Part 6 (Ch 6 & part of Ch?)
Energy Storage Elements: Energy storage elements are capacitor & inductor. They
store electric energy and release energy (without dissipation), so they act as circuit
elements with memory.
Capacitor: Separation of ch
BB 204 I Solution Set #1
#1.2) Q=It 9 t=4800/12=400 s
#14) w=ov 9o=1loo J/12 v=3.3ac. b) CH 9 l=8.33/5=1.67 A
111.5) Q=(1.5)(1.5x60)= 135 c
#13) v1= VBA=~VAE=—120/5=-24 v
#120) if follow the direction of I it moves from + to — so i—V is passive sign conve
Part 3 (ch 3)
N ODAL ANALYSIS:
0 Specify the reference node. .
o Specify all essential nodes; assign nodal voltage (voltage between node &
reference) & label.
- Assign current direction to all passive elements (don t label).
- Write KCL equations f
Part 5 (Chapter 5)
Sugergosition: This method may not be a shortcut method, but 1n phasor domain it is the
only technique to analyze ac circuits with different frequency sources.
Guideline: In this method, we assume one independent source is acting
Summary of Chapter 2
My connecting point or line, straight line represents a perfect conductor,
therefore several points on a straight line are considered as “one” node.
1. simple node: only “two” elements are connected 9
BB 204 HW#9
#1) An uncharged IOO—uF capacitor is charged by a constant current of 1 mA. Find the Voltage
across capacitor after 10 minutes.
#2) A capacitor has an accumulated charge of 600 uC with 5 V across it. What is the value of
#3) The v
E45 Find Vﬂ in térms of V1 and V2 in Fig. E45. If V1 = V1 = _4V, ﬁnd Va. If the op-amﬁ power ANSWER: , ,
\X supplies are $15 V'and V; = 2V, what is the allowable range of V1? V,J = —~2 V1 + 3 5 V21 *
" ' . _ 6V;_—4V5V1511V.
V1 mm mm . ' _ .
Complex Numbers Algebra
General form: Rectangular form Z=a+jb, Polar form Z=|
Z|/Z=r/ = rej
Complex domain is two dimensional domain (plane), with Re Z and Im Z
Conversion from rectangular to polar: Z=a+jB Z=|Z|/Z=
|Z|=r = a2 + b2, /Z = = ta