VISUAL
STORYTELLING
CULTURAL
THINKING
and
3
Creativity
Elizabeth Gilbert (1969- )
American writer, author of the book Eat, Pray, Love (2006)
video: Elizabeth Gilbert-Your elusive creative genius
http:/www.youtube.com/watch?v=86x-u-tz0MA (5:00)
Eat Pray Lo
VISUAL
STORYTELLING
CULTURAL
THINKING
and
7
The Beatles, 1963
She Loves You
https:/www.youtube.com/watch?v=QoF-7VMMihA
Aesthetics
Is this a good painting?
Branches of Philosophy
Epistemology: branch of philosophy that investigates the nature of human know
VISUAL
STORYTELLING
CULTURAL
THINKING
and
5
Narrative
We can be heroes
We can be heroes
We can be heroes just for one day
We can be heroes
David Bowie, Heroes, 2002 live performance in Paris https:/www.youtube.com/watch?v=pU9JAvZGaIg
written by David Bowi
VISUAL
STORYTELLING
CULTURAL
THINKING
and
4
The Worlds Most Expensive Paintings
https:/www.youtube.com/watch?v=ET5pvDI-TOY
Noam Chomsky, American linguist, philosopher, cognitive scientist, logician (1928 - )
On Being Truly Educated
https:/www.youtube.com
VISUAL
STORYTELLING
CULTURAL
THINKING
and
2
How to Pronounce Van Goghs Name
https:/www.youtube.com/watch?v=YLTQv8RH1TE
Frida Kahlo, Mexican painter (1907-1954)
video: Frida Kahlo - A Woman in Rebellion
https:/www.youtube.com/watch?v=wDi41YGqq5U (beginning
VISUAL
STORYTELLING
CULTURAL
THINKING
and
10
Mass Media: pop music, film and advertising
Elvis Aaron Presley (1935 1977) was an
American singer and actor. Regarded as one
of the most significant cultural icons of the 20th
century, he is often referred to
VISUAL
STORYTELLING
CULTURAL
THINKING
and
11
Mixing East and West Culture
John Lennon (1940-1980) and Yoko Ono (1933- )
Imagine, 1971 https:/www.youtube.com/watch?v=DVg2EJvvlF8
one of the most performed songs of the 20th Century; its lyrics encourage the
VISUAL
STORYTELLING
CULTURAL
THINKING
and
1
The Lost (2011)
by Reynold Reynolds
https:/vimeo.com/25250151
The Great Dictator, film, 1940
director and actor Charles Chaplin (1889-1977)
(music by Hans Zimmer added)
https:/www.youtube.com/watch?v=j34IrtLZrmY
VISUAL
STORYTELLING
CULTURAL
THINKING
and
8
Intro Video
Variety Artisans: The Seamless Look of Birdman
https:/www.youtube.com/watch?v=XxXWs74dKnE
Group Presentation (Exercise 6)
You can present the four sections in any order that will be effective, such a
VISUAL
STORYTELLING
CULTURAL
THINKING
and
9
Lady Gaga
Poker Face, 2009
Poker Face: ?
Lady Gaga
Poker Face, 2009
http:/www.youtube.com/watch?v=bESGLojNYSo
Poker Face:
1 . an expressionless face:
He can tell a funny story with a poker face.
2. a person who
CM10250 2011
Week 6 Solution to questions
011.12
a. The cost figure as the basis for depreciation :
$11,000 + $100 + $200 + $400 : $11,700
011.13
(600)
Workings
Depreciation
20X9 20% x ($1,000 + $1 ,600)= $520 (Lorry A $200, Lorry B $320)
20x0 20% x ($1,6
CM10250
Financial Accounting 2011
Week 3 Solution to Questions
Q3.2 refer text/notes
Q 4.2
Date
1 Mar
2 Mar
4 Mar
6 Mar
9 Mar
11 Mar
13 Mar
16 Mar
18 Mar
20 Mar
22 Mar
24 Mar
26 Mar
28 Mar
30 Mar
31 Mar
Dr
Lease
Office Equipment
Purchases
Postage
Purchase
CM10250 2011/12
Week 8 Solutions to questions
Q 10.3(a) & (b) Refer text P 102
Q10.4 Refer text P 102 to 104
Q10.16
Appropriate for Nesales and not for Cadberry.
Q 10.17
The $10 million spent on staff recruitment, training and development should be recogn
axis([0 L+1 0 N+1]);
hold on; % keeps the current graphics
for j = 1:L
plot(j*ones(1,N),1:N,o);
end
plot(1:L, Q,-); % Q is a vector whose components are the states
% at time l = 1, ., L
% Hence a solid line segment drawn from the previous node to the new
This equation is between two polynomials in the variable ejw . Setting the constant terms
2
2
equal, we get k 1 + p |ak |2 = W or
k=1
2
U =
2
W
1 + |ak |2
2
2
where U < W if any ak = 0, k = 1, . . . , p.
11.20. Set D(k) [n]
X[n] X (k+1) [n]. Then from the
24
(b) Mercers Theorem:
( ) =
X
() ()
=0
Hence, 0 () = 1 () = 1 cos 2 2 () = 2 cos 4
R
functions by 0 | ()|2 = 1 we get
=
r
1
1 =
r
Normalizing these orthogonal
2
= 2
Then, we can compute the lambdas as: 0 = 3 1 = and 2 = 2 These are the
variances of
estimate of correlation function
4
3
R[m]
2
1
0
1
2
0
50
100
m
150
200
Figure 1: Estimate of correlation function for N = 100.
r(1,1)=z(N+1);
r(2,1)=z(N+2);
r(3,1)=z(N+3);
r
pause(5);
a=inv(R)*r
disp(May compare a vector values to ar(3) coefficients.);
b1
11.11. (a) Since Y [N ] Y [N + 1] . . . Y [N ]. Using Theorem 11.1-4 property (b), we have
E X[n]|Y [N ], Y [N + 1], . . . , Y [N ] = E[X[n]|Y [N ]+E X[n]|Y [N + 1], . . . , Y [N ] .
By the same procedure
N
E X[n]|Y [N ], Y [N + 1], . . . , Y [N ] =
E[X[
(a) W [n] is the innovation sequence for X[n] because
W [n] is a white (uncorrelated) sequence.
It is dened as a causal invertible linear transformation on X[n].
(b) A simple substitution will show the result. From the defn. of X[n],
n
W [n] = X[n] +
k=
18
Then, if [ ] = [()] = a constant, and if
2 , [( )2 ] 0
then () is ergodic in the mean.
(b) Using the sucient condition, i.e.
Z +
( )
or
( )
Z +
in the case of zero mean, we have
Z +
2 | | cos(2 )
=
=
=
=
2 + 2
2
2
0
"
#
(+2 )
(+2 )
2
+ 2
27
Secondly, we are asked to show using Chebyshevs inequality that for such processes, we
actually have () = ( + ) (pr. 1). Now, by Chebyshev
[|( + ) ()|2 ]
2
0
= 2
= 0
for all 0
[|( + ) ()| ]
Then, dene the events
1
, |( + ) ()|
1
Now, consider the
Solutions to Chapter 11
11.1. For minimum variance, we want to minimize diagonal terms of
2
(Y Y )(Y Y )T ,
where Y = AX.
2 = (AX Y )(AX Y )T = AK1 AT + K2 AK12 K21 AT .
Now write A = A0 + ; is = 0 for minimum variance?
2 = (A0 + )K1 (A0 + )T + K2 (A0 + )
21
so we have
Z
+ 2
2
( )() () = () 2 )() ()
which means that both () and () have the same K-L orthonormal basis functions, i.e.
()
()
()
()
()
() = () and the eigenvalues of () are = 2 , or equivalently =
()
+ 2 We can then express the K-L expansion
9
So,
Z
2 (1 2 )
= ( )
() ( )
1 2
1 =2 =
Z
() ( ) + ( )
where
( ) =
Z
Z
(1 ) (2 ) (1 2 )1 2
as in part (a).
13. (a) We have that [] in the m.s. sense, and hence in probability and distribution.
Each [] is Gaussian distributed with mean and varianc
12
with appropriate regions of convergence for each of these terms. We nd
( + 2)
1
1
( + 2)
and =
=
=
=
( + 2)( + 2) =2 4
( + 2)( + 2) =+2 4
Now, for stability, the region of convergence (ROC) of the
1
4
1
4
+2
term is Re() 2, while
the ROC of the +2 ter
29
we can conclude that 0 is [20 20 + ] Then, since all the functions cos(20 +
20 ) are periodic with period 2 we can just as well integrate them over [ +] Thus
we have
#
"
#
"
\
\
cfw_cos(20 + 20 + ) 0 =
cfw_cos(20 + 0 ) 0
=1
=1
which is independent
6
Then
2
( )
2
!
2 ( )
( ) 2
= 4 ( )
+
2
( ) =
9. Let
1
0
() , [ ( + ) ()]
1
1
= ( + ) cos 20 ( + ) () cos 20
and then use the substitution cos 20 cos 2 0 sin 2 0 sin 20 for the rst cosine term,
to get
1
0
1
0
) cos 20 cos 2 ( + ) sin 2
sin 20
(