5.3.2
Total moles transferred per unit time, Equation 4.2.63.
W A = dLc Ao
4 D AB v max
L
c Ao is a molar density
dL is the surface area
So for our problem:
dL = 2RL = 2 3.14 1.4 13 = 114.296 cm 2
Given Chlorine and Water masses calculate molar density us
Assignment 2 Solutions
June 6, 2012
5.1.4
P = P0
2U0 bx + b2 x2 + y 2 + z 2
2
DP
P
=
+ v P
Dt
t
P
=0
t
DP
= v P = P,i vi
Dt
2U0 b + b2 2x
2
= b2 2y
2
2
= b 2z
2
P,1 =
P,2
P,3
v1 = 2.5x2 y + z
v2 = 0.5 3x2 2.5y 2 + 2z
v3 = 1 + z
1
2U0 b + b2 2x 2.5x2 y
Assignment 3 Solutions
June 12, 2012
5.2.4
Balance of moment of linear momentum:
D
Dt
(r g) dV
(r tn ) da +
(r v) dV =
V
S
V
Distribute the material derivative:
Dr
Dv
v + r
Dt
Dt
V
V
Dr
= v
Dt
vv = 0
D
dV = 0
Dt
r
V
Dv
Dt
+
D
(r v) dV
Dt
By Denition
Co
Quiz 2 Solutions
July 13, 2012
The setup of the problem was a bit vague. The way it should have been
framed was that gravity was in the z direction. In class, gravity was shown
to be in the y direction. As such there were two interpretations of how to
set
Quiz 1 Solutions
June 8, 2012
Question 1
a)
w=
(u v)
wi = eijk (eklm ul vm ),j = eijk eklm (ul,j vm + ul vm,j )
wi = (il jm im jl ) (ul,j vm + ul vm,j )
wi = ui,j vj + ui vj,j uj,j vi uj vi,j
b)
w=
(
v)
wi = eijk (eklm vm,l ),j = eijk eklm vm,lj
wi = (i