PSTAT 120A
Homework 3
Spring 2016
Problem 1: DeAndre Jordan has a career free throw percentage of 41.7 percent. This is
really bad for a professional basketball player (its 10 percentage points lower than Shaqs).
His coaching staff decide that they could
PSTAT 120A
Homework 2
Spring 2016
Problem 1: Two students A and B are both registered for a certain class. Assume that
student A attends class 80 percent of the time and student B attends 60 percent of the time,
and the absences of the two students are in
PSTAT 120A
Homework 5
Spring 2016
Problem 1: Prove that if a continuous random variable has an exponential PDF with
parameter , then for every pair of positive real numbers s and t, Pr (X > s + t | X > s) =
Pr (X > t).
f (x) = ex , x > 0.
so
Pr (X > s + t
PSTAT 120A
Homework 4
Spring 2016
Problem 1: Consider the following probability density functions:
f1 (x) = a, for 0 < x < 1,
f2 (x) = cx(1 x), for 0 < x < 1,
f3 (x) = kx2 (1 x)2 , for 0 < x < 1.
Each of these densities are zero outside of the specified r
PSTAT 120A
Homework 1
Problem 1: Give the sample space
Spring 2016
for each of the following experiments:
(a) An election decides between two candidates A and B.
= cfw_Candidate A wins, Candidate B wins:
(b) A two sided coin is tossed.
= cfw_H; T
(c) A t
PSTAT 120A
Homework 3
Spring 2016
Problem 1: DeAndre Jordan has a career free throw percentage of 41.7 percent. This is
really bad for a professional basketball player (its 10 percentage points lower than Shaqs).
His coaching staff decide that they could
PSTAT 120A
Homework 2
Spring 2016
Problem 1: Two students A and B are both registered for a certain class. Assume that
student A attends class 80 percent of the time and student B attends 60 percent of the time,
and the absences of the two students are in
PSTAT 120A
Homework 6
Spring 2016
Problem 1: Suppose that in a group of 10 people, each person has a 0.1 probability of
having a certain disease, independently from person to person. Now consider a testing plan
where the group is split into two groups of
Wenjian Liu (Instructor)
PSTAT 120A Fall 2014
Solutions of Homework 3 Due Wednesday, Oct 29, 2014
Problem 3.1
What is the probability of rolling an even number with a single die, given the die roll is 3 or less?
Proof. Write A = cfw_the rolling number is
Wenjian Liu (Instructor)
PSTAT 120A Fall 2014
Solution of Homework 2
Due Monday, Oct 20, 2014
Problem 2.1
Before the early 1990s, a telephone area code in the US consisted of three digits, where the rst was
not 0 or 1, the second was 0 or 1, and the third
Math 251 Lab Activity Week 3
1) Match the following equations with the graphs shown below. (Assume 0 < a < b)
( x a )( x + a )
a
( x a )( x + a )
( x a )( x 2 + a )
a) y = x
b) y =
c) y =
d) y =
2
( x b
Abdulaziz Alghunaim
HW Page 95-98
Friday 22 Oct 2010
PART A
2) All of them are depressed and lonely.
3) Their families left them to struggle alone, if they had families.
PART B
4) They do have some money, but its limited.
5) Hes probably very close to bot
Chapter 2:
Different types of engineers:
- Manufacturing Engineering
What they do:
They are concerned with the design and operation of integrated systems for the
production of high-quality, economically competitive products. The Systems mat include
comput
Section 4 Random Variables
and Probability Distributions
Random Variables
Capital X denotes a random variable
Based on the distribution, there are different
probabilities for each value that X could take
on
Were familiar with the normal distribution
al
CHEM. 1BL LAB FINAL Saturday March 17, 4:00 6:00 PM Go to the room where your TA will
be, see Room Assignments below.
You must BRING:
1)
2)
3)
4)
Scantron Form (Available at the bookstore, ParScore form for General Chemistry)
Access Card (Picture ID), PER
CONSTANTS
CONVERSION FACTORS
R = 8.3145 J mol1K1
R = 0.08206 L atm mol1K1
NA = 6.023 x1023 atoms/mol
F = 96,485 C/mol
h = 6.626 x 1034 J s
c = 3 x 108 m/s
1 atm = 760 torr
1 A = 1 C/sec
1 V = 1 J/C
1 L atm = 101.3 J
EQUATIONS
E = E o (RT/n F) ln Q
E = E o
CONSTANTS
CONVERSION FACTORS
R = 8.3145 J mol1K1
R = 0.08206 L atm mol1K1
NA = 6.022 x1023 atoms/mol
F = 96,485 C / mol of electrons
C = 3 x 108 m/s
h = 6.626 x 1034 J s
1 atm = 760 torr
1 A = 1 C/sec
1 V = 1 J/C
1 L atm = 101.3 J
EQUATIONS
RT
E=Eo
zer