14-113) 1
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MME2213b
Page | 1
Engineering Dynamics
Solutions #7
Due: March 30, 2012
Locker #79, 5 pm
All questions are taken from the textbook:
Vector Mechanics for Engineers (Dynamics), 3rd SI metric edition, Beer FP and Johnston ER
Complete all parts of all the que
MME2213b
Page | 1
Engineering Dynamics
Assignment #8
Due: April 13, 2012
Locker #79, 5 pm
All questions are taken from the textbook:
Vector Mechanics for Engineers (Dynamics), 3rd SI metric edition, Beer FP and Johnston ER
Complete all parts of all the qu
MME2213b
Page | 1
Engineering Dynamics
Solutions #2
Due: Feb. 3, 2012
Locker #79, 5 pm
All questions are taken from the textbook:
Vector Mechanics for Engineers (Dynamics), 3rd SI metric edition, Beer FP and Johnston ER
Complete all parts of all the quest
MME2213b
Page | 1
Engineering Dynamics
Solutions #5
Due: March 9, 2012
Locker #79, 5 pm
All questions are taken from the textbook:
Vector Mechanics for Engineers (Dynamics), 3rd SI metric edition, Beer FP and Johnston ER
Complete all parts of all the ques
MME2213b
Page | 1
Engineering Dynamics
Assignment #3
Due: Feb. 10, 2012
Locker #79, 5 pm
All questions are taken from the textbook:
Vector Mechanics for Engineers (Dynamics), 3rd SI metric edition, Beer FP and Johnston ER
Complete all parts of all the que
MME2213b
Page | 1
Engineering Dynamics
Solutions #1
Due: Jan. 27, 2012
Locker #79, 5 pm
All questions are taken from the textbook:
Vector Mechanics for Engineers (Dynamics), 3rd SI metric edition, Beer FP and Johnston ER
Complete all parts of all the ques
MME2213b
Page | 1
Engineering Dynamics
Solutions #6
Due: March 23, 2012
Locker #79, 5 pm
All questions are taken from the textbook:
Vector Mechanics for Engineers (Dynamics), 3rd SI metric edition, Beer FP and Johnston ER
Complete all parts of all the que
11.28
For
, cfw_a is acceleration (m/s2) and v is velocity(m/s) of point A, and
following Initial conditions cfw_x(t=0) =1.5 m; v(t=0)=0 m/s; Find the position of block A.
i) xA=?
When v= -0.6 (m/s)
ii) xA=?
When t= 0.3 (s)
Solution:
1) Definition of the
MME2213b
Page | 1
Engineering Dynamics
Solutions #4
Due: Feb. 17, 2012
Locker #79, 5 pm
All questions are taken from the textbook:
Vector Mechanics for Engineers (Dynamics), 3rd SI metric edition, Beer FP and Johnston ER
Complete all parts of all the ques
ES 1036 Programming Fundamentals
A rrays
Dr. Quazi M. Rahman, Ph.D, P.Eng., SMIEEE
Office Location: TEB 361
Email: QRAHMAN@eng.uwo.ca
Phone: 519-661-2111 x81399
There are no secrets to success.
It is the result of preparation,
hard w ork, and learning fro
ES 1036 Programming Fundamentals
Class and O bject
Dr. Quazi M. Rahman, PhD, PEng, SMIEEE
Office Location: TEB 361
Email: QRAHMAN@eng.uwo.ca
Phone: 519-661-2111 x81399
There are no secrets to success.
It is the result of preparation,
hard w ork, and learn
ES 1036 Programming F d
P
i Fundamentals
t l
An Introduction to Pointers
Dr. Quazi M. Rahman, P.Eng., SMIEEE
Office Location: TEB 361
Email: QRAHMAN@eng.uwo.ca
Phone: 519-661-2111 x81399
There are no secrets to success.
It is the result of preparation,
ha
ES 1036 Programming Fundamentals
Class and Object
Dr. Quazi M. Rahman, PhD, PEng, SMIEEE
Office Location: TEB 361
Email: QRAHMAN@eng.uwo.ca
Phone: 519-661-2111 x81399
There
Th are no secrets to success.
t t
It is the result of preparation,
hard work, and
ES 1036 Programming Fundamentals
C+ Control Structures
There are no secrets to success.
It is the result of preparation,
hard w ork, and learning from
failure
~Colin Pow ell
Dr. Quazi M. Rahman, Ph.D, P.Eng., SMIEEE,
Office Location: TEB 361
Email: QRAHMA
ES 1036 Programming Fundamentals
U nit 5: M odular Program m ing w ith Functions
Dr. Quazi M. Rahman, Ph.D, P.Eng., SMIEEE
Office Location: TEB 361
Email: QRAHMAN@eng.uwo.ca
Phone: 519-661-2111 x81399
There are no secrets to success.
It is the result of p
ES1036: Programming Fundamentals
U nit 3: C+ B asics
Dr. Quazi M. Rahman, Ph.D, P.Eng., SMIEEE
Office Location: TEB 361
Email: QRAHMAN@eng.uwo.ca
Phone: 519-661-2111 x81399
There are no secrets to success.
It is the result of preparation,
hard w ork, and
ES1036A: Programming Fundamentals for Engineers FALL 2014
Lab 00: C+ with Visual Studio (For PC users)
Faculty of Engineering, Western University Canada
This guide will help you to get started with Visual Studio 2013 integrated development environment
(ID
ES1036a: Programming Fundamentals for Engineers FALL 2014
Lab 00: C+ with Xcode (For Mac Users)
Faculty of Engineering, Western University Canada
This guide will help you to get started with Xcode integrated development environment (IDE) for C+
programmin
ES1036: Programming Fundamentals
Unit 3: C+ Basics
Dr. Quazi M. Rahman, Ph.D, P.Eng., SMIEEE
Office Location: TEB 361
Email: QRAHMAN@eng.uwo.ca
Phone: 519-661-2111 x81399
There are no secrets to success.
It is the result of preparation,
hard work, and lea
Section 10.2
Representation of Systems in MATLAB
535
1.5
1
0.5
2
0
1.5
0
0.05
1
0.5
0.1
0
Time (s)
2
(kg m )
Load inertia J
Figure 10.5
load
Response of the closed-loop servomotor to a step command in posi- tion as a function of load
inertia.
Upon executi
Section 10.2
Representation of Systems in MATLAB
533
C=
1
0
0
D=
0
MATLAB provides functions that take system objects such as MotorSS as
an argument. Suppose that we wish to examine the behavior of the motor when it
is connected in a simple feedback confi
536
Chapter 10
Control Systems
where
N(s) = kt
(10.5)
D(s) = JLs3 + (JR + bL)s2 + (bR + ktkb)s + 0
MATLAB represents these polynomials as vectors containing the polynomial coefficients, from highest
power
to the constant. In the case of the servomotor, th
534
Chapter 10
Control Systems
Example 10.2 Step response of a servomotor
We shall determine the response of the servomotor shown in Figure 10.1, connected
with unity feedback as shown in Figure 10.3, to a step input. The script is
[y, t] = step(feedback(
Section 10.2
Representation of Systems in MATLAB
537
in the command window, the following is displayed:
Transfer function:
15
0.00015 s^3 + 0.15 s^2 + 1.925 s
The coefficients of the numerator and denominator polynomials, Num and Den, are the essential da
538
Chapter 10
Control Systems
which are the closed-loop poles of the simple unity feedback control system. The function tzero returns
the transmission zeros of a plant. Thus, the execution of
z = tzero(feedback(MotorTF, 1)
returns z as an empty matrix; t
Section 10.2
Representation of Systems in MATLAB
539
each other, an embedded computer will only observe the angle and change the voltage v(t) at fixed times. To
design a controller for an embedded computer, it is helpful to have a set of tools for studyin