PLANE KINETICS OF RIGID BODIES
by Dr. Abhijit Chaudhuri
Dept. of Applied Mechanics
IIT Madras, Chennai, India
Analyze the response or motion of rigid body due to the
changes in forces acting on it.
Analysis is based
Engineering Mechanics
AM1100
Tutorial (Dynamics) 2
1. The homogeneous rectangular plate has a mass of 20 kg and
is supported in the vertical plane by the light parallel links
shown. If a couple M = 100 N.m is applied to the end link
AB with the syst
Scanned by CamScanner
Scanned by CamScanner
Scanned by CamScanner
Scanned by CamScanner
Scanned by CamScanner
Scanned by CamScanner
Scanned by CamScanner
AM 1101 July-Nov 2016: Tutorial Quiz practice sheet: Equilibrium of rigid bodies (CRC 203)
Date: 17.08.2016 (4.45-5.35pm)
1. If the resultant force of the two tugboats is required
to be directed towards positive x axis, and is FB to be
a minimum, determin
AM1101 - ENGINEERING MECHANICS - ASSIGNMENT 8 Vibration
1. A 90 kg man stands at the end of a diving
board and causes a vertical oscillation which is
observed to have a period of 0.6 s. What is the
static deflection st at the end of the board?
(neglect th
Solution 1:
Drawing the free body diagram of the entire beam we get that there are three unknown
reactions at A and one unknown reaction at B.
MA
HA
15 kN/m
VC
A
Segment AC
C
HC HC
VC
C
Segment CB
B
RB
RA
x
x
For solving, the entire beam is divided into t
Answers of Tutorial 4
ME101 (Engineering Mechanics) 2014-2015 Sem II
Problem-1
Solution: We shall start by drawing the FBD for the BEAM:
2 kN/m
1.5 kN
1.5 kN
Y
X
(4+3) kN-m
RB
RA
Finding Reaction Forces RA and RB:Equation for Half-Sine wave: = 2 sin [
(+1
Indian Institute of Technology Guwahati
ME 101: Engineering Mechanics (2014-2015, Sem II)
Answers of Mid-Semester Examination
Ans 1.
To determine the force in members DG and FI of the truss, a section a-a is passed through members DG,
DE, EF and FI as sho
Indian Institute of Technology Guwahati
ME101 Engineering Mechanics (2014-2015, Sem II)
End-Semester Examination
Time: 3 hours
Full marks: 160
It is a closed-book and closed-note examination
Mention clearly the free-body diagram and sign convention wher
3-D Kinetics of Rigid Bodies
Angular Momentum
Generalized Newtons second law for the motion for a 3-D mass system
Moment eqn for 3-D motion will be different than that obtained for plane
motion
Consider a rigid body in general motion in space
: x-y-z ar
Indian Institute of Technology Guwahati
ME 101: Engineering Mechanics (2014-2015, Sem II)
Answers of Quiz 1
P
Ans 1.
A
B
F
C
G
D
E
H
The FBD for the given frame is drawn by showing the forces on each of the members.
Member AC
Member AF
Ay
Ax = 0
Ax = 0
A
ME101: Engineering Mechanics
IIT Guwahati
1
Solutions to tutorial 6
18th of February, 2015
Problem 1
10 points
Consider the semicircular area and X-Y coordinate axes shown in figure (1). FromR basic definitions
and integration,
find (i) the coordinates of
Kinetics of Particles: Force-Mass-Acceleration method
Rectilinear Motion
Motion of a particle along a straight line
For motion along x-direction, accelerations along y- and z-direction will be zero
Fx = max
Fy = 0
Fz = 0
For a general case:
Fx = max
Fy
Indian Institute of Technology Guwahati
ME 101: Engineering Mechanics (2014-2015, Sem II)
Mid-Semester Examination
Time: 2 hours
It is a closed-book and closed-note examination
Mention clearly the free-body diagram and sign convention wherever applicabl
Plane Kinetics of Rigid Bodies
: Relates external forces acting on a body with the translational and
rotational motions of the body
: Discussion restricted to motion in a single plane (for this course)
Body treated as a thin slab whose motion is confined
W
(4)
N2
F2
N1
G
P
= 15o
F1
F3
N3
F2
N2
Consider a situation where the pipe and the wedge are in static equilibrium. Both of them have to satisfy
equations of equlibrium given next.
N1 N2 sin F2 cos = 0
F1 W + N2 cos F2 sin = 0
R(F1 F2 ) = 0
F3 + N2 sin
INDIAN INSTITUTE OF TECHNOLOGY - GUWAHATI
ME 101 : Engineering Mechanics
2014-2015, IInd semester
Quiz - 2 (25.03.2015)
Total Marks: 45
Question 1 Two automobiles A and B, Fig. (1), are approaching each other in adjacent highway
lanes. At t = 0, A and B a
Answers of Tutorial 1
ME101 (Engineering Mechanics) 2014-2015 Sem II
Vectors and Force Resultants
Ans 1.
The two set of forces form 2 couples as they are equal in magnitude and opposite in direction.
Hence, the resultant force = 0 ,
Each of the couple so
Tutorial 9
ME101 (Engineering Mechanics) 2014-2015 Sem II
Time: 8:00- 8:55 am
Note: Each question carries 10 Marks
Ans. 1. Looking at d and as polar coordinates with = 0
= = ,
= = 0
= + =
= + 2 = 0,
= 2 = 2
From geometry, at = 60, =
120
=
30
180120
3D Kinetics of Rigid Bodies
Angular Momentum
HG [ ( )] dm
Expression for H:
Inertia Matrix
HO [ r ( r)] dm
Components of H:
Principal axes of inertia
Kinetic Energy
ME101 - Division III
Kaustubh Dasgupta
1
3-D Kinetics of Rigid Bodies
General Momentum Equ
INDIAN INSTITUTE OF TECHNOLOGY - GUWAHATI
ME 101 : Engineering Mechanics
2014-2015, IInd semester
Tutorial - 12 (22.04.2015)
Total Marks: 50
Question 1 The 7.5-kg rod BC, see Fig. (1), connects a disk centered at A to crank CD. Knowing that the disk is ma