Final 2009: Question 5
The gate ABCD retains water as shown. The gate is 6m wide (perpendicular to the page). The gate is supported by a pin at A and a roller at D. Neglecting the weight of the gate, determine the reactions at A and D.
Step 1: FBD of the

Final 2009: Question 3
The steel truss below is supported by a pin at A and a roller at B. For the given truss determine: (a) the force in member DK, JK, and EF. (members HJ and JK are in the same direction, i.e. HJK is a straight line) (b) Assuming the

STATICS PRACTICE PROBLEMS 1. All joints in the truss shown connect pinned axial members. Determine the force in member BD.
;
Take the moments about point C.
M C ( 400 N )( 3 m ) ( 6 m ) RAv + ( 600 N )( 4 m ) = 0
;
(A) 250 N (Compression) (B) 250 N (Tens

Final 2009: Question 1
The horizontal homogeneous platform ABCED of uniform thickness, weights 1500 kN. The platform is supported by the cable CF, a ball and socket at A, and a connection at B that provides support in the x and y direction only, determin

Belt Friction Let's look at a flat belt passing over a drum
P d P
1
P' P
2
O
T
1
Let's take a look at a differential element
y
s dN d /2 T dN d r d /2 T+dT x
Motion is assumed to be impending. dF = s dN The normal force is a differential force because

CIV100 Mechanics
Module 5: Internal Forces and Design
by: Jinyue Zhang
Module Objective
By the end of this Module you should be able to:
Find internal forces of any structural members Understand how Shear Force Diagrams (SFD) and Bending Moment Diagrams

CIV100 Mechanics
Module 4: Centroid and Moments of Inertia
by: Jinyue Zhang
Module Objective
By the end of this Module you should be able to:
Understand the underlying concept of centroids Understand how moments relate to the concept of centroid Know ho

CIV100 Mechanics
Module 3: Structural Analysis
by: Jinyue Zhang
Module Objective
By the end of this Module you should be able to:
Understand what a truss is Know how to find internal forces in a truss
using the method of joints using the method of sect

9 Stresses: Beams in Bending
The organization of this chapter mimics that of the last chapter on torsion of cir cular shafts but the story about stresses in beams is longer, covers more territory, and is a bit more complex. In torsion of a circular shaft,

2 Static Equilibrium Force and Moment
2.1
Concept of Force
Equilibrium of a Particle You are standing in an elevator, ascending at a constant velocity, what is t he resultant force acting on you as a particle? T he correct response is zero: For a particle

CIV100: Mechanics
Lecture Notes
Module 1: Force & Moment in 2D
By: Tamer El-Diraby, PhD, PEng. Associate Prof. & Director, I2C University of Toronto
Acknowledgment: Hesham Osman, PhD and Jinyue Zhang, MASc., contributed to this module
You Know What to Do!

5.4 Two and Three Force Members The solution to some problems can be made easier if you recognize members that are subjected to only 2 forces. Two force members - only 2 forces applied at 2 points on the member. - no moments. - line of action of both forc

Addition of a System of Coplanar Forces Vector Notation In many problems it will be necessary to resolve a force into 2 components that are perpendicular to each other. y j i x
O 2 vectors, i and that have the direction shown and magnitude 1 - unit j vect

Strength of Materials
Prof. M. S. Sivakumar
Problem 1: Computation of Reactions Problem 2: Computation of Reactions Problem 3: Computation of Reactions Problem 4: Computation of forces and moments Problem 5: Bending Moment and Shear force Problem 6: Bendi

Prep101
Civ 100 Equation Sheet
Equilibrium Particle Fx = 0, Fy = 0, Fz = 0 Rigid Body-Two Dimensions Fx = 0, Fy = 0, M0 = 0 Rigid Body-Three Dimensions Fx = 0, Fy = 0, Fz = 0 Mx = 0, My = 0, Mz = 0
Moments
Moment of a Force Mo = Fd
i M O = r F = rx Fx j r