Physics 192 Solutions to Mastering Physics Week 8
P20.11. Prepare: We need to solve Coulombs law (Equation 20.1) for r :
F= K
| q1| q2 |
r2
where F = 8 .2 10 4 N and q1 = 5 . 0 nC, q2 = 12 nC, and K = 9 . 0 109 N m 2 /C 2.
Solve:
| q | q |
r2 = K 1 2
F
r=
Physics192SolutionstoMasteringPhysicsWeek1
P9.3.
Prepare: From Equations 9.5, 9.2, and 9.8, Newtons second law can be profitably rewritten as
p
Favg
t
In fact, this is much closer to what Newton actually wrote than F ma.
Solve: This allows us to find the
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Binaural Hearing and Source Localization
Below f = 1000 Hz l is large and
sound waves diffract around the
head. Sound levels at the two
ears are comparable, but time (or
phase) differences can be sensed.
Above f = 4000 Hz the
wavelength l is small and a
s
The Musical Staff: Musicians Graph Paper
PHYS 192: Logarithm and Blues
Assignment #3: Due Friday October 18, 2013
Name: _
Stud. #: _
Music is written on staves that are similar to the semi-logarithmic graph paper used by physicists and
mathematicians. The
Physics 192: Logarithm & Blues (1137)
MWF 11:30-12:20 in AQ3150
Instructors
Dr. Mike Hayden
Office: P8441
Phone: (778) 782-4845
Textbook
`Musical Acoustics by Donald E Hall
Opt I Opt II Opt III
Midterm exam I (Wed Oct 2)
10%
6%
Midterm exam II (Fri Nov 8)
Is the Dorian Mode unique?
The notes of the Pythagorean Scale that weve been discussing
were created by alternately multiplying and dividing string lengths
by 3/2, resulting in the Dorian Mode. Why multiply and divide?
Why not just multiply? Or divide?
e.
Pythagorean Intervals
(Dorian mode)
Larger interval: 9/8 = 1.125 (tone)
Smaller interval: 256/243 = 1.0535
(semitone)
Arrangement of intervals
T s T T T s T
x 9/8
1.000
x 9/8
1.125
1.185
x 256/243
x 9/8
1.333
x 9/8
1.500
x 9/8
1.688
1.778
x 256/243
2.000
Physics192SolutionstoMasteringPhysicsWeek2
P9.15. Prepare: This is a problem with no external forces so we can use the law of conservation of momentum.
Solve: The total momentum before the bullet hits the block equals the total momentum after the bullet p
Physics192SolutionstoMasteringPhysicsAssignmentWeek5
P15.37. Solve: (a) If a source of spherical waves radiates uniformly in all directions, the ratio of the intensities at
distances r1 and r2 is
2
2m
I1 r 2
I
3
3
3
3
2
2
2
2 50 m
1.6 10 I 50 m I 2
Physics 192 Solutions to Mastering Physics Week 10
P22.24. Prepare: Resistance, current, and electric potential difference are related by Ohms law R = V / I . Resistance,
resistivity, length, and cross-sectional area are related by R = L / A.
Solve: Combi
Physics 192
Practice Final Exam
1. Find the impulse and the average force for applied forces and the time intervals
below:
a)
b)
Force vs. time
Force vs. time
120
Fi
(N)
120
80
Fi
(N)
40
200
400
t (ms)
600
800
80
40
200
400
600
t (ms)
2. A driver is sitti
Physics 192 Practice Multiple Choice Questions for Final Exam 2013
Name_
TRUE/FALSE. Write 'T' if the statement is true and 'F' if the statement is false.
1) A rubber ball moving horizontally at 8.50 m/s hits a brick wall and bounces back with exactly the
Physics 192 Solutions to Mastering Physics Week 9
P21.6. Prepare: Mechanical energy is conserved. The potential energy is determined by the electric potential and is
given by U = qV. The figure shows a before-and-after pictorial representation of an elect
Physics 192 Solutions to Mastering Physics Week 7 Assignment
P12.32. Prepare: The heat needed to change an objects temperature by T is Q = McT. The mass of the ice cube is
0.200 kg and its specific heat from Table 12.4 is cice = 2090 J/(kg K).
Solve:
Q =
Physics 192 Solutions to Mastering Physics Week 6
P16.29. Prepare: Interference occurs as a result of the path difference between the path lengths of the sound from the
two speakers. A separation of 20 cm between the speakers leads to maximum intensity on
Physics192SolutionstoMasteringPhysicsWeek4Assignment
P15.1. Prepare: The wave is a traveling wave on a stretched string. We will use Equation 15.2 to find the wave speed.
Solve: The wave speed on a stretched string with linear density is vstring TS / . Th
Physics192SolutionstoMasteringPhysicsWeek3Assignment
Q14.23. Reason: This is simple harmonic motion where the equilibrium position is at x 0.
(a) One can read the period off the graph by seeing how much time elapses from peak to peak or trough to trough.
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