MatSE 489, Materials Selection for Sustainability, Fall 2016
Due on Tuesday, Oct. 11
Note: Your term paper outline is due today.
Reading: Ashby Ch. 9
Daily problems:
None, because the outline is due.
1. E8.7
Transportatio
Material Process
n
Use
106.56
12.4
4.32
1338.12
CO2 eco-audit
1600
1338.12
1400
1200
1000
kg
800
600
400
200
0
2. E8.12
106.56
Material
12.4
4.32
Process
Transportation
Use
Using
E1.2
Steel offers the greatest global energy saving and device-grade silicon offers the least.
E2.6 When we integral the dynamic production over time, we can get the total amount of resources
produced
1. E7.3
a) E = 23.5 MJ/kg * 4 kg * 0.33 = 31.02 MJ
CO2 = 2.35 kg/kg * 4 kg = 9.4 kg
b) E = (39 MJ/kg 85 MJ/kg) * 4kg = -184 MJ
CO2 = (2.3 kg/kg 2.35 kg/kg) * 4kg = -0.2 kg
We can only recover 31.02 MJ
1. E10.3
Steel frame (1 m2): 86 kg * (25 MJ/kg 6.6 MJ/kg) + 625 kg * 1 MJ/kg = 2.2074 GJ
Wood frame (1 m2): 80 kg * 8.8 MJ/kg = 0.704 GJ
The calculated result is similar to the table mentioned in the
MatSE 489, Materials Selection for Sustainability, Fall 2016
Due on Tuesday, Sept. 15
Reading: Ashby, Ch. 5
Daily problems:
E 5.6
E 5.7
Class discussion topic (think about this in advance but no writt
1. E4.11
R electric
=
C
si f i
0.50.95
=
=0.2244
rc
exp ( 0.0515)
exp (
t )
100 i
R hard disc
=
C
si f i
0.150.95
=
=0.1227
rc
exp ( 0.053)
exp (
t )
100 i
2.
For BMW:
embodied energy = 8.5e6 kcal
Eol
1. As mentioned in the book, Metals are usually classed as critical if (because) they are
geologically scarce, subject to potential supply constraints, costly, and needed for an
economically important
MatSE 489, Materials Selection for Sustainability, Fall 2015
Due on Tuesday, Nov. 15
Reading: Ashby Ch. 12
Daily problems:
E 12.8
E 12.11
E 12.19
E 12.20
Due on Thursday, Nov. 17
Reading: Ashby Ch. 13
1. E6.21
Sea-freight: CO2 = 0.015 kg/(t*km) * 24000 km * 1.2 t = 432 kg
Air-freight: CO2 = 0.45 kg/(t*km) * 24000 km * 1.2 t = 12960 kg
Although using air-freight may have some benefits, but it would