Homework 3 CHEM 112B, Winter 2013
TA: Thanh Do
Due on Jan 30, 2013
Grading scheme: 5 points per problem, 50 points total.
Problem 1. Dill 10.1 See the problem from Dill Chapter 10.
Solutions.
a.
X Ej /kB T 0/kB T 0 /kB T
q=
e
=e
+e
+ e2 0 /kB T = 1 + e
0
Homework 4 CHEM 112B, Winter 2013
TA: Thanh Do
Due on Feb 06, 2013
ADDITIONAL PROBLEMS:
Problem 1. Given
Q(N, V, T ) =
Let
1
N!
q=
3N/2
2mkb T
h2
3/2
2mkT
h2
V
So
Q(N, V, T ) =
We know that
E =
VN
qN
N!
ln Q
Note that this is equation 10.40 from Dill (Ch
Homework 5 CHEM 112B, Winter 2013
TA: Thanh Do
Due on Feb 20, 2013
Problem 1. Tinoco 6.5
(a) A plot of log x vs. t (see below) yields a straight line with a slope of 5.8 106 s1 .
(1.1)
S=
2.303 d log x
2.303
=
(5.8 106 s1 )
2
dt
2
So
2 1 min
= 2.579 103 s
Homework 6 CHEM 112B, Winter 2013
TA: Thanh Do
Due on Feb 27, 2013
Problem 1. Dill 33.2
1/2
We know that r2
= N b2 and from equation (33.9), we know that fpulling = felastic , thus
(1.1)
1/2
r
2
2 1/2
= (N b )
=
3kT x
f
1/2
3(1.38 1023 JK1 )(300 K)(20 1
Homework 7 CHEM 112B, Winter 2013
TA: Thanh Do
Due on March 6, 2013
Problem 1. Atkins Exercise 21.13(b)
Reaction:
A
Kf
Kr
B+C
Some notes about temperature jump experiments: You may be confused between Kr and Kf , and how
to generate the correct expression
Homework 8 CHEM 112B, Winter 2013
TA: Thanh Do
Due on March 13, 2013
Problem 1. Chang 12.29
Using the Arrhenius equation
k = A exp[Ea /kB T ] ln k = ln A Ea /kB T
So
(1.1)
ln k275.4
K
ln k272.1
K
k1
= ln
k2
We have
Ea
ln 2 =
8.314 J/(K.mol)
Ea
=
R
1
1
2
Homework 1 CHEM 112B, Winter 2013
TA: Thanh Do
Due on Jan 16, 2013
HW1 grading scheme:
KKW Problems (checked): 2 points each .
Additional Problems (graded): I (10 points), II (5 points), III (5 points), IV (a- 5 points, b- 5
points), V (10 points).
Max