Bayesian Correction for Attenuation of Correlation in
Multi-Trial Spike Count Data
Sam Behseta, Tamara Berdyyeva, Carl R. Olson and Robert E. Kass
J Neurophysiol 101:2186-2193, 2009. First published 7 January 2009;
doi: 10.1152/jn.90727.2008
You might fin
\documentclass[11pt, oneside]cfw_article
% use "amsart" instead of "article"
for AMSLaTeX format
\usepackagecfw_amsmath,amssymb,amsfonts,amsbsy % Typical maths resource packages
\usepackagecfw_graphics
% Packages to allow inclusion of graphics
\usepackage
Math 535 Bio Stats
Rick Corp
Midterm 2
1. Explain LASSO
LASSO stands for Least Absolute Shrinkage and Selection Operator. It is a form of linear regression
that uses both shrinkage and variable selection methods in determining the best model. In general,
Math 535 Bio Stats
Rick Corp
Midterm 2
1. Explain LASSO
LASSO stands for Least Absolute Shrinkage and Selection Operator. It is a form of linear regression
that uses both shrinkage and variable selection methods in determining the best model. In general,
Report to Rick:
Grade: 95/100.
Overall: A very nice paper!
Problem 1:
1- Correlations: I wish you had constructed confidence intervals as opposed to merely
reporting the correlations. It's quite nice that you constructed one-sided two-sample t-tests, as
Math 535 Exam 2+1=Final
Richard L Corp IIII
July 3, 2013
1. Summarize Efrons Paper
Jackknife is a nonparametric method commonly used for inference, estimating bias, and variance of certain
statistics. The main goal of the paper is to present the strengths
Math 535 Summer 2013 Midterm #1 Rick Corp
A1.) From the skeletal measurements I choose to do a t-test and a correlation analysis on the elbow diameter (column 6)
and wrist diameter (column 7). For the girth data I choose waist (column 12) and hip (column
535 - HW #2 - Richard Corp
1.4 Normal Approximation of Poisson
pnorm(6-1/2),mean=3,sd=sqrt(3),lower.tail=F)
[1] 0.07445734 The answer with continuity correction is a slight underestimate.
1.5 Table for t-distr
MATH 535 HW 1 Rick Corp
1.1a.) Having at least one girl.
and Y=cfw_1,2,3,4
1.1b.) Having exactly 2 girls
1.1c.) P(Y=2|Y > 1) =
1.2a.) Let P(Y=1) = .49, then:
1.2b.) P(Y=2) =
1.2c.) P(Y=2|Y > 1) =
Math 535 HW #2
Problem 1
Code to sample 1000 points from an exponential distribution with mean 2
%
g <- function(n, meanx)cfw_(-meanx)*log(1-x)
x = runif(1000)
data <- g(x, 2)
hist(data, breaks = 20, prob = TRUE, main ="Exp Data Generated Using CDF Invers