
[0.001(1) and parallel resistances [10.0.0].
a. From your spreadsheet, what is the current, voltage a
7.2 An anemometer mounted 10 In above a surface with crops, hedges and shrubs,
shows a Windspeed of 5 m/s. Assuming 15°C and 1 atm pressure, determine the
following for a Wind turbine with hub height 80 In and rotor diameter of 80 m:
7.11 Consider the design of a home-built wind turbine using a BSD-W permanent
magnet dc motor used as a generator. The. goal is to deliver 70 kWh in a 30—
a. What capacity factor would be needed for the machine?
Energy delivered (lemno) _ r0 _
5.11 An idealized 1-sun I—chrve for a single 80-W module is shown below. For
two such modules wired in series, draw the resulting I-V curve if the modules
are exposed to only 1/ 2 sun, and one cell, in one of the modules, is shaded.
Assume the shaded cell
kWhr’yr : Pdcﬂc x Overall Derate X (hfdaypeaksun) X 365 dfyr
1 kW X 5.56 hfday x 365dfvr
Temperature Derate : = O'Hgg = 0.93 3?
Default 0.7? 0.?7
which is a 1 - 0.9337 2 0.066 = 6.6% loss due to temperature.
Boulder Overall Derate : = 0.718 9
Integrating again gives: u = g sin + ghy sin + B
Applying the boundary condition 1:
u = sin hy
Flow rate per unit width Q is given by:
Q = udy
= sin hy dy
y 2 y3
= sin h
Q = sin .
Exam 1 MKT 383
Ch 1-4; Case 1; Class Discussions & Examples
Chapter 1 Sales Force Management
Changes in Customer Needs
1. Be personally accountable for our desired results
2. Understand our Business
3. Be on our side
4. Design the right applications