Kinetics of Particles: Force-Mass-Acceleration method
Rectilinear Motion
Motion of a particle along a straight line
For motion along x-direction, accelerations along y- and z-direction will be zero
Fx = max
Fy = 0
Fz = 0
For a general case:
Fx = max
Fy

Indian Institute of Technology Guwahati
ME 101: Engineering Mechanics (2014-2015, Sem II)
Mid-Semester Examination
Time: 2 hours
It is a closed-book and closed-note examination
Mention clearly the free-body diagram and sign convention wherever applicabl

Plane Kinetics of Rigid Bodies
: Relates external forces acting on a body with the translational and
rotational motions of the body
: Discussion restricted to motion in a single plane (for this course)
Body treated as a thin slab whose motion is confined

W
(4)
N2
F2
N1
G
P
= 15o
F1
F3
N3
F2
N2
Consider a situation where the pipe and the wedge are in static equilibrium. Both of them have to satisfy
equations of equlibrium given next.
N1 N2 sin F2 cos = 0
F1 W + N2 cos F2 sin = 0
R(F1 F2 ) = 0
F3 + N2 sin

INDIAN INSTITUTE OF TECHNOLOGY - GUWAHATI
ME 101 : Engineering Mechanics
2014-2015, IInd semester
Quiz - 2 (25.03.2015)
Total Marks: 45
Question 1 Two automobiles A and B, Fig. (1), are approaching each other in adjacent highway
lanes. At t = 0, A and B a

Answers of Tutorial 1
ME101 (Engineering Mechanics) 2014-2015 Sem II
Vectors and Force Resultants
Ans 1.
The two set of forces form 2 couples as they are equal in magnitude and opposite in direction.
Hence, the resultant force = 0 ,
Each of the couple so

Tutorial 9
ME101 (Engineering Mechanics) 2014-2015 Sem II
Time: 8:00- 8:55 am
Note: Each question carries 10 Marks
Ans. 1. Looking at d and as polar coordinates with = 0
= = ,
= = 0
= + =
= + 2 = 0,
= 2 = 2
From geometry, at = 60, =
120
=
30
180120

3D Kinetics of Rigid Bodies
Angular Momentum
HG [ ( )] dm
Expression for H:
Inertia Matrix
HO [ r ( r)] dm
Components of H:
Principal axes of inertia
Kinetic Energy
ME101 - Division III
Kaustubh Dasgupta
1
3-D Kinetics of Rigid Bodies
General Momentum Equ

INDIAN INSTITUTE OF TECHNOLOGY - GUWAHATI
ME 101 : Engineering Mechanics
2014-2015, IInd semester
Tutorial - 12 (22.04.2015)
Total Marks: 50
Question 1 The 7.5-kg rod BC, see Fig. (1), connects a disk centered at A to crank CD. Knowing that the disk is ma

A ball is thrown at an inclined wall. Just before the impact on the wall, the ball has a
height of 1.2 m and a velocity v 0 that is horizontal with a magnitude of 15 m/s. The
coefficient of restitution between the ball and the wall is 0.9 and there is no

ME101: Engineering Mechanics
IIT Guwahati
1
Solutions to tutorial 6
18th of February, 2015
Problem 1
10 points
Consider the semicircular area and X-Y coordinate axes shown in figure (1). FromR basic definitions
and integration,
find (i) the coordinates of

Indian Institute of Technology Guwahati
ME 101: Engineering Mechanics (2014-2015, Sem II)
Answers of Quiz 1
P
Ans 1.
A
B
F
C
G
D
E
H
The FBD for the given frame is drawn by showing the forces on each of the members.
Member AC
Member AF
Ay
Ax = 0
Ax = 0
A

PLANE KINETICS OF RIGID BODIES
by Dr. Abhijit Chaudhuri
Dept. of Applied Mechanics
IIT Madras, Chennai, India
Analyze the response or motion of rigid body due to the
changes in forces acting on it.
Analysis is based

Engineering Mechanics
AM1100
Tutorial (Dynamics) 2
1. The homogeneous rectangular plate has a mass of 20 kg and
is supported in the vertical plane by the light parallel links
shown. If a couple M = 100 N.m is applied to the end link
AB with the syst

Solution 1:
Drawing the free body diagram of the entire beam we get that there are three unknown
reactions at A and one unknown reaction at B.
MA
HA
15 kN/m
VC
A
Segment AC
C
HC HC
VC
C
Segment CB
B
RB
RA
x
x
For solving, the entire beam is divided into t

Answers of Tutorial 4
ME101 (Engineering Mechanics) 2014-2015 Sem II
Problem-1
Solution: We shall start by drawing the FBD for the BEAM:
2 kN/m
1.5 kN
1.5 kN
Y
X
(4+3) kN-m
RB
RA
Finding Reaction Forces RA and RB:Equation for Half-Sine wave: = 2 sin [
(+1

Indian Institute of Technology Guwahati
ME 101: Engineering Mechanics (2014-2015, Sem II)
Answers of Mid-Semester Examination
Ans 1.
To determine the force in members DG and FI of the truss, a section a-a is passed through members DG,
DE, EF and FI as sho

Indian Institute of Technology Guwahati
ME101 Engineering Mechanics (2014-2015, Sem II)
End-Semester Examination
Time: 3 hours
Full marks: 160
It is a closed-book and closed-note examination
Mention clearly the free-body diagram and sign convention wher

3-D Kinetics of Rigid Bodies
Angular Momentum
Generalized Newtons second law for the motion for a 3-D mass system
Moment eqn for 3-D motion will be different than that obtained for plane
motion
Consider a rigid body in general motion in space
: x-y-z ar

Tutorial 11
ME101: Engineering Mechanics
Note: This is an open book and open notes exercise. While students can consult tutors
and TAs, consultaion among students during tutorials is discouraged.
1) Link OA has a constant counter-clokwise angular velocity

3-D Dynamics of Rigid Bodies
Introduction of third dimension
: Third component of vectors representing force, linear velocity, linear
acceleration, and linear momentum
: Two additional components for vectors representing angular quantities:
moments of for

3-D Kinematics of Rigid Bodies
Rotation about a Fixed Point
Instantaneous Axis of Rotation
: Rotation of solid rotor with black particles
embedded on its surface
: 1 and 2 are steady angular velocities
: Along line O-n, velocity of particles will be
momen

AM 110 Engineering Mechanics
Tutorial 2 - Equilibrium of structural systems
Date: 19th August 2011
Due: 19th August 2011
NOTE : You must submit the * marked questions soon after the tutorial session.
1. Draw the free body diagram for the truss system show

AM 110 Engineering Mechanics
Tutorial 3 - Equilibrium of structural systems : Beams
Date: 26th August 2011
Due: 26th August 2011
NOTE : You must submit the * marked questions soon after the tutorial session.
1.Draw the shear force diagram and bending mome